8:1 multiplexer to 6:1 multiplexer
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I have 6 inputs that I want to insert in a 8-1 multiplexer. I just want to know how to modify the 8-1 mux to support only 6 inputs. I mean the last two rows on the truth table of the 8-1 won't be available.
This is the 8-1 mux I am using:
and its logic table:
I only want to use the D0 to D5 inputs.
multiplexer
edited Dec 12 '18 at 18:21
mike65535
1,0392719
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
$endgroup$
add a comment |
$begingroup$
I have 6 inputs that I want to insert in a 8-1 multiplexer. I just want to know how to modify the 8-1 mux to support only 6 inputs. I mean the last two rows on the truth table of the 8-1 won't be available.
This is the 8-1 mux I am using:
and its logic table:
I only want to use the D0 to D5 inputs.
multiplexer
edited Dec 12 '18 at 18:21
mike65535
1,0392719
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
$endgroup$
$begingroup$
Then ensure that your selection inputs only produces numbers in the range 000 to 101. Go stufy modulo arithmetic.
$endgroup$
– Andy aka
Dec 12 '18 at 15:36
1
$begingroup$
You might tie the top 3 inputs together, thus 101,110, and 111 produce the same output. Will this confuse your state machine?
$endgroup$
– analogsystemsrf
Dec 12 '18 at 15:49
2
$begingroup$
Nothing in the MUX should be modified. It's the S-inputs who define. The S>=6 should be don't cares.
$endgroup$
– Eugene Sh.
Dec 12 '18 at 15:50
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Instead of placing the enable on the inputs, perhaps you should put the enable on the output? Literally after the OR gate and before it forks into Y and Ỹ. Besides, are you sure that it is Y and Ỹ, shouldn't they be swapped?
$endgroup$
– Harry Svensson
Dec 12 '18 at 18:27
add a comment |
$begingroup$
I have 6 inputs that I want to insert in a 8-1 multiplexer. I just want to know how to modify the 8-1 mux to support only 6 inputs. I mean the last two rows on the truth table of the 8-1 won't be available.
This is the 8-1 mux I am using:
and its logic table:
I only want to use the D0 to D5 inputs.
multiplexer
edited Dec 12 '18 at 18:21
mike65535
1,0392719
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
$endgroup$
I have 6 inputs that I want to insert in a 8-1 multiplexer. I just want to know how to modify the 8-1 mux to support only 6 inputs. I mean the last two rows on the truth table of the 8-1 won't be available.
This is the 8-1 mux I am using:
and its logic table:
I only want to use the D0 to D5 inputs.
multiplexer
multiplexer
edited Dec 12 '18 at 18:21
mike65535
1,0392719
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
edited Dec 12 '18 at 18:21
mike65535
1,0392719
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
edited Dec 12 '18 at 18:21
mike65535
1,0392719
edited Dec 12 '18 at 18:21
mike65535
1,0392719
edited Dec 12 '18 at 18:21
mike65535
1,0392719
1,0392719
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
asked Dec 12 '18 at 15:27
zaiz2szaiz2s
211
211
$begingroup$
Then ensure that your selection inputs only produces numbers in the range 000 to 101. Go stufy modulo arithmetic.
$endgroup$
– Andy aka
Dec 12 '18 at 15:36
1
$begingroup$
You might tie the top 3 inputs together, thus 101,110, and 111 produce the same output. Will this confuse your state machine?
$endgroup$
– analogsystemsrf
Dec 12 '18 at 15:49
2
$begingroup$
Nothing in the MUX should be modified. It's the S-inputs who define. The S>=6 should be don't cares.
$endgroup$
– Eugene Sh.
Dec 12 '18 at 15:50
$begingroup$
Instead of placing the enable on the inputs, perhaps you should put the enable on the output? Literally after the OR gate and before it forks into Y and Ỹ. Besides, are you sure that it is Y and Ỹ, shouldn't they be swapped?
$endgroup$
– Harry Svensson
Dec 12 '18 at 18:27
add a comment |
$begingroup$
Then ensure that your selection inputs only produces numbers in the range 000 to 101. Go stufy modulo arithmetic.
$endgroup$
– Andy aka
Dec 12 '18 at 15:36
1
$begingroup$
You might tie the top 3 inputs together, thus 101,110, and 111 produce the same output. Will this confuse your state machine?
$endgroup$
– analogsystemsrf
Dec 12 '18 at 15:49
2
$begingroup$
Nothing in the MUX should be modified. It's the S-inputs who define. The S>=6 should be don't cares.
$endgroup$
– Eugene Sh.
Dec 12 '18 at 15:50
$begingroup$
Instead of placing the enable on the inputs, perhaps you should put the enable on the output? Literally after the OR gate and before it forks into Y and Ỹ. Besides, are you sure that it is Y and Ỹ, shouldn't they be swapped?
