Evaluating a derivative in gp/pari












0














Specifically, I'm trying to evaluate the derivative of the Weierstrass P function at a specific point.



I know that I can set up a function like the following



p(z) = ellwp([1,I],z);



Which will allow me to input p(z), where z is a copmlex number, and have the output be the desired evaluation of the Weierstrass P function at z.



The problem is, I can't seem to do anything similar with the derivative. For example something like



p(z) = deriv(ellwp([1,I],z));



will return $0$ for any input $z$ (because pari is computing the value of the Weierstrass P function at z and then differentiating the resulting constant).



If there is any way this can be done, I would be grateful to hear about it.










share|cite|improve this question



























    0














    Specifically, I'm trying to evaluate the derivative of the Weierstrass P function at a specific point.



    I know that I can set up a function like the following



    p(z) = ellwp([1,I],z);



    Which will allow me to input p(z), where z is a copmlex number, and have the output be the desired evaluation of the Weierstrass P function at z.



    The problem is, I can't seem to do anything similar with the derivative. For example something like



    p(z) = deriv(ellwp([1,I],z));



    will return $0$ for any input $z$ (because pari is computing the value of the Weierstrass P function at z and then differentiating the resulting constant).



    If there is any way this can be done, I would be grateful to hear about it.










    share|cite|improve this question

























      0












      0








      0







      Specifically, I'm trying to evaluate the derivative of the Weierstrass P function at a specific point.



      I know that I can set up a function like the following



      p(z) = ellwp([1,I],z);



      Which will allow me to input p(z), where z is a copmlex number, and have the output be the desired evaluation of the Weierstrass P function at z.



      The problem is, I can't seem to do anything similar with the derivative. For example something like



      p(z) = deriv(ellwp([1,I],z));



      will return $0$ for any input $z$ (because pari is computing the value of the Weierstrass P function at z and then differentiating the resulting constant).



      If there is any way this can be done, I would be grateful to hear about it.










      share|cite|improve this question













      Specifically, I'm trying to evaluate the derivative of the Weierstrass P function at a specific point.



      I know that I can set up a function like the following



      p(z) = ellwp([1,I],z);



      Which will allow me to input p(z), where z is a copmlex number, and have the output be the desired evaluation of the Weierstrass P function at z.



      The problem is, I can't seem to do anything similar with the derivative. For example something like



      p(z) = deriv(ellwp([1,I],z));



      will return $0$ for any input $z$ (because pari is computing the value of the Weierstrass P function at z and then differentiating the resulting constant).



      If there is any way this can be done, I would be grateful to hear about it.







      power-series math-software elliptic-functions






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      asked Dec 3 '18 at 14:42









      JonHalesJonHales

      381211




      381211






















          1 Answer
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          2














          Look at the help:



          ? ?ellwp
          ellwp(w,{z='x},{flag=0}): computes the value at z of the Weierstrass P function
          attached to the lattice w, as given by ellperiods. Optional flag means 0
          (default), compute only P(z), 1 compute [P(z),P'(z)].


          So you can compute the function value and the derivative in one call



          ? ellwp([1,I], 1.2 + 2.1*I, 1)
          %1 = [12.28012262 - 15.62055727*I, -28.28677598 + 177.9634914*I]


          Now define the derivative dp(z) and get



          ? dp(z) = my{local a; a=ellwp([1,I],z,1); a[2]}
          %2 = (z)->mylocala;a=ellwp([1,I],z,1);a[2]
          ? dp(1.2+2.1*I)
          %3 = -28.28677598 + 177.9634914*I





          share|cite|improve this answer





















          • I knew it must be something simple, thank you very much.
            – JonHales
            Dec 3 '18 at 16:27











          Your Answer





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          1 Answer
          1






          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          Look at the help:



          ? ?ellwp
          ellwp(w,{z='x},{flag=0}): computes the value at z of the Weierstrass P function
          attached to the lattice w, as given by ellperiods. Optional flag means 0
          (default), compute only P(z), 1 compute [P(z),P'(z)].


