How can I increase the recurrence of a question in a quiz?

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I am developing a quiz based app on Swift and the questions repeat several times within a set time limit. If the user gets a specific question wrong I would like the app to increase the recurrence of this question.

Any help would be appreciated greatly!

Many thanks,

Jonny

edited 2 days ago

Ashley Mills

27.9k883110

asked 2 days ago

Jonny Taylor

New contributor

Could you show us your class, or any code you have written?
– J. Doe
2 days ago

Thanks for your reply. I have not yet started writing the code. I am a complete beginner in Swift and so I am just trying to get an idea of what is possible and any possible solutions to this problem. Many thanks!
– Jonny Taylor
yesterday

add a comment |

up vote
1
down vote

favorite

Any help would be appreciated greatly!

Many thanks,

Jonny

edited 2 days ago

Ashley Mills

27.9k883110

asked 2 days ago

Jonny Taylor

New contributor

Could you show us your class, or any code you have written?
– J. Doe
2 days ago

Thanks for your reply. I have not yet started writing the code. I am a complete beginner in Swift and so I am just trying to get an idea of what is possible and any possible solutions to this problem. Many thanks!
– Jonny Taylor
yesterday

add a comment |

up vote
1
down vote

favorite

Any help would be appreciated greatly!

Many thanks,

Jonny

edited 2 days ago

Ashley Mills

27.9k883110

asked 2 days ago

Jonny Taylor

New contributor

Any help would be appreciated greatly!

Many thanks,

Jonny

swift

edited 2 days ago

Ashley Mills

27.9k883110

asked 2 days ago

Jonny Taylor

New contributor

edited 2 days ago

Ashley Mills

27.9k883110

asked 2 days ago

Jonny Taylor

New contributor

edited 2 days ago

Ashley Mills

27.9k883110

edited 2 days ago

Ashley Mills

27.9k883110

edited 2 days ago

Ashley Mills

27.9k883110

asked 2 days ago

Jonny Taylor

New contributor

asked 2 days ago

Jonny Taylor

asked 2 days ago

Jonny Taylor

New contributor

Jonny Taylor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Could you show us your class, or any code you have written?
– J. Doe
2 days ago

Thanks for your reply. I have not yet started writing the code. I am a complete beginner in Swift and so I am just trying to get an idea of what is possible and any possible solutions to this problem. Many thanks!
– Jonny Taylor
yesterday

add a comment |

Could you show us your class, or any code you have written?
– J. Doe
2 days ago

Thanks for your reply. I have not yet started writing the code. I am a complete beginner in Swift and so I am just trying to get an idea of what is possible and any possible solutions to this problem. Many thanks!
– Jonny Taylor
yesterday

Could you show us your class, or any code you have written?
– J. Doe
2 days ago

Thanks for your reply. I have not yet started writing the code. I am a complete beginner in Swift and so I am just trying to get an idea of what is possible and any possible solutions to this problem. Many thanks!
– Jonny Taylor
yesterday

add a comment |

1 Answer
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Not really a Swift question - more about what approach to take to solve your problem. There are many ways to achieve this and which one is right for you will probably depend upon how precise you want to be with the probabilities of a particular question being asked and your own coding ability.

The simplest approach would probably be to have an array of questions and use array.randomElement() to choose a question randomly from that array. If the user gets the question wrong you add that question to the array again. That's definitely not the best approach but if you are having trouble with this yourself it may be the best for you.

answered 2 days ago

365SplendidSuns

2,00511221

This is the right approach, but if OP wants to increase the incorrect question's occurrence, he should not only re-add it to the list, but add it again so that its likelihood of being selected again increases by that much.
– NRitH
2 days ago

@NRitH that's why I said he should add the question to the array again...
– 365SplendidSuns
2 days ago

Thank you both for your replies. That method would definitely be a good starting point for me. @365SplendidSuns what approach would you take to solve this problem? (as you mentioned this is not the best approach). Also some additional detail: If the user “repeatedly" got a question wrong I would like to continue increasing the occurrence of that question until it is being asked every 3 questions. Equally once the user started getting the question correct I would like to reduce it back down until it has an equal chance of being selected again.
– Jonny Taylor
yesterday

@JonnyTaylor A lo depends on the context but I guess I would make a Question class holding the question text as a property along with the answer and methods for checking the answer etc. The class would have a variable holding a float between 0 and 1 indicating the weighting that question should have fro being chosen to be displayed. In my main code I would have an array of Question objects. Pick a question from the array at random then generate a random number between 0 and 1. If the number is < that question's weighting property you display the question if > you repeat with another question.
– 365SplendidSuns
20 hours ago

