Reflection on slice of pointers
I am trying to reflect a slice of pointers on a struct stored in an interface{}
I think I am doing ok until it's time to introspect the content on the pointed struct.
See the below example
package main
import (
"fmt"
"reflect"
)
type teststruct struct {
prop1 string
prop2 string
}
func main() {
test := teststruct{"test", "12"}
var container interface{}
var testcontainer *teststruct
testcontainer = append(testcontainer, &test)
container = testcontainer
rcontainer := reflect.ValueOf(container)
fmt.Println(rcontainer.Kind())
rtest := rcontainer.Index(0).Elem()
fmt.Println(rtest)
rteststruct := reflect.ValueOf(rtest)
fmt.Println(rteststruct.Kind())
typeOfT := rteststruct.Type()
for i := 0; i < rteststruct.NumField(); i++ {
f := rteststruct.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
}
Which results
slice
{test 12}
struct
0: typ *reflect.rtype = <*reflect.rtype Value>
1: ptr unsafe.Pointer = <unsafe.Pointer Value>
2: flag reflect.flag = <reflect.flag Value>
I am definitely missing something here, someone would be able to explain me what ?
pointers go reflection slice
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
add a comment |
I am trying to reflect a slice of pointers on a struct stored in an interface{}
I think I am doing ok until it's time to introspect the content on the pointed struct.
See the below example
package main
import (
"fmt"
"reflect"
)
type teststruct struct {
prop1 string
prop2 string
}
func main() {
test := teststruct{"test", "12"}
var container interface{}
var testcontainer *teststruct
testcontainer = append(testcontainer, &test)
container = testcontainer
rcontainer := reflect.ValueOf(container)
fmt.Println(rcontainer.Kind())
rtest := rcontainer.Index(0).Elem()
fmt.Println(rtest)
rteststruct := reflect.ValueOf(rtest)
fmt.Println(rteststruct.Kind())
typeOfT := rteststruct.Type()
for i := 0; i < rteststruct.NumField(); i++ {
f := rteststruct.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
}
Which results
slice
{test 12}
struct
0: typ *reflect.rtype = <*reflect.rtype Value>
1: ptr unsafe.Pointer = <unsafe.Pointer Value>
2: flag reflect.flag = <reflect.flag Value>
I am definitely missing something here, someone would be able to explain me what ?
pointers go reflection slice
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
add a comment |
I am trying to reflect a slice of pointers on a struct stored in an interface{}
I think I am doing ok until it's time to introspect the content on the pointed struct.
See the below example
package main
import (
"fmt"
"reflect"
)
type teststruct struct {
prop1 string
prop2 string
}
func main() {
test := teststruct{"test", "12"}
var container interface{}
var testcontainer *teststruct
testcontainer = append(testcontainer, &test)
container = testcontainer
rcontainer := reflect.ValueOf(container)
fmt.Println(rcontainer.Kind())
rtest := rcontainer.Index(0).Elem()
fmt.Println(rtest)
rteststruct := reflect.ValueOf(rtest)
fmt.Println(rteststruct.Kind())
typeOfT := rteststruct.Type()
for i := 0; i < rteststruct.NumField(); i++ {
f := rteststruct.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
}
Which results
slice
{test 12}
struct
0: typ *reflect.rtype = <*reflect.rtype Value>
1: ptr unsafe.Pointer = <unsafe.Pointer Value>
2: flag reflect.flag = <reflect.flag Value>
I am definitely missing something here, someone would be able to explain me what ?
pointers go reflection slice
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
I am trying to reflect a slice of pointers on a struct stored in an interface{}
I think I am doing ok until it's time to introspect the content on the pointed struct.