$endgroup$
– Harry Svensson
Dec 12 '18 at 18:27
$begingroup$
Then ensure that your selection inputs only produces numbers in the range 000 to 101. Go stufy modulo arithmetic.
$endgroup$
– Andy aka
Dec 12 '18 at 15:36
$begingroup$
Then ensure that your selection inputs only produces numbers in the range 000 to 101. Go stufy modulo arithmetic.
$endgroup$
– Andy aka
Dec 12 '18 at 15:36
1
1
$begingroup$
You might tie the top 3 inputs together, thus 101,110, and 111 produce the same output. Will this confuse your state machine?
$endgroup$
– analogsystemsrf
Dec 12 '18 at 15:49
$begingroup$
You might tie the top 3 inputs together, thus 101,110, and 111 produce the same output. Will this confuse your state machine?
$endgroup$
– analogsystemsrf
Dec 12 '18 at 15:49
2
2
$begingroup$
Nothing in the MUX should be modified. It's the S-inputs who define. The S>=6 should be don't cares.
$endgroup$
– Eugene Sh.
Dec 12 '18 at 15:50
$begingroup$
Nothing in the MUX should be modified. It's the S-inputs who define. The S>=6 should be don't cares.
$endgroup$
– Eugene Sh.
Dec 12 '18 at 15:50
$begingroup$
Instead of placing the enable on the inputs, perhaps you should put the enable on the output? Literally after the OR gate and before it forks into Y and Ỹ. Besides, are you sure that it is Y and Ỹ, shouldn't they be swapped?
$endgroup$
– Harry Svensson
Dec 12 '18 at 18:27
$begingroup$
Instead of placing the enable on the inputs, perhaps you should put the enable on the output? Literally after the OR gate and before it forks into Y and Ỹ. Besides, are you sure that it is Y and Ỹ, shouldn't they be swapped?
$endgroup$
– Harry Svensson
Dec 12 '18 at 18:27
add a comment |
1 Answer
1
active
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votes
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Assume that D6 and D7 are always low. Trace those signals through the gates in your design. If you find gates whose output values must always be the same, those gates can be removed and their output signals changed to a direct connection to logic '1' or '0'. Repeat until no gates are removed. Then remove unnecessary direct connections to logic '1' or '0'.
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
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$begingroup$
Assume that D6 and D7 are always low. Trace those signals through the gates in your design. If you find gates whose output values must always be the same, those gates can be removed and their output signals changed to a direct connection to logic '1' or '0'. Repeat until no gates are removed. Then remove unnecessary direct connections to logic '1' or '0'.
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
$endgroup$
add a comment |
$begingroup$
Assume that D6 and D7 are always low. Trace those signals through the gates in your design. If you find gates whose output values must always be the same, those gates can be removed and their output signals changed to a direct connection to logic '1' or '0'. Repeat until no gates are removed. Then remove unnecessary direct connections to logic '1' or '0'.
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
$endgroup$
add a comment |
$begingroup$
Assume that D6 and D7 are always low. Trace those signals through the gates in your design. If you find gates whose output values must always be the same, those gates can be removed and their output signals changed to a direct connection to logic '1' or '0'. Repeat until no gates are removed. Then remove unnecessary direct connections to logic '1' or '0'.
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
$endgroup$
Assume that D6 and D7 are always low. Trace those signals through the gates in your design. If you find gates whose output values must always be the same, those gates can be removed and their output signals changed to a direct connection to logic '1' or '0'. Repeat until no gates are removed. Then remove unnecessary direct connections to logic '1' or '0'.
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
answered Dec 12 '18 at 15:33
Elliot AldersonElliot Alderson
6,54511022
6,54511022
add a comment |
add a comment |
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$begingroup$
Then ensure that your selection inputs only produces numbers in the range 000 to 101. Go stufy modulo arithmetic.
$endgroup$
– Andy aka
Dec 12 '18 at 15:36
1
$begingroup$
You might tie the top 3 inputs together, thus 101,110, and 111 produce the same output. Will this confuse your state machine?
$endgroup$
– analogsystemsrf
Dec 12 '18 at 15:49
2
$begingroup$
Nothing in the MUX should be modified. It's the S-inputs who define. The S>=6 should be don't cares.
$endgroup$
– Eugene Sh.
Dec 12 '18 at 15:50
$begingroup$
Instead of placing the enable on the inputs, perhaps you should put the enable on the output? Literally after the OR gate and before it forks into Y and Ỹ. Besides, are you sure that it is Y and Ỹ, shouldn't they be swapped?
$endgroup$
– Harry Svensson
Dec 12 '18 at 18:27