If the user gets the question wrong you increase the weighting up to a limit. Right you decrease it. Forcing it to be asked every 3 questions when at the limit will make things a bit more complex because on every third question you will have to use a different approach to choosing the question. It also means that if they keep getting a lot of questions wrong they will be stuck with the same three repeatedly until they get it right so personally I would avoid that unless it is a specification I have to work with.
– 365SplendidSuns
20 hours ago

|
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1 Answer
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answered 2 days ago

365SplendidSuns

2,00511221

This is the right approach, but if OP wants to increase the incorrect question's occurrence, he should not only re-add it to the list, but add it again so that its likelihood of being selected again increases by that much.
– NRitH
2 days ago

@NRitH that's why I said he should add the question to the array again...
– 365SplendidSuns
2 days ago

Thank you both for your replies. That method would definitely be a good starting point for me. @365SplendidSuns what approach would you take to solve this problem? (as you mentioned this is not the best approach). Also some additional detail: If the user “repeatedly" got a question wrong I would like to continue increasing the occurrence of that question until it is being asked every 3 questions. Equally once the user started getting the question correct I would like to reduce it back down until it has an equal chance of being selected again.
– Jonny Taylor
yesterday

@JonnyTaylor A lo depends on the context but I guess I would make a Question class holding the question text as a property along with the answer and methods for checking the answer etc. The class would have a variable holding a float between 0 and 1 indicating the weighting that question should have fro being chosen to be displayed. In my main code I would have an array of Question objects. Pick a question from the array at random then generate a random number between 0 and 1. If the number is < that question's weighting property you display the question if > you repeat with another question.
– 365SplendidSuns
20 hours ago

If the user gets the question wrong you increase the weighting up to a limit. Right you decrease it. Forcing it to be asked every 3 questions when at the limit will make things a bit more complex because on every third question you will have to use a different approach to choosing the question. It also means that if they keep getting a lot of questions wrong they will be stuck with the same three repeatedly until they get it right so personally I would avoid that unless it is a specification I have to work with.
– 365SplendidSuns
20 hours ago

|
show 2 more comments

up vote
0
down vote

answered 2 days ago

365SplendidSuns

2,00511221

This is the right approach, but if OP wants to increase the incorrect question's occurrence, he should not only re-add it to the list, but add it again so that its likelihood of being selected again increases by that much.
– NRitH
2 days ago

@NRitH that's why I said he should add the question to the array again...
– 365SplendidSuns
2 days ago

Thank you both for your replies. That method would definitely be a good starting point for me. @365SplendidSuns what approach would you take to solve this problem? (as you mentioned this is not the best approach). Also some additional detail: If the user “repeatedly" got a question wrong I would like to continue increasing the occurrence of that question until it is being asked every 3 questions. Equally once the user started getting the question correct I would like to reduce it back down until it has an equal chance of being selected again.
– Jonny Taylor
yesterday

@JonnyTaylor A lo depends on the context but I guess I would make a Question class holding the question text as a property along with the answer and methods for checking the answer etc. The class would have a variable holding a float between 0 and 1 indicating the weighting that question should have fro being chosen to be displayed. In my main code I would have an array of Question objects. Pick a question from the array at random then generate a random number between 0 and 1. If the number is < that question's weighting property you display the question if > you repeat with another question.
– 365SplendidSuns
20 hours ago

If the user gets the question wrong you increase the weighting up to a limit. Right you decrease it. Forcing it to be asked every 3 questions when at the limit will make things a bit more complex because on every third question you will have to use a different approach to choosing the question. It also means that if they keep getting a lot of questions wrong they will be stuck with the same three repeatedly until they get it right so personally I would avoid that unless it is a specification I have to work with.
– 365SplendidSuns
20 hours ago

|
show 2 more comments

up vote
0
down vote

answered 2 days ago

365SplendidSuns

2,00511221

answered 2 days ago

365SplendidSuns

2,00511221

answered 2 days ago

365SplendidSuns

2,00511221

answered 2 days ago

365SplendidSuns

2,00511221

answered 2 days ago

365SplendidSuns

2,00511221

This is the right approach, but if OP wants to increase the incorrect question's occurrence, he should not only re-add it to the list, but add it again so that its likelihood of being selected again increases by that much.
– NRitH
2 days ago

@NRitH that's why I said he should add the question to the array again...
– 365SplendidSuns
2 days ago

