dplyr Rolling Conditional Counts











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I have a data frame as follows:



df <- data.frame(
Item=c("A","A","A","A","A","B","B","B","B","B"),
Date=c("2018-1-1","2018-2-1","2018-3-1","2018-4-1","2018-5-1","2018-1-1","2018-2-1",
"2018-3-1","2018-4-1","2018-5-1"),
Value=rnorm(10))


I want to mutate a new column grouped by Item, to count the number of values higher than 0 within the window of 3 (or any other integer I specify).



I am familiar with tidyverse, therefore, a dplyr solution would be most welcome.










share|improve this question




























    up vote
    0
    down vote

    favorite












    I have a data frame as follows:



    df <- data.frame(
    Item=c("A","A","A","A","A","B","B","B","B","B"),
    Date=c("2018-1-1","2018-2-1","2018-3-1","2018-4-1","2018-5-1","2018-1-1","2018-2-1",
    "2018-3-1","2018-4-1","2018-5-1"),
    Value=rnorm(10))


    I want to mutate a new column grouped by Item, to count the number of values higher than 0 within the window of 3 (or any other integer I specify).



    I am familiar with tidyverse, therefore, a dplyr solution would be most welcome.










    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a data frame as follows:



      df <- data.frame(
      Item=c("A","A","A","A","A","B","B","B","B","B"),
      Date=c("2018-1-1","2018-2-1","2018-3-1","2018-4-1","2018-5-1","2018-1-1","2018-2-1",
      "2018-3-1","2018-4-1","2018-5-1"),
      Value=rnorm(10))


      I want to mutate a new column grouped by Item, to count the number of values higher than 0 within the window of 3 (or any other integer I specify).



      I am familiar with tidyverse, therefore, a dplyr solution would be most welcome.










      share|improve this question















      I have a data frame as follows:



      df <- data.frame(
      Item=c("A","A","A","A","A","B","B","B","B","B"),
      Date=c("2018-1-1","2018-2-1","2018-3-1","2018-4-1","2018-5-1","2018-1-1","2018-2-1",
      "2018-3-1","2018-4-1","2018-5-1"),
      Value=rnorm(10))


      I want to mutate a new column grouped by Item, to count the number of values higher than 0 within the window of 3 (or any other integer I specify).



      I am familiar with tidyverse, therefore, a dplyr solution would be most welcome.







      r dplyr






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 at 13:47









      Ronak Shah

      30.7k103753




      30.7k103753










      asked Nov 20 at 12:51









      Felix Zhao

      4614




      4614
























          3 Answers
          3






          active

          oldest

          votes

















          up vote
          0
          down vote



          accepted










            Item  Date       Value
          <fct> <date> <int>
          1 A 2018-01-01 3
          2 B 2018-01-01 2
          3 B 2018-02-01 -5
          4 A 2018-02-01 -3
          5 A 2018-03-01 4
          6 B 2018-03-01 -2
          7 A 2018-04-01 5
          8 B 2018-04-01 0
          9 A 2018-05-01 1
          10 B 2018-05-01 -4


          Changed rnorm example for clarity, used sample(-5:5):



          > df <- df %>% mutate(greater_than = (Value>0)*Value) %>%
          group_by(Item) %>% arrange(Date) %>% mutate(greater_than =
          zoo::rollapplyr(greater_than, 3, sum, partial = T))
          df %>% arrange(Item) %>% head(10)


          Should look like this:



           1 A     2018-01-01     3            3
          2 A 2018-02-01 -3 3
          3 A 2018-03-01 4 7
          4 A 2018-04-01 5 9
          5 A 2018-05-01 1 10
          6 B 2018-01-01 2 2
          7 B 2018-02-01 -5 2
          8 B 2018-03-01 -2 2
          9 B 2018-04-01 0 0
          10 B 2018-05-01 -4 0





          share|improve this answer




























            up vote
            3
            down vote













            Think zoo:: package if you want to roll anything.



            df$new<-
            zoo::rollsum( df$Value > 0, 3, fill = NA )

            # Item Date Value new
            #1 A 2018-1-1 0.5852699 NA
            #2 A 2018-2-1 -0.7383377 1
            #3 A 2018-3-1 -0.3157693 1
            #4 A 2018-4-1 1.2475237 1
            #5 A 2018-5-1 -1.5479757 1
            #6 B 2018-1-1 -0.6913331 0
            #7 B 2018-2-1 -0.2423809 0
            #8 B 2018-3-1 -1.6363024 0
            #9 B 2018-4-1 -0.3256263 1
            #10 B 2018-5-1 0.3563144 NA


            You have an option of the "window-position". Have a closer look at argument align = c("center", "left", "right").





