Writing As a Transformation of the Reciprocal Parent Function
0
$begingroup$
Write $y=frac{2}{3x-6}$ in the form $y=frac{k}{x-b}+c$
Supposedly simple, but how do you remove the coefficient of x in the denominator and get c? Thanks in advance.
functions
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
$endgroup$
add a comment |
0
$begingroup$
Write $y=frac{2}{3x-6}$ in the form $y=frac{k}{x-b}+c$
Supposedly simple, but how do you remove the coefficient of x in the denominator and get c? Thanks in advance.
functions
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
$endgroup$
$begingroup$
Take a factor of $3$ out of the denominator. $c$ may be zero.
$endgroup$
– George Coote
Dec 13 '18 at 11:33
$begingroup$
I still don't quite understand what the end result should be?
$endgroup$
– SolvingTrainee
Dec 13 '18 at 11:58
$begingroup$
It is awkwardly phrased. Write $frac 2 {3x - 6} = frac 2 {3(x - 2)} = frac {frac 2 3} {x - 2}$ then k, b, c = ?
$endgroup$
– George Coote
Dec 13 '18 at 12:06
add a comment |
0
0
0
$begingroup$
Write $y=frac{2}{3x-6}$ in the form $y=frac{k}{x-b}+c$
Supposedly simple, but how do you remove the coefficient of x in the denominator and get c? Thanks in advance.
functions
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
$endgroup$
Write $y=frac{2}{3x-6}$ in the form $y=frac{k}{x-b}+c$
Supposedly simple, but how do you remove the coefficient of x in the denominator and get c? Thanks in advance.
functions
functions
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
asked Dec 13 '18 at 11:21
SolvingTraineeSolvingTrainee
264
264
$begingroup$
Take a factor of $3$ out of the denominator. $c$ may be zero.
$endgroup$
– George Coote
Dec 13 '18 at 11:33
$begingroup$
I still don't quite understand what the end result should be?
$endgroup$
– SolvingTrainee
Dec 13 '18 at 11:58
$begingroup$
It is awkwardly phrased. Write $frac 2 {3x - 6} = frac 2 {3(x - 2)} = frac {frac 2 3} {x - 2}$ then k, b, c = ?
$endgroup$
– George Coote
Dec 13 '18 at 12:06
add a comment |
$begingroup$
Take a factor of $3$ out of the denominator. $c$ may be zero.
$endgroup$
– George Coote
Dec 13 '18 at 11:33
$begingroup$
I still don't quite understand what the end result should be?
$endgroup$
– SolvingTrainee
Dec 13 '18 at 11:58
$begingroup$
It is awkwardly phrased. Write $frac 2 {3x - 6} = frac 2 {3(x - 2)} = frac {frac 2 3} {x - 2}$ then k, b, c = ?
$endgroup$
– George Coote
Dec 13 '18 at 12:06
$begingroup$
Take a factor of $3$ out of the denominator. $c$ may be zero.
$endgroup$
– George Coote
Dec 13 '18 at 11:33
$begingroup$
Take a factor of $3$ out of the denominator. $c$ may be zero.
$endgroup$
– George Coote
Dec 13 '18 at 11:33
$begingroup$
I still don't quite understand what the end result should be?
$endgroup$
– SolvingTrainee
Dec 13 '18 at 11:58
$begingroup$
I still don't quite understand what the end result should be?
$endgroup$
– SolvingTrainee
Dec 13 '18 at 11:58
$begingroup$
It is awkwardly phrased. Write $frac 2 {3x - 6} = frac 2 {3(x - 2)} = frac {frac 2 3} {x - 2}$ then k, b, c = ?
$endgroup$
– George Coote
Dec 13 '18 at 12:06
$begingroup$
It is awkwardly phrased. Write $frac 2 {3x - 6} = frac 2 {3(x - 2)} = frac {frac 2 3} {x - 2}$ then k, b, c = ?
$endgroup$
– George Coote
Dec 13 '18 at 12:06
add a comment |
0
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$begingroup$
Take a factor of $3$ out of the denominator. $c$ may be zero.
$endgroup$
– George Coote
Dec 13 '18 at 11:33
$begingroup$
I still don't quite understand what the end result should be?
$endgroup$
– SolvingTrainee
Dec 13 '18 at 11:58
$begingroup$
It is awkwardly phrased. Write $frac 2 {3x - 6} = frac 2 {3(x - 2)} = frac {frac 2 3} {x - 2}$ then k, b, c = ?
$endgroup$
– George Coote
Dec 13 '18 at 12:06