Searching for a String in an Array and returning the position

Hi I'm a complete newbie on programming and I try to search for a certain String in an array. When it's found the method should return the index but if the String is not found it should return -1.

public int poitionOfWord(String testWord) {

    for (int i = 0; i < wordArray.length; i++) {

        if (wordArray[i].equals(testWord)) {

            return i;

        }

    }

    return -1;

}

would this method return always -1 or would it actually terminate when finding a word and would return i.

edited Nov 23 '18 at 15:14

deHaar

2,45251628

asked Nov 23 '18 at 15:13

superoma

111

2

What is the value of testWord passed and what are the contents of wordArray

– user7
Nov 23 '18 at 15:13

It will terminate as soon as there's a match, i.e. it will short-circuit.

– Federico Peralta Schaffner
Nov 23 '18 at 15:16

You have to make sure the content of testWord is actually stored in wordArray on an arbitrary position. Otherwise, you code looks ok and should meet the requirements.

– deHaar
Nov 23 '18 at 15:16

Your code looks good. One way of answering your question is running your code...

– f1sh
Nov 23 '18 at 15:22

Your code is fine. It will return the position of the item if found or -1 if not found.

– forpas
Nov 23 '18 at 15:29

add a comment |

public int poitionOfWord(String testWord) {

    for (int i = 0; i < wordArray.length; i++) {

        if (wordArray[i].equals(testWord)) {

            return i;

        }

    }

    return -1;

}

would this method return always -1 or would it actually terminate when finding a word and would return i.

edited Nov 23 '18 at 15:14

deHaar

2,45251628

asked Nov 23 '18 at 15:13

superoma

111

2

What is the value of testWord passed and what are the contents of wordArray

– user7
Nov 23 '18 at 15:13

It will terminate as soon as there's a match, i.e. it will short-circuit.

– Federico Peralta Schaffner
Nov 23 '18 at 15:16

You have to make sure the content of testWord is actually stored in wordArray on an arbitrary position. Otherwise, you code looks ok and should meet the requirements.

– deHaar
Nov 23 '18 at 15:16

Your code looks good. One way of answering your question is running your code...

– f1sh
Nov 23 '18 at 15:22

Your code is fine. It will return the position of the item if found or -1 if not found.

– forpas
Nov 23 '18 at 15:29

add a comment |

public int poitionOfWord(String testWord) {

    for (int i = 0; i < wordArray.length; i++) {

        if (wordArray[i].equals(testWord)) {

            return i;

        }

    }

    return -1;

}

would this method return always -1 or would it actually terminate when finding a word and would return i.

edited Nov 23 '18 at 15:14

deHaar

2,45251628

asked Nov 23 '18 at 15:13

superoma

111

public int poitionOfWord(String testWord) {

    for (int i = 0; i < wordArray.length; i++) {

        if (wordArray[i].equals(testWord)) {

            return i;

        }

    }

    return -1;

}

would this method return always -1 or would it actually terminate when finding a word and would return i.

java arrays equals

edited Nov 23 '18 at 15:14

deHaar

2,45251628

asked Nov 23 '18 at 15:13

superoma

111

edited Nov 23 '18 at 15:14

deHaar

2,45251628

asked Nov 23 '18 at 15:13

superoma

111

edited Nov 23 '18 at 15:14

deHaar

2,45251628

edited Nov 23 '18 at 15:14

deHaar

2,45251628

edited Nov 23 '18 at 15:14

deHaar

2,45251628

asked Nov 23 '18 at 15:13

superoma

111

asked Nov 23 '18 at 15:13

superoma

111

asked Nov 23 '18 at 15:13

superoma

111

2

What is the value of testWord passed and what are the contents of wordArray

– user7
Nov 23 '18 at 15:13

It will terminate as soon as there's a match, i.e. it will short-circuit.

– Federico Peralta Schaffner
Nov 23 '18 at 15:16

You have to make sure the content of testWord is actually stored in wordArray on an arbitrary position. Otherwise, you code looks ok and should meet the requirements.

– deHaar
Nov 23 '18 at 15:16

Your code looks good. One way of answering your question is running your code...

– f1sh
Nov 23 '18 at 15:22

Your code is fine. It will return the position of the item if found or -1 if not found.

– forpas
Nov 23 '18 at 15:29

add a comment |

2

What is the value of testWord passed and what are the contents of wordArray

– user7
Nov 23 '18 at 15:13

It will terminate as soon as there's a match, i.e. it will short-circuit.

– Federico Peralta Schaffner
Nov 23 '18 at 15:16

You have to make sure the content of testWord is actually stored in wordArray on an arbitrary position. Otherwise, you code looks ok and should meet the requirements.

– deHaar
Nov 23 '18 at 15:16

Your code looks good. One way of answering your question is running your code...

