On torsion sheaf of a coherent sheaf of $dim X$












0












$begingroup$


$underline {Background}$:Let,$E$ be a coherent sheaf on a Noetherian,integral scheme $X$ and $dim E$=$dim X$.



Then we have the unique torsion filtration of that coherent sheaf as



$0subset T_0(E)subset....subset T_{dim X-1}(E) subset T_{dim X} (E)=E$



where,$T_i(E)$ is the maximal subsheaf of of $E$ of dimension $leq i$



we also have torsion subsheaf of $E$ ,denoted by $T(E)$ which is defined as



for any affine $SpecA$ in $X$, define $ T(E)(SpecA)$:={$m in E(SpecA)|exists sin A$ with $s$ nonzero such that $s.m=0$}



we also have $(T(E))_x=T(E_x)$



$underline {Question}$:How do we show that $T(E)=T_{dim X-1}(E)$



I only know that $T(E)$ is a subsheaf of $E$ ,and I am supposed to show the following



$T(E)$ is a maximal subsheaf of dimension $leq dim(X)-1$.



I have no clue how to show (i) it has dimension $leq dim(X)-1$ and



(ii) It is maximal among all such subsheaves.



Any help from anyone is welcome.










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$endgroup$












  • $begingroup$
    What do you mean by $dim E$?
    $endgroup$
    – Armando j18eos
    Jan 2 at 11:12










  • $begingroup$
    @Armandoj18eos $dim E=dim(Supp( E))$
    $endgroup$
    – HARRY
    Jan 2 at 13:11


















0












$begingroup$


$underline {Background}$:Let,$E$ be a coherent sheaf on a Noetherian,integral scheme $X$ and $dim E$=$dim X$.



Then we have the unique torsion filtration of that coherent sheaf as



$0subset T_0(E)subset....subset T_{dim X-1}(E) subset T_{dim X} (E)=E$



where,$T_i(E)$ is the maximal subsheaf of of $E$ of dimension $leq i$



we also have torsion subsheaf of $E$ ,denoted by $T(E)$ which is defined as



for any affine $SpecA$ in $X$, define $ T(E)(SpecA)$:={$m in E(SpecA)|exists sin A$ with $s$ nonzero such that $s.m=0$}



we also have $(T(E))_x=T(E_x)$



$underline {Question}$:How do we show that $T(E)=T_{dim X-1}(E)$



I only know that $T(E)$ is a subsheaf of $E$ ,and I am supposed to show the following



$T(E)$ is a maximal subsheaf of dimension $leq dim(X)-1$.



I have no clue how to show (i) it has dimension $leq dim(X)-1$ and



(ii) It is maximal among all such subsheaves.



Any help from anyone is welcome.










share|cite|improve this question











$endgroup$












  • $begingroup$
    What do you mean by $dim E$?
    $endgroup$
    – Armando j18eos
    Jan 2 at 11:12










  • $begingroup$
    @Armandoj18eos $dim E=dim(Supp( E))$
    $endgroup$
    – HARRY
    Jan 2 at 13:11
















0












0








0


2



$begingroup$


$underline {Background}$:Let,$E$ be a coherent sheaf on a Noetherian,integral scheme $X$ and $dim E$=$dim X$.



Then we have the unique torsion filtration of that coherent sheaf as



$0subset T_0(E)subset....subset T_{dim X-1}(E) subset T_{dim X} (E)=E$



where,$T_i(E)$ is the maximal subsheaf of of $E$ of dimension $leq i$



we also have torsion subsheaf of $E$ ,denoted by $T(E)$ which is defined as



for any affine $SpecA$ in $X$, define $ T(E)(SpecA)$:={$m in E(SpecA)|exists sin A$ with $s$ nonzero such that $s.m=0$}



we also have $(T(E))_x=T(E_x)$



$underline {Question}$:How do we show that $T(E)=T_{dim X-1}(E)$



I only know that $T(E)$ is a subsheaf of $E$ ,and I am supposed to show the following



$T(E)$ is a maximal subsheaf of dimension $leq dim(X)-1$.



I have no clue how to show (i) it has dimension $leq dim(X)-1$ and



(ii) It is maximal among all such subsheaves.



Any help from anyone is welcome.










share|cite|improve this question











$endgroup$




$underline {Background}$:Let,$E$ be a coherent sheaf on a Noetherian,integral scheme $X$ and $dim E$=$dim X$.



Then we have the unique torsion filtration of that coherent sheaf as



$0subset T_0(E)subset....subset T_{dim X-1}(E) subset T_{dim X} (E)=E$



where,$T_i(E)$ is the maximal subsheaf of of $E$ of dimension $leq i$



we also have torsion subsheaf of $E$ ,denoted by $T(E)$ which is defined as



for any affine $SpecA$ in $X$, define $ T(E)(SpecA)$:={$m in E(SpecA)|exists sin A$ with $s$ nonzero such that $s.m=0$}



we also have $(T(E))_x=T(E_x)$



$underline {Question}$:How do we show that $T(E)=T_{dim X-1}(E)$



I only know that $T(E)$ is a subsheaf of $E$ ,and I am supposed to show the following



$T(E)$ is a maximal subsheaf of dimension $leq dim(X)-1$.



I have no clue how to show (i) it has dimension $leq dim(X)-1$ and



(ii) It is maximal among all such subsheaves.



Any help from anyone is welcome.







algebraic-geometry sheaf-theory coherent-sheaves






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share|cite|improve this question













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share|cite|improve this question








edited Jan 2 at 7:06









Henno Brandsma

114k348124




114k348124










asked Jan 2 at 6:50









HARRYHARRY

889




889












  • $begingroup$
    What do you mean by $dim E$?
    $endgroup$
    – Armando j18eos
    Jan 2 at 11:12










  • $begingroup$
    @Armandoj18eos $dim E=dim(Supp( E))$
    $endgroup$
    – HARRY
    Jan 2 at 13:11




















  • $begingroup$
    What do you mean by $dim E$?
    $endgroup$
    – Armando j18eos
    Jan 2 at 11:12










  • $begingroup$
    @Armandoj18eos $dim E=dim(Supp( E))$
    $endgroup$
    – HARRY
    Jan 2 at 13:11


















$begingroup$
What do you mean by $dim E$?
$endgroup$
– Armando j18eos
Jan 2 at 11:12




$begingroup$
What do you mean by $dim E$?
$endgroup$
– Armando j18eos
Jan 2 at 11:12












$begingroup$
@Armandoj18eos $dim E=dim(Supp( E))$
$endgroup$
– HARRY
Jan 2 at 13:11






$begingroup$
@Armandoj18eos $dim E=dim(Supp( E))$
$endgroup$
– HARRY
Jan 2 at 13:11












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