How to make python count how many files are in a directory?

-1

Just by the title, you might think that this is a duplicate but it is not. I need to make my program count how many files with a specific ending such as .mp3 or .mp4 are in a directory. So if I have 10 .mp3 files in a directory I want my program to figure that out. After that, I need to list those files with numbers next to them so that the user can enter a number to launch that file. I need help with counting the files.

edited Nov 23 '18 at 2:16

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

1

Take a look at stackoverflow.com/questions/33635353/…

– KJH
Nov 23 '18 at 1:54

1

for file in glob.glob('/some/directory/*.mp3'):

– John Gordon
Nov 23 '18 at 1:57

Great for the first part but I still need help with the number part.

– Hrittik Chatterjee
Nov 23 '18 at 1:59

btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

– Hrittik Chatterjee
Nov 23 '18 at 2:17

Split the filename on the dot; feed the extensions into collections.Counter.

– wwii
Nov 23 '18 at 2:19

|
show 2 more comments

-1

edited Nov 23 '18 at 2:16

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

1

Take a look at stackoverflow.com/questions/33635353/…

– KJH
Nov 23 '18 at 1:54

1

for file in glob.glob('/some/directory/*.mp3'):

– John Gordon
Nov 23 '18 at 1:57

Great for the first part but I still need help with the number part.

– Hrittik Chatterjee
Nov 23 '18 at 1:59

btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

– Hrittik Chatterjee
Nov 23 '18 at 2:17

Split the filename on the dot; feed the extensions into collections.Counter.

– wwii
Nov 23 '18 at 2:19

|
show 2 more comments

-1

edited Nov 23 '18 at 2:16

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

python directory

edited Nov 23 '18 at 2:16

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

edited Nov 23 '18 at 2:16

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

edited Nov 23 '18 at 2:16

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

asked Nov 23 '18 at 1:51

Hrittik Chatterjee

1510

1

Take a look at stackoverflow.com/questions/33635353/…

– KJH
Nov 23 '18 at 1:54

1

for file in glob.glob('/some/directory/*.mp3'):

– John Gordon
Nov 23 '18 at 1:57

Great for the first part but I still need help with the number part.

– Hrittik Chatterjee
Nov 23 '18 at 1:59

btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

– Hrittik Chatterjee
Nov 23 '18 at 2:17

Split the filename on the dot; feed the extensions into collections.Counter.

– wwii
Nov 23 '18 at 2:19

|
show 2 more comments

1

Take a look at stackoverflow.com/questions/33635353/…

– KJH
Nov 23 '18 at 1:54

1

for file in glob.glob('/some/directory/*.mp3'):

– John Gordon
Nov 23 '18 at 1:57

Great for the first part but I still need help with the number part.

– Hrittik Chatterjee
Nov 23 '18 at 1:59

btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

– Hrittik Chatterjee
Nov 23 '18 at 2:17

Split the filename on the dot; feed the extensions into collections.Counter.

– wwii
Nov 23 '18 at 2:19

Take a look at stackoverflow.com/questions/33635353/…

– KJH
Nov 23 '18 at 1:54

for file in glob.glob('/some/directory/*.mp3'):

– John Gordon
Nov 23 '18 at 1:57

Great for the first part but I still need help with the number part.

– Hrittik Chatterjee
Nov 23 '18 at 1:59

btw I am taking KJH's answer if anyone is wondering. The sites posted provided clear answers.

– Hrittik Chatterjee
Nov 23 '18 at 2:17

Split the filename on the dot; feed the extensions into collections.Counter.

