Calculate the double integral. [closed]
$begingroup$
First of all I would like to ask you if you know a very good material that could help me with range of integration.
$$int_{-1}^ {1} int_{0}^{x+2}y,dy,dx$$
How do I solve this question?
integration
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
asked Dec 11 '18 at 0:32
user2860452user2860452
588
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closed as off-topic by Saad, Nosrati, RRL, Eric Wofsey, Leucippus Dec 22 '18 at 7:08
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Nosrati, RRL, Eric Wofsey, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
First of all I would like to ask you if you know a very good material that could help me with range of integration.
$$int_{-1}^ {1} int_{0}^{x+2}y,dy,dx$$
How do I solve this question?
integration
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
asked Dec 11 '18 at 0:32
user2860452user2860452
588
$endgroup$
closed as off-topic by Saad, Nosrati, RRL, Eric Wofsey, Leucippus Dec 22 '18 at 7:08
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Nosrati, RRL, Eric Wofsey, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Is it $$int_{-1}^1int_0^{x+2}y~dydx~~?$$
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– Dave
Dec 11 '18 at 0:36
2
$begingroup$
tutorial.math.lamar.edu/Classes/CalcIII/DoubleIntegrals.aspx This is a good start may be for double integrals.
$endgroup$
– mm-crj
Dec 11 '18 at 0:39
add a comment |
$begingroup$
First of all I would like to ask you if you know a very good material that could help me with range of integration.
$$int_{-1}^ {1} int_{0}^{x+2}y,dy,dx$$
How do I solve this question?
integration
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
asked Dec 11 '18 at 0:32
user2860452user2860452
588
$endgroup$
First of all I would like to ask you if you know a very good material that could help me with range of integration.
$$int_{-1}^ {1} int_{0}^{x+2}y,dy,dx$$
How do I solve this question?
integration
integration
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
asked Dec 11 '18 at 0:32
user2860452user2860452
588
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
asked Dec 11 '18 at 0:32
user2860452user2860452
588
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
edited Dec 11 '18 at 3:47
Key Flex
7,89961233
7,89961233
asked Dec 11 '18 at 0:32
user2860452user2860452
588
asked Dec 11 '18 at 0:32
user2860452user2860452
588
asked Dec 11 '18 at 0:32
user2860452user2860452
588
588
closed as off-topic by Saad, Nosrati, RRL, Eric Wofsey, Leucippus Dec 22 '18 at 7:08
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Nosrati, RRL, Eric Wofsey, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Saad, Nosrati, RRL, Eric Wofsey, Leucippus Dec 22 '18 at 7:08
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Nosrati, RRL, Eric Wofsey, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Is it $$int_{-1}^1int_0^{x+2}y~dydx~~?$$
$endgroup$
– Dave
Dec 11 '18 at 0:36
2
$begingroup$
tutorial.math.lamar.edu/Classes/CalcIII/DoubleIntegrals.aspx This is a good start may be for double integrals.
$endgroup$
– mm-crj
Dec 11 '18 at 0:39
add a comment |
$begingroup$
Is it $$int_{-1}^1int_0^{x+2}y~dydx~~?$$
$endgroup$
– Dave
Dec 11 '18 at 0:36
2
$begingroup$
tutorial.math.lamar.edu/Classes/CalcIII/DoubleIntegrals.aspx This is a good start may be for double integrals.
$endgroup$
– mm-crj
Dec 11 '18 at 0:39
$begingroup$
Is it $$int_{-1}^1int_0^{x+2}y~dydx~~?$$
$endgroup$
– Dave
Dec 11 '18 at 0:36
$begingroup$
Is it $$int_{-1}^1int_0^{x+2}y~dydx~~?$$
$endgroup$
– Dave
Dec 11 '18 at 0:36
2
2
$begingroup$
tutorial.math.lamar.edu/Classes/CalcIII/DoubleIntegrals.aspx This is a good start may be for double integrals.
$endgroup$
– mm-crj
Dec 11 '18 at 0:39
$begingroup$
tutorial.math.lamar.edu/Classes/CalcIII/DoubleIntegrals.aspx This is a good start may be for double integrals.
$endgroup$
– mm-crj
Dec 11 '18 at 0:39
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The given bounds for $x$ are from $-1$ to $1$ and the given bounds for $y$ are from $0$ to $x+2$
$$int_{-1}^1int_0^{x+2} y dy dx$$
Now first take the inner integral $$int_0^{x+2} y dy=dfrac{(x+2)^2}{2}$$
Now we get $$int_{-1}^1dfrac{(x+2)^2}{2} dx=dfrac{13}{3}$$
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
$endgroup$
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The given bounds for $x$ are from $-1$ to $1$ and the given bounds for $y$ are from $0$ to $x+2$
$$int_{-1}^1int_0^{x+2} y dy dx$$
Now first take the inner integral $$int_0^{x+2} y dy=dfrac{(x+2)^2}{2}$$
Now we get $$int_{-1}^1dfrac{(x+2)^2}{2} dx=dfrac{13}{3}$$
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
$endgroup$
add a comment |
$begingroup$
The given bounds for $x$ are from $-1$ to $1$ and the given bounds for $y$ are from $0$ to $x+2$
$$int_{-1}^1int_0^{x+2} y dy dx$$
Now first take the inner integral $$int_0^{x+2} y dy=dfrac{(x+2)^2}{2}$$
Now we get $$int_{-1}^1dfrac{(x+2)^2}{2} dx=dfrac{13}{3}$$
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
$endgroup$
add a comment |
$begingroup$
The given bounds for $x$ are from $-1$ to $1$ and the given bounds for $y$ are from $0$ to $x+2$
$$int_{-1}^1int_0^{x+2} y dy dx$$
Now first take the inner integral $$int_0^{x+2} y dy=dfrac{(x+2)^2}{2}$$
Now we get $$int_{-1}^1dfrac{(x+2)^2}{2} dx=dfrac{13}{3}$$
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
$endgroup$
The given bounds for $x$ are from $-1$ to $1$ and the given bounds for $y$ are from $0$ to $x+2$
$$int_{-1}^1int_0^{x+2} y dy dx$$
Now first take the inner integral $$int_0^{x+2} y dy=dfrac{(x+2)^2}{2}$$
Now we get $$int_{-1}^1dfrac{(x+2)^2}{2} dx=dfrac{13}{3}$$
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
answered Dec 11 '18 at 0:36
Key FlexKey Flex
7,89961233
7,89961233
add a comment |
add a comment |
$begingroup$
Is it $$int_{-1}^1int_0^{x+2}y~dydx~~?$$
$endgroup$
– Dave
Dec 11 '18 at 0:36
2
$begingroup$
tutorial.math.lamar.edu/Classes/CalcIII/DoubleIntegrals.aspx This is a good start may be for double integrals.
$endgroup$
– mm-crj
Dec 11 '18 at 0:39