– f1sh
Nov 23 '18 at 15:22

Your code is fine. It will return the position of the item if found or -1 if not found.

– forpas
Nov 23 '18 at 15:29

What is the value of testWord passed and what are the contents of wordArray

– user7
Nov 23 '18 at 15:13

It will terminate as soon as there's a match, i.e. it will short-circuit.

– Federico Peralta Schaffner
Nov 23 '18 at 15:16

You have to make sure the content of testWord is actually stored in wordArray on an arbitrary position. Otherwise, you code looks ok and should meet the requirements.

– deHaar
Nov 23 '18 at 15:16

Your code looks good. One way of answering your question is running your code...

– f1sh
Nov 23 '18 at 15:22

Your code is fine. It will return the position of the item if found or -1 if not found.

– forpas
Nov 23 '18 at 15:29

add a comment |

2 Answers
2

active

oldest

votes

-1

Your method is correct and it will return the index in case it finds a match else if it doesn't find the match, it will come out of loop and return -1.

Just to make code crisp and concise, you can use something like this,

public static String wordArray = new String{"a", "b"};

public static int poitionOfWord(String testWord) {

    return Arrays.asList(wordArray).indexOf(testWord);

}

Then test it with some code,

public static void main(String args) {

    System.out.println(poitionOfWord("a"));

    System.out.println(poitionOfWord("z"));

}

This prints,

1

-1

edited Nov 23 '18 at 15:28

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

add a comment |

-1

In general, when your function reaches a return statement, it will terminate and return the given value.

answered Nov 23 '18 at 15:24

DrNaughtyDog

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

-1

Your method is correct and it will return the index in case it finds a match else if it doesn't find the match, it will come out of loop and return -1.

Just to make code crisp and concise, you can use something like this,

public static String wordArray = new String{"a", "b"};

public static int poitionOfWord(String testWord) {

    return Arrays.asList(wordArray).indexOf(testWord);

}

Then test it with some code,

public static void main(String args) {

    System.out.println(poitionOfWord("a"));

    System.out.println(poitionOfWord("z"));

}

This prints,

1

-1

edited Nov 23 '18 at 15:28

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

add a comment |

-1

Your method is correct and it will return the index in case it finds a match else if it doesn't find the match, it will come out of loop and return -1.

Just to make code crisp and concise, you can use something like this,

public static String wordArray = new String{"a", "b"};

public static int poitionOfWord(String testWord) {

    return Arrays.asList(wordArray).indexOf(testWord);

}

Then test it with some code,

public static void main(String args) {

    System.out.println(poitionOfWord("a"));

    System.out.println(poitionOfWord("z"));

}

This prints,

1

-1

edited Nov 23 '18 at 15:28

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

add a comment |

-1

Your method is correct and it will return the index in case it finds a match else if it doesn't find the match, it will come out of loop and return -1.

Just to make code crisp and concise, you can use something like this,

public static String wordArray = new String{"a", "b"};

public static int poitionOfWord(String testWord) {

    return Arrays.asList(wordArray).indexOf(testWord);

}

Then test it with some code,

public static void main(String args) {

    System.out.println(poitionOfWord("a"));

    System.out.println(poitionOfWord("z"));

}

This prints,

1

-1

edited Nov 23 '18 at 15:28

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

Your method is correct and it will return the index in case it finds a match else if it doesn't find the match, it will come out of loop and return -1.

Just to make code crisp and concise, you can use something like this,

public static String wordArray = new String{"a", "b"};

public static int poitionOfWord(String testWord) {

    return Arrays.asList(wordArray).indexOf(testWord);

}

Then test it with some code,

public static void main(String args) {

    System.out.println(poitionOfWord("a"));

    System.out.println(poitionOfWord("z"));

}

This prints,

1

-1

edited Nov 23 '18 at 15:28

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

edited Nov 23 '18 at 15:28

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

answered Nov 23 '18 at 15:22

Pushpesh Kumar Rajwanshi

7,8362927

add a comment |

-1

In general, when your function reaches a return statement, it will terminate and return the given value.

answered Nov 23 '18 at 15:24

DrNaughtyDog

add a comment |

-1

In general, when your function reaches a return statement, it will terminate and return the given value.

answered Nov 23 '18 at 15:24

DrNaughtyDog

add a comment |

-1

In general, when your function reaches a return statement, it will terminate and return the given value.

answered Nov 23 '18 at 15:24

DrNaughtyDog

In general, when your function reaches a return statement, it will terminate and return the given value.

answered Nov 23 '18 at 15:24

DrNaughtyDog

answered Nov 23 '18 at 15:24

DrNaughtyDog

answered Nov 23 '18 at 15:24

DrNaughtyDog

answered Nov 23 '18 at 15:24

DrNaughtyDog

add a comment |

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