            So as a dplyr chain:



            df %>% group_by(Item) %>% dplyr::mutate( new = zoo::rollsum( Value > 0, 3, fill = NA ))





            share|improve this answer























            • Thanks Andre for your help. I tested with your method, it works!
              – Felix Zhao
              Nov 21 at 12:04










            • If your problem got solved please choose an answer.
              – Andre Elrico
              Nov 22 at 11:11


















            up vote
            1
            down vote













            You could use the RcppRoll package.



            require(RcppRoll)
            df$new <- df$new <- RcppRoll::roll_sum(df$Value > 0, 3, fill = NA)


            Using Tidyverse:



            df %>% 
            group_by(Item) %>%
            dplyr::mutate(new = RcppRoll::roll_sum(Value > 0, 3, fill = NA))


            Speedwise this is faster than the zoo Package:



            n <- 10000
            df <- data.frame(
            Item = sample(LETTERS, n, replace = TRUE),
            Value = rnorm(n))

            df_grouped <- df %>%
            group_by(Item)
            microbenchmark::microbenchmark(
            RcppRoll = df_grouped <- df_grouped %>% dplyr::mutate(new_RcppRoll = RcppRoll::roll_sum(Value > 0, 3, fill = NA)),
            zoo = df_grouped <- df_grouped %>% dplyr::mutate(new_zoo = zoo::rollsum( Value > 0, 3, fill = NA ))
            )


            Results in:



            Unit: milliseconds
            expr min lq mean median uq max neval
            RcppRoll 2.509003 2.741993 2.929227 2.83913 2.983726 5.832962 100
            zoo 11.172920 11.785113 13.288970 12.43320 13.607826 25.879754 100


            And



            all.equal(df_grouped$new_RcppRoll, df_grouped$new_zoo)
            TRUE





            share|improve this answer





















            • Hi Rentrop, it took me to figure out the alignment clause and it is a really good package dealing with rolling. Thanks a lot for your help!
              – Felix Zhao
              Nov 21 at 12:06











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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

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            active

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            up vote
            0
            down vote



            accepted










              Item  Date       Value
            <fct> <date> <int>
            1 A 2018-01-01 3
            2 B 2018-01-01 2
            3 B 2018-02-01 -5
            4 A 2018-02-01 -3
            5 A 2018-03-01 4
            6 B 2018-03-01 -2
            7 A 2018-04-01 5
            8 B 2018-04-01 0
            9 A 2018-05-01 1
            10 B 2018-05-01 -4


            Changed rnorm example for clarity, used sample(-5:5):



            > df <- df %>% mutate(greater_than = (Value>0)*Value) %>%
            group_by(Item) %>% arrange(Date) %>% mutate(greater_than =
            zoo::rollapplyr(greater_than, 3, sum, partial = T))
            df %>% arrange(Item) %>% head(10)


            Should look like this:



             1 A     2018-01-01     3            3
            2 A 2018-02-01 -3 3
            3 A 2018-03-01 4 7
            4 A 2018-04-01 5 9
            5 A 2018-05-01 1 10
            6 B 2018-01-01 2 2
            7 B 2018-02-01 -5 2
            8 B 2018-03-01 -2 2
            9 B 2018-04-01 0 0
            10 B 2018-05-01 -4 0





            share|improve this answer

























              up vote
              0
              down vote



              accepted










                Item  Date       Value
              <fct> <date> <int>
              1 A 2018-01-01 3
              2 B 2018-01-01 2
              3 B 2018-02-01 -5
              4 A 2018-02-01 -3
              5 A 2018-03-01 4
              6 B 2018-03-01 -2
              7 A 2018-04-01 5
              8 B 2018-04-01 0
              9 A 2018-05-01 1
              10 B 2018-05-01 -4


