file in python formatting

-3

So here is a file

APPLE: toronto, 2018, garden, tasty, 5

apple is a tasty fruit

>>>end 

Orange: japan, 32, home, sour, 1

orange is a sour fruit

>>>end

graEes: america, 24, organic, sweet, 4

grapes is a sweet fruit

>>>end

This is a file which also has new line characters.
I want tp create a dictionary using the file. it goes like this

the function is def f(file_to: (TextIO))-> Dict[str, List[tuple]]

file_to is file name entered and it will return the dictionary like,

{'apple': ['apple is a tasty fruit', 2018, 'garden', 'tasty', 5], orange:['orange is a sour fruit', 32,'home', 'sour',1] then grapes......}

each of the fruit is key and their discription is values as formatted there. Each fruits ends at >>>end

I tried

with open (file_to, "r") as myfile:

    data= myfile.readlines()

return data

it returns the file strings in a list with /n I'm thinking I can use strip() to remove that and get the element that comes before ':' as keys.

edited Nov 28 '18 at 17:07

asked Nov 23 '18 at 1:51

Comp

456

add a comment |

-3

So here is a file

APPLE: toronto, 2018, garden, tasty, 5

apple is a tasty fruit

>>>end 

Orange: japan, 32, home, sour, 1

orange is a sour fruit

>>>end

graEes: america, 24, organic, sweet, 4

grapes is a sweet fruit

>>>end

This is a file which also has new line characters.
I want tp create a dictionary using the file. it goes like this

the function is def f(file_to: (TextIO))-> Dict[str, List[tuple]]

file_to is file name entered and it will return the dictionary like,

{'apple': ['apple is a tasty fruit', 2018, 'garden', 'tasty', 5], orange:['orange is a sour fruit', 32,'home', 'sour',1] then grapes......}

each of the fruit is key and their discription is values as formatted there. Each fruits ends at >>>end

I tried

with open (file_to, "r") as myfile:

    data= myfile.readlines()

return data

it returns the file strings in a list with /n I'm thinking I can use strip() to remove that and get the element that comes before ':' as keys.

edited Nov 28 '18 at 17:07

asked Nov 23 '18 at 1:51

Comp

456

add a comment |

-3

So here is a file

APPLE: toronto, 2018, garden, tasty, 5

apple is a tasty fruit

>>>end 

Orange: japan, 32, home, sour, 1

orange is a sour fruit

>>>end

graEes: america, 24, organic, sweet, 4

grapes is a sweet fruit

>>>end

This is a file which also has new line characters.
I want tp create a dictionary using the file. it goes like this

the function is def f(file_to: (TextIO))-> Dict[str, List[tuple]]

file_to is file name entered and it will return the dictionary like,

{'apple': ['apple is a tasty fruit', 2018, 'garden', 'tasty', 5], orange:['orange is a sour fruit', 32,'home', 'sour',1] then grapes......}

each of the fruit is key and their discription is values as formatted there. Each fruits ends at >>>end

I tried

with open (file_to, "r") as myfile:

    data= myfile.readlines()

return data

it returns the file strings in a list with /n I'm thinking I can use strip() to remove that and get the element that comes before ':' as keys.

edited Nov 28 '18 at 17:07

asked Nov 23 '18 at 1:51

Comp

456

So here is a file

APPLE: toronto, 2018, garden, tasty, 5

apple is a tasty fruit

>>>end 

Orange: japan, 32, home, sour, 1

orange is a sour fruit

>>>end

graEes: america, 24, organic, sweet, 4

grapes is a sweet fruit

>>>end

This is a file which also has new line characters.
I want tp create a dictionary using the file. it goes like this

the function is def f(file_to: (TextIO))-> Dict[str, List[tuple]]

file_to is file name entered and it will return the dictionary like,

{'apple': ['apple is a tasty fruit', 2018, 'garden', 'tasty', 5], orange:['orange is a sour fruit', 32,'home', 'sour',1] then grapes......}

each of the fruit is key and their discription is values as formatted there. Each fruits ends at >>>end