See the below example
package main
import (
"fmt"
"reflect"
)
type teststruct struct {
prop1 string
prop2 string
}
func main() {
test := teststruct{"test", "12"}
var container interface{}
var testcontainer *teststruct
testcontainer = append(testcontainer, &test)
container = testcontainer
rcontainer := reflect.ValueOf(container)
fmt.Println(rcontainer.Kind())
rtest := rcontainer.Index(0).Elem()
fmt.Println(rtest)
rteststruct := reflect.ValueOf(rtest)
fmt.Println(rteststruct.Kind())
typeOfT := rteststruct.Type()
for i := 0; i < rteststruct.NumField(); i++ {
f := rteststruct.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
}
Which results
slice
{test 12}
struct
0: typ *reflect.rtype = <*reflect.rtype Value>
1: ptr unsafe.Pointer = <unsafe.Pointer Value>
2: flag reflect.flag = <reflect.flag Value>
I am definitely missing something here, someone would be able to explain me what ?
pointers go reflection slice
pointers go reflection slice
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
edited Nov 23 '18 at 7:44
Flimzy
38.3k96597
38.3k96597
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
asked Nov 23 '18 at 1:36
Riwi KumabeRiwi Kumabe
132
132
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
rtest := rcontainer.Index(0).Elem() is already the value, so when you do this: rteststruct := reflect.ValueOf(rtest), you are actually getting a reflect.Value which is of course a struct.
Replace the end of your code with this:
typeOfT := rtest.Type()
for i := 0; i < rtest.NumField(); i++ {
f := rtest.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
Playground
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
Thank you for your help, I see now, my understanding of Elem() was wrong.
– Riwi Kumabe
Nov 23 '18 at 2:56
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
rtest := rcontainer.Index(0).Elem() is already the value, so when you do this: rteststruct := reflect.ValueOf(rtest), you are actually getting a reflect.Value which is of course a struct.
Replace the end of your code with this:
typeOfT := rtest.Type()
for i := 0; i < rtest.NumField(); i++ {
f := rtest.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
Playground
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
Thank you for your help, I see now, my understanding of Elem() was wrong.
– Riwi Kumabe
Nov 23 '18 at 2:56
add a comment |
rtest := rcontainer.Index(0).Elem() is already the value, so when you do this: rteststruct := reflect.ValueOf(rtest), you are actually getting a reflect.Value which is of course a struct.
Replace the end of your code with this:
typeOfT := rtest.Type()
for i := 0; i < rtest.NumField(); i++ {
f := rtest.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
Playground
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
Thank you for your help, I see now, my understanding of Elem() was wrong.
– Riwi Kumabe
Nov 23 '18 at 2:56
add a comment |
rtest := rcontainer.Index(0).Elem() is already the value, so when you do this: rteststruct := reflect.ValueOf(rtest), you are actually getting a reflect.Value which is of course a struct.
Replace the end of your code with this:
typeOfT := rtest.Type()
for i := 0; i < rtest.NumField(); i++ {
f := rtest.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
Playground
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
rtest := rcontainer.Index(0).Elem() is already the value, so when you do this: rteststruct := reflect.ValueOf(rtest), you are actually getting a reflect.Value which is of course a struct.
Replace the end of your code with this:
typeOfT := rtest.Type()
for i := 0; i < rtest.NumField(); i++ {
f := rtest.Field(i)
fmt.Printf("%d: %s %s = %vn", i, typeOfT.Field(i).Name, f.Type(), f.String())
}
Playground
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
answered Nov 23 '18 at 2:49
ssemillassemilla
3,087424
3,087424
Thank you for your help, I see now, my understanding of Elem() was wrong.
– Riwi Kumabe
Nov 23 '18 at 2:56
add a comment |
Thank you for your help, I see now, my understanding of Elem() was wrong.
– Riwi Kumabe
Nov 23 '18 at 2:56
Thank you for your help, I see now, my understanding of Elem() was wrong.
– Riwi Kumabe
Nov 23 '18 at 2:56
Thank you for your help, I see now, my understanding of Elem() was wrong.
– Riwi Kumabe
Nov 23 '18 at 2:56
add a comment |
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