              Changed rnorm example for clarity, used sample(-5:5):



              > df <- df %>% mutate(greater_than = (Value>0)*Value) %>%
              group_by(Item) %>% arrange(Date) %>% mutate(greater_than =
              zoo::rollapplyr(greater_than, 3, sum, partial = T))
              df %>% arrange(Item) %>% head(10)


              Should look like this:



               1 A     2018-01-01     3            3
              2 A 2018-02-01 -3 3
              3 A 2018-03-01 4 7
              4 A 2018-04-01 5 9
              5 A 2018-05-01 1 10
              6 B 2018-01-01 2 2
              7 B 2018-02-01 -5 2
              8 B 2018-03-01 -2 2
              9 B 2018-04-01 0 0
              10 B 2018-05-01 -4 0





              share|improve this answer























                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                  Item  Date       Value
                <fct> <date> <int>
                1 A 2018-01-01 3
                2 B 2018-01-01 2
                3 B 2018-02-01 -5
                4 A 2018-02-01 -3
                5 A 2018-03-01 4
                6 B 2018-03-01 -2
                7 A 2018-04-01 5
                8 B 2018-04-01 0
                9 A 2018-05-01 1
                10 B 2018-05-01 -4


                Changed rnorm example for clarity, used sample(-5:5):



                > df <- df %>% mutate(greater_than = (Value>0)*Value) %>%
                group_by(Item) %>% arrange(Date) %>% mutate(greater_than =
                zoo::rollapplyr(greater_than, 3, sum, partial = T))
                df %>% arrange(Item) %>% head(10)


                Should look like this:



                 1 A     2018-01-01     3            3
                2 A 2018-02-01 -3 3
                3 A 2018-03-01 4 7
                4 A 2018-04-01 5 9
                5 A 2018-05-01 1 10
                6 B 2018-01-01 2 2
                7 B 2018-02-01 -5 2
                8 B 2018-03-01 -2 2
                9 B 2018-04-01 0 0
                10 B 2018-05-01 -4 0





                share|improve this answer












                  Item  Date       Value
                <fct> <date> <int>
                1 A 2018-01-01 3
                2 B 2018-01-01 2
                3 B 2018-02-01 -5
                4 A 2018-02-01 -3
                5 A 2018-03-01 4
                6 B 2018-03-01 -2
                7 A 2018-04-01 5
                8 B 2018-04-01 0
                9 A 2018-05-01 1
                10 B 2018-05-01 -4


                Changed rnorm example for clarity, used sample(-5:5):



                > df <- df %>% mutate(greater_than = (Value>0)*Value) %>%
                group_by(Item) %>% arrange(Date) %>% mutate(greater_than =
                zoo::rollapplyr(greater_than, 3, sum, partial = T))
                df %>% arrange(Item) %>% head(10)


                Should look like this:



                 1 A     2018-01-01     3            3
                2 A 2018-02-01 -3 3
                3 A 2018-03-01 4 7
                4 A 2018-04-01 5 9
                5 A 2018-05-01 1 10
                6 B 2018-01-01 2 2
                7 B 2018-02-01 -5 2
                8 B 2018-03-01 -2 2
                9 B 2018-04-01 0 0
                10 B 2018-05-01 -4 0






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 20 at 13:37









                Matheus Deister Veiga

                16




                16
























                    up vote
                    3
                    down vote













                    Think zoo:: package if you want to roll anything.



                    df$new<-
                    zoo::rollsum( df$Value > 0, 3, fill = NA )

                    # Item Date Value new
                    #1 A 2018-1-1 0.5852699 NA
                    #2 A 2018-2-1 -0.7383377 1
                    #3 A 2018-3-1 -0.3157693 1
                    #4 A 2018-4-1 1.2475237 1
                    #5 A 2018-5-1 -1.5479757 1
                    #6 B 2018-1-1 -0.6913331 0
                    #7 B 2018-2-1 -0.2423809 0
                    #8 B 2018-3-1 -1.6363024 0
                    #9 B 2018-4-1 -0.3256263 1
                    #10 B 2018-5-1 0.3563144 NA


                    You have an option of the "window-position". Have a closer look at argument align = c("center", "left", "right").