– wwii
Nov 23 '18 at 2:19

|
show 2 more comments

1 Answer
1

active

oldest

votes

import os 

i=0

x=

for file in os.listdir():

    if file.endswith('.mp3'):

        print(file)

        x.append(file)

        i+=1

print('the total number of files: ' +str(i))

fileNumber=input('enter number')

os.startfile(x[int(fileNumber)])

make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()

edited Nov 23 '18 at 2:45

answered Nov 23 '18 at 2:26

timmy

1348

I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29

Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30

you can use `os.startfile()'

– timmy
Nov 23 '18 at 2:34

do not worry i will edit my answer to complete your answer

– timmy
Nov 23 '18 at 2:35

i should note that programmers start count from 0

– timmy
Nov 23 '18 at 2:41

|
show 3 more comments

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

import os 

i=0

x=

for file in os.listdir():

    if file.endswith('.mp3'):

        print(file)

        x.append(file)

        i+=1

print('the total number of files: ' +str(i))

fileNumber=input('enter number')

os.startfile(x[int(fileNumber)])

make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()

edited Nov 23 '18 at 2:45

answered Nov 23 '18 at 2:26

timmy

1348

I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29

Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30

you can use `os.startfile()'

– timmy
Nov 23 '18 at 2:34

do not worry i will edit my answer to complete your answer

– timmy
Nov 23 '18 at 2:35

i should note that programmers start count from 0

– timmy
Nov 23 '18 at 2:41

|
show 3 more comments

import os 

i=0

x=

for file in os.listdir():

    if file.endswith('.mp3'):

        print(file)

        x.append(file)

        i+=1

print('the total number of files: ' +str(i))

fileNumber=input('enter number')

os.startfile(x[int(fileNumber)])

make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()

edited Nov 23 '18 at 2:45

answered Nov 23 '18 at 2:26

timmy

1348

I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29

Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30

you can use `os.startfile()'

– timmy
Nov 23 '18 at 2:34

do not worry i will edit my answer to complete your answer

– timmy
Nov 23 '18 at 2:35

i should note that programmers start count from 0

– timmy
Nov 23 '18 at 2:41

|
show 3 more comments

import os 

i=0

x=

for file in os.listdir():

    if file.endswith('.mp3'):

        print(file)

        x.append(file)

        i+=1

print('the total number of files: ' +str(i))

fileNumber=input('enter number')

os.startfile(x[int(fileNumber)])

make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()

edited Nov 23 '18 at 2:45

answered Nov 23 '18 at 2:26

timmy

1348

import os 

i=0

x=

for file in os.listdir():

    if file.endswith('.mp3'):

        print(file)

        x.append(file)

        i+=1

print('the total number of files: ' +str(i))

fileNumber=input('enter number')

os.startfile(x[int(fileNumber)])

make sure to use change directory to the folder location using os.chdir() or enter complete path in os.listdir()

edited Nov 23 '18 at 2:45

answered Nov 23 '18 at 2:26

timmy

1348

edited Nov 23 '18 at 2:45

answered Nov 23 '18 at 2:26

timmy

1348

answered Nov 23 '18 at 2:26

timmy

1348

answered Nov 23 '18 at 2:26

timmy

1348

I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29

Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30

you can use `os.startfile()'

– timmy
Nov 23 '18 at 2:34

do not worry i will edit my answer to complete your answer

– timmy
Nov 23 '18 at 2:35

i should note that programmers start count from 0

– timmy
Nov 23 '18 at 2:41

|
show 3 more comments

I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29

Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30

you can use `os.startfile()'

– timmy
Nov 23 '18 at 2:34

do not worry i will edit my answer to complete your answer

– timmy
Nov 23 '18 at 2:35

i should note that programmers start count from 0

– timmy
Nov 23 '18 at 2:41

I got that part the part I need help with now is adding numbers to each file and then print all the files out with those numbers. I need the numbering system so that each file is numbered in a way that a user can just enter 0 and the file labeled 0 will launch.

– Hrittik Chatterjee
Nov 23 '18 at 2:29

Also I cant ask any more questions apparently so if you guys could upvote this :)

– Hrittik Chatterjee
Nov 23 '18 at 2:30

you can use `os.startfile()'

– timmy
Nov 23 '18 at 2:34

do not worry i will edit my answer to complete your answer

– timmy
Nov 23 '18 at 2:35

i should note that programmers start count from 0

– timmy
Nov 23 '18 at 2:41

|
show 3 more comments

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