Is there any method to embed $K_p$ into a orientable surface?
0
$begingroup$
It is known that $K_p$ can be embedded into genus $g=lceil{frac{(p-3)(p-4)}{12}}rceil$ orientable surface. Do we know how to embed $K_p$ into the genus $g$ orientable surface?
graph-theory geometric-topology low-dimensional-topology
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
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add a comment |
0
$begingroup$
It is known that $K_p$ can be embedded into genus $g=lceil{frac{(p-3)(p-4)}{12}}rceil$ orientable surface. Do we know how to embed $K_p$ into the genus $g$ orientable surface?
graph-theory geometric-topology low-dimensional-topology
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
$endgroup$
$begingroup$
Did you learn anything from the proof that it can be embedded which is pertinent to your question?
$endgroup$
– Lee Mosher
Jan 2 at 19:40
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@Lee Mosher, I read the proof (may be sketch of the proof) from 'Graph Theory, Frank Harary'. There is used 'g geq the number' and 'g leq the number' so they are equal. So the answer of your question is no.
$endgroup$
– camsilbira
Jan 10 at 8:21
1
$begingroup$
Well, if you have read the proof, or a sketch, then the better way to write your question is to tell us what part you understand, where you got stuck, etc. etc.
$endgroup$
– Lee Mosher
Jan 10 at 12:51
add a comment |
0
0
0
$begingroup$
It is known that $K_p$ can be embedded into genus $g=lceil{frac{(p-3)(p-4)}{12}}rceil$ orientable surface. Do we know how to embed $K_p$ into the genus $g$ orientable surface?
graph-theory geometric-topology low-dimensional-topology
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
$endgroup$
It is known that $K_p$ can be embedded into genus $g=lceil{frac{(p-3)(p-4)}{12}}rceil$ orientable surface. Do we know how to embed $K_p$ into the genus $g$ orientable surface?
graph-theory geometric-topology low-dimensional-topology
graph-theory geometric-topology low-dimensional-topology
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
asked Dec 31 '18 at 14:28
camsilbiracamsilbira
119111
119111
$begingroup$
Did you learn anything from the proof that it can be embedded which is pertinent to your question?
$endgroup$
– Lee Mosher
Jan 2 at 19:40
$begingroup$
@Lee Mosher, I read the proof (may be sketch of the proof) from 'Graph Theory, Frank Harary'. There is used 'g geq the number' and 'g leq the number' so they are equal. So the answer of your question is no.
$endgroup$
– camsilbira
Jan 10 at 8:21
1
$begingroup$
Well, if you have read the proof, or a sketch, then the better way to write your question is to tell us what part you understand, where you got stuck, etc. etc.
$endgroup$
– Lee Mosher
Jan 10 at 12:51
add a comment |
$begingroup$
Did you learn anything from the proof that it can be embedded which is pertinent to your question?
$endgroup$
– Lee Mosher
Jan 2 at 19:40
$begingroup$
@Lee Mosher, I read the proof (may be sketch of the proof) from 'Graph Theory, Frank Harary'. There is used 'g geq the number' and 'g leq the number' so they are equal. So the answer of your question is no.
$endgroup$
– camsilbira
Jan 10 at 8:21
1
$begingroup$
Well, if you have read the proof, or a sketch, then the better way to write your question is to tell us what part you understand, where you got stuck, etc. etc.
$endgroup$
– Lee Mosher
Jan 10 at 12:51
$begingroup$
Did you learn anything from the proof that it can be embedded which is pertinent to your question?
$endgroup$
– Lee Mosher
Jan 2 at 19:40
$begingroup$
Did you learn anything from the proof that it can be embedded which is pertinent to your question?
$endgroup$
– Lee Mosher
Jan 2 at 19:40
$begingroup$
@Lee Mosher, I read the proof (may be sketch of the proof) from 'Graph Theory, Frank Harary'. There is used 'g geq the number' and 'g leq the number' so they are equal. So the answer of your question is no.
$endgroup$
– camsilbira
Jan 10 at 8:21
$begingroup$
@Lee Mosher, I read the proof (may be sketch of the proof) from 'Graph Theory, Frank Harary'. There is used 'g geq the number' and 'g leq the number' so they are equal. So the answer of your question is no.
$endgroup$
– camsilbira
Jan 10 at 8:21
1
1
$begingroup$
Well, if you have read the proof, or a sketch, then the better way to write your question is to tell us what part you understand, where you got stuck, etc. etc.
$endgroup$
– Lee Mosher
Jan 10 at 12:51
$begingroup$
Well, if you have read the proof, or a sketch, then the better way to write your question is to tell us what part you understand, where you got stuck, etc. etc.
$endgroup$
– Lee Mosher
Jan 10 at 12:51
add a comment |
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$begingroup$
Did you learn anything from the proof that it can be embedded which is pertinent to your question?
$endgroup$
– Lee Mosher
Jan 2 at 19:40
$begingroup$
@Lee Mosher, I read the proof (may be sketch of the proof) from 'Graph Theory, Frank Harary'. There is used 'g geq the number' and 'g leq the number' so they are equal. So the answer of your question is no.
$endgroup$
– camsilbira
Jan 10 at 8:21
1
$begingroup$
Well, if you have read the proof, or a sketch, then the better way to write your question is to tell us what part you understand, where you got stuck, etc. etc.
$endgroup$
– Lee Mosher
Jan 10 at 12:51