                    So as a dplyr chain:



                    df %>% group_by(Item) %>% dplyr::mutate( new = zoo::rollsum( Value > 0, 3, fill = NA ))





                    share|improve this answer























                    • Thanks Andre for your help. I tested with your method, it works!
                      – Felix Zhao
                      Nov 21 at 12:04










                    • If your problem got solved please choose an answer.
                      – Andre Elrico
                      Nov 22 at 11:11















                    up vote
                    3
                    down vote













                    Think zoo:: package if you want to roll anything.



                    df$new<-
                    zoo::rollsum( df$Value > 0, 3, fill = NA )

                    # Item Date Value new
                    #1 A 2018-1-1 0.5852699 NA
                    #2 A 2018-2-1 -0.7383377 1
                    #3 A 2018-3-1 -0.3157693 1
                    #4 A 2018-4-1 1.2475237 1
                    #5 A 2018-5-1 -1.5479757 1
                    #6 B 2018-1-1 -0.6913331 0
                    #7 B 2018-2-1 -0.2423809 0
                    #8 B 2018-3-1 -1.6363024 0
                    #9 B 2018-4-1 -0.3256263 1
                    #10 B 2018-5-1 0.3563144 NA


                    You have an option of the "window-position". Have a closer look at argument align = c("center", "left", "right").





                    So as a dplyr chain:



                    df %>% group_by(Item) %>% dplyr::mutate( new = zoo::rollsum( Value > 0, 3, fill = NA ))





                    share|improve this answer























                    • Thanks Andre for your help. I tested with your method, it works!
                      – Felix Zhao
                      Nov 21 at 12:04










                    • If your problem got solved please choose an answer.
                      – Andre Elrico
                      Nov 22 at 11:11













                    up vote
                    3
                    down vote










                    up vote
                    3
                    down vote









                    Think zoo:: package if you want to roll anything.



                    df$new<-
                    zoo::rollsum( df$Value > 0, 3, fill = NA )

                    # Item Date Value new
                    #1 A 2018-1-1 0.5852699 NA
                    #2 A 2018-2-1 -0.7383377 1
                    #3 A 2018-3-1 -0.3157693 1
                    #4 A 2018-4-1 1.2475237 1
                    #5 A 2018-5-1 -1.5479757 1
                    #6 B 2018-1-1 -0.6913331 0
                    #7 B 2018-2-1 -0.2423809 0
                    #8 B 2018-3-1 -1.6363024 0
                    #9 B 2018-4-1 -0.3256263 1
                    #10 B 2018-5-1 0.3563144 NA


                    You have an option of the "window-position". Have a closer look at argument align = c("center", "left", "right").





                    So as a dplyr chain:



                    df %>% group_by(Item) %>% dplyr::mutate( new = zoo::rollsum( Value > 0, 3, fill = NA ))





                    share|improve this answer














                    Think zoo:: package if you want to roll anything.



                    df$new<-
                    zoo::rollsum( df$Value > 0, 3, fill = NA )

                    # Item Date Value new
                    #1 A 2018-1-1 0.5852699 NA
                    #2 A 2018-2-1 -0.7383377 1
                    #3 A 2018-3-1 -0.3157693 1
                    #4 A 2018-4-1 1.2475237 1
                    #5 A 2018-5-1 -1.5479757 1
                    #6 B 2018-1-1 -0.6913331 0
                    #7 B 2018-2-1 -0.2423809 0
                    #8 B 2018-3-1 -1.6363024 0
                    #9 B 2018-4-1 -0.3256263 1
                    #10 B 2018-5-1 0.3563144 NA


                    You have an option of the "window-position". Have a closer look at argument align = c("center", "left", "right").





