Excel Text to column
Does any of you know if exist any function to split the double brake line to column? I do know how to split by spaces like: =SUBSTITUTE(SUBSTITUTE(B2;CHAR(13);"");CHAR(10);"|"), but I want something like the image bellow:
excel vba excel-vba excel-formula
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
add a comment |
Does any of you know if exist any function to split the double brake line to column? I do know how to split by spaces like: =SUBSTITUTE(SUBSTITUTE(B2;CHAR(13);"");CHAR(10);"|"), but I want something like the image bellow:
excel vba excel-vba excel-formula
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
add a comment |
Does any of you know if exist any function to split the double brake line to column? I do know how to split by spaces like: =SUBSTITUTE(SUBSTITUTE(B2;CHAR(13);"");CHAR(10);"|"), but I want something like the image bellow:
excel vba excel-vba excel-formula
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
Does any of you know if exist any function to split the double brake line to column? I do know how to split by spaces like: =SUBSTITUTE(SUBSTITUTE(B2;CHAR(13);"");CHAR(10);"|"), but I want something like the image bellow:
excel vba excel-vba excel-formula
excel vba excel-vba excel-formula
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
edited Nov 26 '18 at 7:26
Pᴇʜ
23.6k62951
23.6k62951
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
asked Nov 24 '18 at 11:38
Baggelis KotsifakhsBaggelis Kotsifakhs
62
62
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The solution is depend on your string. If you have only one separation as shown, you can use following equations.
for the 1st part
=LEFT(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)-1)
for the 2nd part
=MID(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)+1,10000)
This is independent from the number of consecutive char(10) characters between text.
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
add a comment |
Just use two different formulas, there are many ways you could go about it. Say something like =LEFT(A1,FIND(CHAR(10),A1)) for the first column and =RIGHT(A1,LEN(A1)-SEARCH(CHAR(10),A1)) for the second one.
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The solution is depend on your string. If you have only one separation as shown, you can use following equations.
for the 1st part
=LEFT(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)-1)
for the 2nd part
=MID(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)+1,10000)
This is independent from the number of consecutive char(10) characters between text.
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
add a comment |
The solution is depend on your string. If you have only one separation as shown, you can use following equations.
for the 1st part
=LEFT(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)-1)
for the 2nd part
=MID(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)+1,10000)
This is independent from the number of consecutive char(10) characters between text.
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
add a comment |
The solution is depend on your string. If you have only one separation as shown, you can use following equations.
for the 1st part
=LEFT(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)-1)
for the 2nd part
=MID(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)+1,10000)
This is independent from the number of consecutive char(10) characters between text.
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
The solution is depend on your string. If you have only one separation as shown, you can use following equations.
for the 1st part
=LEFT(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)-1)
for the 2nd part
=MID(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)+1,10000)
This is independent from the number of consecutive char(10) characters between text.
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
edited Nov 26 '18 at 4:16
Forward Ed
6,76711337
6,76711337
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
answered Nov 24 '18 at 12:12
lighthouselklighthouselk
1015
1015
add a comment |
add a comment |
Just use two different formulas, there are many ways you could go about it. Say something like =LEFT(A1,FIND(CHAR(10),A1)) for the first column and =RIGHT(A1,LEN(A1)-SEARCH(CHAR(10),A1)) for the second one.
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
add a comment |
Just use two different formulas, there are many ways you could go about it. Say something like =LEFT(A1,FIND(CHAR(10),A1)) for the first column and =RIGHT(A1,LEN(A1)-SEARCH(CHAR(10),A1)) for the second one.
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
add a comment |
Just use two different formulas, there are many ways you could go about it. Say something like =LEFT(A1,FIND(CHAR(10),A1)) for the first column and =RIGHT(A1,LEN(A1)-SEARCH(CHAR(10),A1)) for the second one.
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
Just use two different formulas, there are many ways you could go about it. Say something like =LEFT(A1,FIND(CHAR(10),A1)) for the first column and =RIGHT(A1,LEN(A1)-SEARCH(CHAR(10),A1)) for the second one.
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
answered Nov 24 '18 at 11:55
Michal RosaMichal Rosa
1,3221814
1,3221814
add a comment |
add a comment |
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