I tried

with open (file_to, "r") as myfile:

    data= myfile.readlines()

return data

it returns the file strings in a list with /n I'm thinking I can use strip() to remove that and get the element that comes before ':' as keys.

python dictionary

edited Nov 28 '18 at 17:07

asked Nov 23 '18 at 1:51

Comp

456

edited Nov 28 '18 at 17:07

asked Nov 23 '18 at 1:51

Comp

456

edited Nov 28 '18 at 17:07

asked Nov 23 '18 at 1:51

Comp

456

asked Nov 23 '18 at 1:51

Comp

456

asked Nov 23 '18 at 1:51

Comp

456

add a comment |

1 Answer
1

active

oldest

votes

For this simple example, the following gives the results you want. (Although you probably misspelled grapes).

from pprint import pprint

import re



def main():

    fin = open('f1.txt', 'r')



    data = {}

    key = ''

    parsed = 

    for line in fin:

        line = line.rstrip()

        if line.startswith('>'):

            data[key] = parsed

            parsed = 

        elif ':' in line:

            parts = re.split('W+', line)

            key = parts[0].lower()

            parsed += parts[2:]

        else:

            parsed.insert(0, line)



    fin.close()

    pprint(data)





main()

edited Nov 23 '18 at 3:01

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

For this simple example, the following gives the results you want. (Although you probably misspelled grapes).

from pprint import pprint

import re



def main():

    fin = open('f1.txt', 'r')



    data = {}

    key = ''

    parsed = 

    for line in fin:

        line = line.rstrip()

        if line.startswith('>'):

            data[key] = parsed

            parsed = 

        elif ':' in line:

            parts = re.split('W+', line)

            key = parts[0].lower()

            parsed += parts[2:]

        else:

            parsed.insert(0, line)



    fin.close()

    pprint(data)





main()

edited Nov 23 '18 at 3:01

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

add a comment |

For this simple example, the following gives the results you want. (Although you probably misspelled grapes).

from pprint import pprint

import re



def main():

    fin = open('f1.txt', 'r')



    data = {}

    key = ''

    parsed = 

    for line in fin:

        line = line.rstrip()

        if line.startswith('>'):

            data[key] = parsed

            parsed = 

        elif ':' in line:

            parts = re.split('W+', line)

            key = parts[0].lower()

            parsed += parts[2:]

        else:

            parsed.insert(0, line)



    fin.close()

    pprint(data)





main()

edited Nov 23 '18 at 3:01

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

add a comment |

For this simple example, the following gives the results you want. (Although you probably misspelled grapes).

from pprint import pprint

import re



def main():

    fin = open('f1.txt', 'r')



    data = {}

    key = ''

    parsed = 

    for line in fin:

        line = line.rstrip()

        if line.startswith('>'):

            data[key] = parsed

            parsed = 

        elif ':' in line:

            parts = re.split('W+', line)

            key = parts[0].lower()

            parsed += parts[2:]

        else:

            parsed.insert(0, line)



    fin.close()

    pprint(data)





main()

edited Nov 23 '18 at 3:01

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

For this simple example, the following gives the results you want. (Although you probably misspelled grapes).

from pprint import pprint

import re



def main():

    fin = open('f1.txt', 'r')



    data = {}

    key = ''

    parsed = 

    for line in fin:

        line = line.rstrip()

        if line.startswith('>'):

            data[key] = parsed

            parsed = 

        elif ':' in line:

            parts = re.split('W+', line)

            key = parts[0].lower()

            parsed += parts[2:]

        else:

            parsed.insert(0, line)



    fin.close()

    pprint(data)





main()

edited Nov 23 '18 at 3:01

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

edited Nov 23 '18 at 3:01

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

answered Nov 23 '18 at 2:53

Chris Charley

3,68021618

add a comment |

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