                    So as a dplyr chain:



                    df %>% group_by(Item) %>% dplyr::mutate( new = zoo::rollsum( Value > 0, 3, fill = NA ))






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 20 at 13:16

























                    answered Nov 20 at 13:03









                    Andre Elrico

                    5,56311027




                    5,56311027












                    • Thanks Andre for your help. I tested with your method, it works!
                      – Felix Zhao
                      Nov 21 at 12:04










                    • If your problem got solved please choose an answer.
                      – Andre Elrico
                      Nov 22 at 11:11


















                    • Thanks Andre for your help. I tested with your method, it works!
                      – Felix Zhao
                      Nov 21 at 12:04










                    • If your problem got solved please choose an answer.
                      – Andre Elrico
                      Nov 22 at 11:11
















                    Thanks Andre for your help. I tested with your method, it works!
                    – Felix Zhao
                    Nov 21 at 12:04




                    Thanks Andre for your help. I tested with your method, it works!
                    – Felix Zhao
                    Nov 21 at 12:04












                    If your problem got solved please choose an answer.
                    – Andre Elrico
                    Nov 22 at 11:11




                    If your problem got solved please choose an answer.
                    – Andre Elrico
                    Nov 22 at 11:11










                    up vote
                    1
                    down vote













                    You could use the RcppRoll package.



                    require(RcppRoll)
                    df$new <- df$new <- RcppRoll::roll_sum(df$Value > 0, 3, fill = NA)


                    Using Tidyverse:



                    df %>% 
                    group_by(Item) %>%
                    dplyr::mutate(new = RcppRoll::roll_sum(Value > 0, 3, fill = NA))


                    Speedwise this is faster than the zoo Package:



                    n <- 10000
                    df <- data.frame(
                    Item = sample(LETTERS, n, replace = TRUE),
                    Value = rnorm(n))

                    df_grouped <- df %>%
                    group_by(Item)
                    microbenchmark::microbenchmark(
                    RcppRoll = df_grouped <- df_grouped %>% dplyr::mutate(new_RcppRoll = RcppRoll::roll_sum(Value > 0, 3, fill = NA)),
                    zoo = df_grouped <- df_grouped %>% dplyr::mutate(new_zoo = zoo::rollsum( Value > 0, 3, fill = NA ))
                    )


                    Results in:



                    Unit: milliseconds
                    expr min lq mean median uq max neval
                    RcppRoll 2.509003 2.741993 2.929227 2.83913 2.983726 5.832962 100
                    zoo 11.172920 11.785113 13.288970 12.43320 13.607826 25.879754 100


                    And



                    all.equal(df_grouped$new_RcppRoll, df_grouped$new_zoo)
                    TRUE





                    share|improve this answer





















                    • Hi Rentrop, it took me to figure out the alignment clause and it is a really good package dealing with rolling. Thanks a lot for your help!
                      – Felix Zhao
                      Nov 21 at 12:06















                    up vote
                    1
                    down vote













                    You could use the RcppRoll package.



                    require(RcppRoll)
                    df$new <- df$new <- RcppRoll::roll_sum(df$Value > 0, 3, fill = NA)


                    Using Tidyverse:



                    df %>% 
                    group_by(Item) %>%
                    dplyr::mutate(new = RcppRoll::roll_sum(Value > 0, 3, fill = NA))


                    Speedwise this is faster than the zoo Package:



                    n <- 10000
                    df <- data.frame(
                    Item = sample(LETTERS, n, replace = TRUE),
                    Value = rnorm(n))

                    df_grouped <- df %>%
                    group_by(Item)
                    microbenchmark::microbenchmark(
                    RcppRoll = df_grouped <- df_grouped %>% dplyr::mutate(new_RcppRoll = RcppRoll::roll_sum(Value > 0, 3, fill = NA)),
                    zoo = df_grouped <- df_grouped %>% dplyr::mutate(new_zoo = zoo::rollsum( Value > 0, 3, fill = NA ))
                    )


                    Results in:



                    Unit: milliseconds
                    expr min lq mean median uq max neval
                    RcppRoll 2.509003 2.741993 2.929227 2.83913 2.983726 5.832962 100
                    zoo 11.172920 11.785113 13.288970 12.43320 13.607826 25.879754 100