Thank you both for your replies. That method would definitely be a good starting point for me. @365SplendidSuns what approach would you take to solve this problem? (as you mentioned this is not the best approach). Also some additional detail: If the user “repeatedly" got a question wrong I would like to continue increasing the occurrence of that question until it is being asked every 3 questions. Equally once the user started getting the question correct I would like to reduce it back down until it has an equal chance of being selected again.
– Jonny Taylor
yesterday

@JonnyTaylor A lo depends on the context but I guess I would make a Question class holding the question text as a property along with the answer and methods for checking the answer etc. The class would have a variable holding a float between 0 and 1 indicating the weighting that question should have fro being chosen to be displayed. In my main code I would have an array of Question objects. Pick a question from the array at random then generate a random number between 0 and 1. If the number is < that question's weighting property you display the question if > you repeat with another question.
– 365SplendidSuns
20 hours ago

If the user gets the question wrong you increase the weighting up to a limit. Right you decrease it. Forcing it to be asked every 3 questions when at the limit will make things a bit more complex because on every third question you will have to use a different approach to choosing the question. It also means that if they keep getting a lot of questions wrong they will be stuck with the same three repeatedly until they get it right so personally I would avoid that unless it is a specification I have to work with.
– 365SplendidSuns
20 hours ago

|
show 2 more comments

This is the right approach, but if OP wants to increase the incorrect question's occurrence, he should not only re-add it to the list, but add it again so that its likelihood of being selected again increases by that much.
– NRitH
2 days ago

@NRitH that's why I said he should add the question to the array again...
– 365SplendidSuns
2 days ago

Thank you both for your replies. That method would definitely be a good starting point for me. @365SplendidSuns what approach would you take to solve this problem? (as you mentioned this is not the best approach). Also some additional detail: If the user “repeatedly" got a question wrong I would like to continue increasing the occurrence of that question until it is being asked every 3 questions. Equally once the user started getting the question correct I would like to reduce it back down until it has an equal chance of being selected again.
– Jonny Taylor
yesterday

@JonnyTaylor A lo depends on the context but I guess I would make a Question class holding the question text as a property along with the answer and methods for checking the answer etc. The class would have a variable holding a float between 0 and 1 indicating the weighting that question should have fro being chosen to be displayed. In my main code I would have an array of Question objects. Pick a question from the array at random then generate a random number between 0 and 1. If the number is < that question's weighting property you display the question if > you repeat with another question.
– 365SplendidSuns
20 hours ago

If the user gets the question wrong you increase the weighting up to a limit. Right you decrease it. Forcing it to be asked every 3 questions when at the limit will make things a bit more complex because on every third question you will have to use a different approach to choosing the question. It also means that if they keep getting a lot of questions wrong they will be stuck with the same three repeatedly until they get it right so personally I would avoid that unless it is a specification I have to work with.
– 365SplendidSuns
20 hours ago

This is the right approach, but if OP wants to increase the incorrect question's occurrence, he should not only re-add it to the list, but add it again so that its likelihood of being selected again increases by that much.
– NRitH
2 days ago

@NRitH that's why I said he should add the question to the array again...
– 365SplendidSuns
2 days ago

Thank you both for your replies. That method would definitely be a good starting point for me. @365SplendidSuns what approach would you take to solve this problem? (as you mentioned this is not the best approach). Also some additional detail: If the user “repeatedly" got a question wrong I would like to continue increasing the occurrence of that question until it is being asked every 3 questions. Equally once the user started getting the question correct I would like to reduce it back down until it has an equal chance of being selected again.
– Jonny Taylor
yesterday

@JonnyTaylor A lo depends on the context but I guess I would make a Question class holding the question text as a property along with the answer and methods for checking the answer etc. The class would have a variable holding a float between 0 and 1 indicating the weighting that question should have fro being chosen to be displayed. In my main code I would have an array of Question objects. Pick a question from the array at random then generate a random number between 0 and 1. If the number is < that question's weighting property you display the question if > you repeat with another question.
– 365SplendidSuns
20 hours ago

If the user gets the question wrong you increase the weighting up to a limit. Right you decrease it. Forcing it to be asked every 3 questions when at the limit will make things a bit more complex because on every third question you will have to use a different approach to choosing the question. It also means that if they keep getting a lot of questions wrong they will be stuck with the same three repeatedly until they get it right so personally I would avoid that unless it is a specification I have to work with.
– 365SplendidSuns
20 hours ago

|
show 2 more comments

Jonny Taylor is a new contributor. Be nice, and check out our Code of Conduct.

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