          So you can compute the function value and the derivative in one call



          ? ellwp([1,I], 1.2 + 2.1*I, 1)
          %1 = [12.28012262 - 15.62055727*I, -28.28677598 + 177.9634914*I]


          Now define the derivative dp(z) and get



          ? dp(z) = my{local a; a=ellwp([1,I],z,1); a[2]}
          %2 = (z)->mylocala;a=ellwp([1,I],z,1);a[2]
          ? dp(1.2+2.1*I)
          %3 = -28.28677598 + 177.9634914*I





          share|cite|improve this answer





















          • I knew it must be something simple, thank you very much.
            – JonHales
            Dec 3 '18 at 16:27
















          2














          Look at the help:



          ? ?ellwp
          ellwp(w,{z='x},{flag=0}): computes the value at z of the Weierstrass P function
          attached to the lattice w, as given by ellperiods. Optional flag means 0
          (default), compute only P(z), 1 compute [P(z),P'(z)].


          So you can compute the function value and the derivative in one call



          ? ellwp([1,I], 1.2 + 2.1*I, 1)
          %1 = [12.28012262 - 15.62055727*I, -28.28677598 + 177.9634914*I]


          Now define the derivative dp(z) and get



          ? dp(z) = my{local a; a=ellwp([1,I],z,1); a[2]}
          %2 = (z)->mylocala;a=ellwp([1,I],z,1);a[2]
          ? dp(1.2+2.1*I)
          %3 = -28.28677598 + 177.9634914*I





          share|cite|improve this answer





















          • I knew it must be something simple, thank you very much.
            – JonHales
            Dec 3 '18 at 16:27














          2












          2








          2






          Look at the help:



          ? ?ellwp
          ellwp(w,{z='x},{flag=0}): computes the value at z of the Weierstrass P function
          attached to the lattice w, as given by ellperiods. Optional flag means 0
          (default), compute only P(z), 1 compute [P(z),P'(z)].


          So you can compute the function value and the derivative in one call



          ? ellwp([1,I], 1.2 + 2.1*I, 1)
          %1 = [12.28012262 - 15.62055727*I, -28.28677598 + 177.9634914*I]


          Now define the derivative dp(z) and get



          ? dp(z) = my{local a; a=ellwp([1,I],z,1); a[2]}
          %2 = (z)->mylocala;a=ellwp([1,I],z,1);a[2]
          ? dp(1.2+2.1*I)
          %3 = -28.28677598 + 177.9634914*I





          share|cite|improve this answer












          Look at the help:



          ? ?ellwp
          ellwp(w,{z='x},{flag=0}): computes the value at z of the Weierstrass P function
          attached to the lattice w, as given by ellperiods. Optional flag means 0
          (default), compute only P(z), 1 compute [P(z),P'(z)].


          So you can compute the function value and the derivative in one call



          ? ellwp([1,I], 1.2 + 2.1*I, 1)
          %1 = [12.28012262 - 15.62055727*I, -28.28677598 + 177.9634914*I]


          Now define the derivative dp(z) and get



          ? dp(z) = my{local a; a=ellwp([1,I],z,1); a[2]}
          %2 = (z)->mylocala;a=ellwp([1,I],z,1);a[2]
          ? dp(1.2+2.1*I)
          %3 = -28.28677598 + 177.9634914*I






          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 3 '18 at 16:00









          gammatestergammatester

          16.7k21632




          16.7k21632












          • I knew it must be something simple, thank you very much.
            – JonHales
            Dec 3 '18 at 16:27


















          • I knew it must be something simple, thank you very much.
            – JonHales
            Dec 3 '18 at 16:27
















          I knew it must be something simple, thank you very much.
          – JonHales
          Dec 3 '18 at 16:27




          I knew it must be something simple, thank you very much.
          – JonHales
          Dec 3 '18 at 16:27


















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