                    And



                    all.equal(df_grouped$new_RcppRoll, df_grouped$new_zoo)
                    TRUE





                    share|improve this answer





















                    • Hi Rentrop, it took me to figure out the alignment clause and it is a really good package dealing with rolling. Thanks a lot for your help!
                      – Felix Zhao
                      Nov 21 at 12:06













                    up vote
                    1
                    down vote










                    up vote
                    1
                    down vote









                    You could use the RcppRoll package.



                    require(RcppRoll)
                    df$new <- df$new <- RcppRoll::roll_sum(df$Value > 0, 3, fill = NA)


                    Using Tidyverse:



                    df %>% 
                    group_by(Item) %>%
                    dplyr::mutate(new = RcppRoll::roll_sum(Value > 0, 3, fill = NA))


                    Speedwise this is faster than the zoo Package:



                    n <- 10000
                    df <- data.frame(
                    Item = sample(LETTERS, n, replace = TRUE),
                    Value = rnorm(n))

                    df_grouped <- df %>%
                    group_by(Item)
                    microbenchmark::microbenchmark(
                    RcppRoll = df_grouped <- df_grouped %>% dplyr::mutate(new_RcppRoll = RcppRoll::roll_sum(Value > 0, 3, fill = NA)),
                    zoo = df_grouped <- df_grouped %>% dplyr::mutate(new_zoo = zoo::rollsum( Value > 0, 3, fill = NA ))
                    )


                    Results in:



                    Unit: milliseconds
                    expr min lq mean median uq max neval
                    RcppRoll 2.509003 2.741993 2.929227 2.83913 2.983726 5.832962 100
                    zoo 11.172920 11.785113 13.288970 12.43320 13.607826 25.879754 100


                    And



                    all.equal(df_grouped$new_RcppRoll, df_grouped$new_zoo)
                    TRUE





                    share|improve this answer












                    You could use the RcppRoll package.



                    require(RcppRoll)
                    df$new <- df$new <- RcppRoll::roll_sum(df$Value > 0, 3, fill = NA)


                    Using Tidyverse:



                    df %>% 
                    group_by(Item) %>%
                    dplyr::mutate(new = RcppRoll::roll_sum(Value > 0, 3, fill = NA))


                    Speedwise this is faster than the zoo Package:



                    n <- 10000
                    df <- data.frame(
                    Item = sample(LETTERS, n, replace = TRUE),
                    Value = rnorm(n))

                    df_grouped <- df %>%
                    group_by(Item)
                    microbenchmark::microbenchmark(
                    RcppRoll = df_grouped <- df_grouped %>% dplyr::mutate(new_RcppRoll = RcppRoll::roll_sum(Value > 0, 3, fill = NA)),
                    zoo = df_grouped <- df_grouped %>% dplyr::mutate(new_zoo = zoo::rollsum( Value > 0, 3, fill = NA ))
                    )


                    Results in:



                    Unit: milliseconds
                    expr min lq mean median uq max neval
                    RcppRoll 2.509003 2.741993 2.929227 2.83913 2.983726 5.832962 100
                    zoo 11.172920 11.785113 13.288970 12.43320 13.607826 25.879754 100


                    And



                    all.equal(df_grouped$new_RcppRoll, df_grouped$new_zoo)
                    TRUE






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 20 at 13:33









                    Rentrop

                    13.9k33871




                    13.9k33871












                    • Hi Rentrop, it took me to figure out the alignment clause and it is a really good package dealing with rolling. Thanks a lot for your help!
                      – Felix Zhao
                      Nov 21 at 12:06


















                    • Hi Rentrop, it took me to figure out the alignment clause and it is a really good package dealing with rolling. Thanks a lot for your help!
                      – Felix Zhao
                      Nov 21 at 12:06
















                    Hi Rentrop, it took me to figure out the alignment clause and it is a really good package dealing with rolling. Thanks a lot for your help!
                    – Felix Zhao
                    Nov 21 at 12:06




                    Hi Rentrop, it took me to figure out the alignment clause and it is a really good package dealing with rolling. Thanks a lot for your help!
                    – Felix Zhao
                    Nov 21 at 12:06


















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