Simulating a sample path using continuous time markov chain












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I am trying to simulate a sample path using continuous time markov chain. This is what I've done:



set.seed(183427)
require(ECctmc)

# rates
r1 <- 1 # 1->2
r2 <- 0.75 # 2->3
r3 <- 0.5 # 3->1
r4 <- 0.5 # 3-> 2
Q <- matrix(c(-r1, r1, 0, 0, -r2, r2, r3, r4, -(r3+r4)),nrow = 3, byrow = TRUE)

# sample path
path <- sample_path(a=1, b = 3,t0=0, t1=5, Q=Q)


plot(stepfun(x=path[1:(nrow(path)-1),"time"], y = path[,"state"]), xlim = c(0,5), xlab = "Time", ylab = "State", main = "Sample path")


This works fine and I get a graph as an output where I have State on y axis and time on x-axis. However, in this case I have to specify my ending state b. I want to modify this code such that I don't have to specify the ending state and just give a rate matrix, initial distribution and the length of time interval T as an input. But I don't know how to do that. Help would be appreciated.










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    0














    I am trying to simulate a sample path using continuous time markov chain. This is what I've done:



    set.seed(183427)
    require(ECctmc)

    # rates
    r1 <- 1 # 1->2
    r2 <- 0.75 # 2->3
    r3 <- 0.5 # 3->1
    r4 <- 0.5 # 3-> 2
    Q <- matrix(c(-r1, r1, 0, 0, -r2, r2, r3, r4, -(r3+r4)),nrow = 3, byrow = TRUE)

    # sample path
    path <- sample_path(a=1, b = 3,t0=0, t1=5, Q=Q)


    plot(stepfun(x=path[1:(nrow(path)-1),"time"], y = path[,"state"]), xlim = c(0,5), xlab = "Time", ylab = "State", main = "Sample path")


    This works fine and I get a graph as an output where I have State on y axis and time on x-axis. However, in this case I have to specify my ending state b. I want to modify this code such that I don't have to specify the ending state and just give a rate matrix, initial distribution and the length of time interval T as an input. But I don't know how to do that. Help would be appreciated.










    share|improve this question



























      0












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      0







      I am trying to simulate a sample path using continuous time markov chain. This is what I've done:



      set.seed(183427)
      require(ECctmc)

      # rates
      r1 <- 1 # 1->2
      r2 <- 0.75 # 2->3
      r3 <- 0.5 # 3->1
      r4 <- 0.5 # 3-> 2
      Q <- matrix(c(-r1, r1, 0, 0, -r2, r2, r3, r4, -(r3+r4)),nrow = 3, byrow = TRUE)

      # sample path
      path <- sample_path(a=1, b = 3,t0=0, t1=5, Q=Q)


      plot(stepfun(x=path[1:(nrow(path)-1),"time"], y = path[,"state"]), xlim = c(0,5), xlab = "Time", ylab = "State", main = "Sample path")


      This works fine and I get a graph as an output where I have State on y axis and time on x-axis. However, in this case I have to specify my ending state b. I want to modify this code such that I don't have to specify the ending state and just give a rate matrix, initial distribution and the length of time interval T as an input. But I don't know how to do that. Help would be appreciated.










      share|improve this question















      I am trying to simulate a sample path using continuous time markov chain. This is what I've done:



      set.seed(183427)
      require(ECctmc)

      # rates
      r1 <- 1 # 1->2
      r2 <- 0.75 # 2->3
      r3 <- 0.5 # 3->1
      r4 <- 0.5 # 3-> 2
      Q <- matrix(c(-r1, r1, 0, 0, -r2, r2, r3, r4, -(r3+r4)),nrow = 3, byrow = TRUE)

      # sample path
      path <- sample_path(a=1, b = 3,t0=0, t1=5, Q=Q)


      plot(stepfun(x=path[1:(nrow(path)-1),"time"], y = path[,"state"]), xlim = c(0,5), xlab = "Time", ylab = "State", main = "Sample path")


      This works fine and I get a graph as an output where I have State on y axis and time on x-axis. However, in this case I have to specify my ending state b. I want to modify this code such that I don't have to specify the ending state and just give a rate matrix, initial distribution and the length of time interval T as an input. But I don't know how to do that. Help would be appreciated.







      r markov-chains






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      edited Dec 20 at 8:11









      Rohan Nadagouda

      439




      439










      asked Nov 20 at 19:25









      Shafa Haider

      468




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