Unable to execute the If condition in shell script












-2















I need to check if container is already present with specific name.
Using if statement for same, however container is present with same name but i am not sure why if statement is not running successfully.



if [`echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1`]
then
statements
else
statements


container with test name is present but its always going inside the else statement. Could you help me on this.










share|improve this question


















  • 3





    Possible duplicate of Why should there be a space after '[' and before ']' in Bash?

    – jww
    Nov 26 '18 at 9:28













  • Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.

    – jww
    Nov 26 '18 at 9:28
















-2















I need to check if container is already present with specific name.
Using if statement for same, however container is present with same name but i am not sure why if statement is not running successfully.



if [`echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1`]
then
statements
else
statements


container with test name is present but its always going inside the else statement. Could you help me on this.










share|improve this question


















  • 3





    Possible duplicate of Why should there be a space after '[' and before ']' in Bash?

    – jww
    Nov 26 '18 at 9:28













  • Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.

    – jww
    Nov 26 '18 at 9:28














-2












-2








-2








I need to check if container is already present with specific name.
Using if statement for same, however container is present with same name but i am not sure why if statement is not running successfully.



if [`echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1`]
then
statements
else
statements


container with test name is present but its always going inside the else statement. Could you help me on this.










share|improve this question














I need to check if container is already present with specific name.
Using if statement for same, however container is present with same name but i am not sure why if statement is not running successfully.



if [`echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1`]
then
statements
else
statements


container with test name is present but its always going inside the else statement. Could you help me on this.







linux bash shell shellexecute






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 26 '18 at 7:19









J.vikJ.vik

386




386








  • 3





    Possible duplicate of Why should there be a space after '[' and before ']' in Bash?

    – jww
    Nov 26 '18 at 9:28













  • Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.

    – jww
    Nov 26 '18 at 9:28














  • 3





    Possible duplicate of Why should there be a space after '[' and before ']' in Bash?

    – jww
    Nov 26 '18 at 9:28













  • Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.

    – jww
    Nov 26 '18 at 9:28








3




3





Possible duplicate of Why should there be a space after '[' and before ']' in Bash?

– jww
Nov 26 '18 at 9:28







Possible duplicate of Why should there be a space after '[' and before ']' in Bash?

– jww
Nov 26 '18 at 9:28















Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.

– jww
Nov 26 '18 at 9:28





Also see How to use Shellcheck, How to debug a bash script? (U&L.SE), How to debug a bash script? (SO), How to debug bash script? (AskU), Debugging Bash scripts, etc.

– jww
Nov 26 '18 at 9:28












2 Answers
2






active

oldest

votes


















0














in addition to @ÔHARA Kazutaka information.



-all does not exists, try --all instead.



The --quiet --filter name=test options are going to make docker filters output using the container's name, and make it prints to the standard output the CONTAINER ID if a container exists.



Give a try to this:



container_name=test

container_id=$(echo password | sudo -S docker ps --all --quiet --filter name="${container_name}")

if [ ! -z "${container_id}" ] ; then
printf "%s is the id of the container with name '%s'n" "${container_id}" "${container_name}"
else
printf "no docker container with name '%s' has been found.n" "${container_name}"
fi





share|improve this answer

































    2














    You need blanks between [, ] and `, i.e. :



    if [ `echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1` ]


    Also, you need fi after the last line.






    share|improve this answer
























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      in addition to @ÔHARA Kazutaka information.



      -all does not exists, try --all instead.



      The --quiet --filter name=test options are going to make docker filters output using the container's name, and make it prints to the standard output the CONTAINER ID if a container exists.



      Give a try to this:



      container_name=test

      container_id=$(echo password | sudo -S docker ps --all --quiet --filter name="${container_name}")

      if [ ! -z "${container_id}" ] ; then
      printf "%s is the id of the container with name '%s'n" "${container_id}" "${container_name}"
      else
      printf "no docker container with name '%s' has been found.n" "${container_name}"
      fi





      share|improve this answer






























        0














        in addition to @ÔHARA Kazutaka information.



        -all does not exists, try --all instead.



        The --quiet --filter name=test options are going to make docker filters output using the container's name, and make it prints to the standard output the CONTAINER ID if a container exists.



        Give a try to this:



        container_name=test

        container_id=$(echo password | sudo -S docker ps --all --quiet --filter name="${container_name}")

        if [ ! -z "${container_id}" ] ; then
        printf "%s is the id of the container with name '%s'n" "${container_id}" "${container_name}"
        else
        printf "no docker container with name '%s' has been found.n" "${container_name}"
        fi





        share|improve this answer




























          0












          0








          0







          in addition to @ÔHARA Kazutaka information.



          -all does not exists, try --all instead.



          The --quiet --filter name=test options are going to make docker filters output using the container's name, and make it prints to the standard output the CONTAINER ID if a container exists.



          Give a try to this:



          container_name=test

          container_id=$(echo password | sudo -S docker ps --all --quiet --filter name="${container_name}")

          if [ ! -z "${container_id}" ] ; then
          printf "%s is the id of the container with name '%s'n" "${container_id}" "${container_name}"
          else
          printf "no docker container with name '%s' has been found.n" "${container_name}"
          fi





          share|improve this answer















          in addition to @ÔHARA Kazutaka information.



          -all does not exists, try --all instead.



          The --quiet --filter name=test options are going to make docker filters output using the container's name, and make it prints to the standard output the CONTAINER ID if a container exists.



          Give a try to this:



          container_name=test

          container_id=$(echo password | sudo -S docker ps --all --quiet --filter name="${container_name}")

          if [ ! -z "${container_id}" ] ; then
          printf "%s is the id of the container with name '%s'n" "${container_id}" "${container_name}"
          else
          printf "no docker container with name '%s' has been found.n" "${container_name}"
          fi






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 26 '18 at 9:01

























          answered Nov 26 '18 at 8:50









          Jay jargotJay jargot

          1,9821511




          1,9821511

























              2














              You need blanks between [, ] and `, i.e. :



              if [ `echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1` ]


              Also, you need fi after the last line.






              share|improve this answer




























                2














                You need blanks between [, ] and `, i.e. :



                if [ `echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1` ]


                Also, you need fi after the last line.






                share|improve this answer


























                  2












                  2








                  2







                  You need blanks between [, ] and `, i.e. :



                  if [ `echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1` ]


                  Also, you need fi after the last line.






                  share|improve this answer













                  You need blanks between [, ] and `, i.e. :



                  if [ `echo password | sudo -S docker ps -all|grep test|cut -d' ' -f1` ]


                  Also, you need fi after the last line.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 26 '18 at 7:30









                  ŌHARA KazutakaŌHARA Kazutaka

                  767




                  767






























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