I get strange results when I access the Sqlitedatabase with Unity C# via XAMPP
0
<?php
$servername = "localhost";
$username="root";
$password="";
$dbName="escape_room";
$user_username = $_POST['Input_user'];
$user_password = $_POST['Input_pass'];
$conn = new mysqli($servername, $username, $password, $dbName);
if(!$conn){
die("Cound not Connect: " . mysqli_connect_error());
}
$sql = "SELECT pass FROM escape_room WHERE user = '".$user_username."' ";
$result = mysqli_query($conn, $sql);
//Get the result and confirm login
if(mysqli_num_rows($result)>0){
while($row = mysqli_fetch_assoc($result)){
if($row['pass'] == $user_password){
echo "login success";
echo $row['pass'];
}else{
echo "password incorrect";
echo "password is =". $row['pass'];
}
}
}else{
echo "user not found";
echo "password is =". $row['pass'];}
I created a WWWForm in Unity C Script and tried to get the value of Mysqlitedatabase by running Login.php on server XAMPP. However, I could not confirm whether the IDs match or not. Only code written in html language will appear in console.
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">
<head>
<title>Object not found!</title>
...
What should I do?
Thank you for reading.
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
public string LoginUrI;
// Use this for initialization
void Start () {
LoginUrI = "localhost/escape_room/Login.php";
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
WWW webRequest = new WWW(LoginUrI, form);
yield return webRequest;
Debug.Log(webRequest.text);
}
public void CreateAccountBtn()
{
}
}
+Add)
[ This is what I have implemented in the Unity C script. I have an InputField and I used an AddField method to accept that inputField and pass it to php. In addition, I created a WWW object to allow access to Login.php through the server. At the end, I tested via Debug.Log to see how well the logged-in results would look good. ]
php sqlite unity3d login xampp
asked Nov 21 at 4:43
황인규
255
|
show 4 more comments
0
<?php
$servername = "localhost";
$username="root";
$password="";
$dbName="escape_room";
$user_username = $_POST['Input_user'];
$user_password = $_POST['Input_pass'];
$conn = new mysqli($servername, $username, $password, $dbName);
if(!$conn){
die("Cound not Connect: " . mysqli_connect_error());
}
$sql = "SELECT pass FROM escape_room WHERE user = '".$user_username."' ";
$result = mysqli_query($conn, $sql);
//Get the result and confirm login
if(mysqli_num_rows($result)>0){
while($row = mysqli_fetch_assoc($result)){
if($row['pass'] == $user_password){
echo "login success";
echo $row['pass'];
}else{
echo "password incorrect";
echo "password is =". $row['pass'];
}
}
}else{
echo "user not found";
echo "password is =". $row['pass'];}
I created a WWWForm in Unity C Script and tried to get the value of Mysqlitedatabase by running Login.php on server XAMPP. However, I could not confirm whether the IDs match or not. Only code written in html language will appear in console.
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">
<head>
<title>Object not found!</title>
...
What should I do?
Thank you for reading.
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
public string LoginUrI;
// Use this for initialization
void Start () {
LoginUrI = "localhost/escape_room/Login.php";
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
WWW webRequest = new WWW(LoginUrI, form);
yield return webRequest;
Debug.Log(webRequest.text);
}
public void CreateAccountBtn()
{
}
}
+Add)
[ This is what I have implemented in the Unity C script. I have an InputField and I used an AddField method to accept that inputField and pass it to php. In addition, I created a WWW object to allow access to Login.php through the server. At the end, I tested via Debug.Log to see how well the logged-in results would look good. ]
php sqlite unity3d login xampp
asked Nov 21 at 4:43
황인규
255
PHP file containing the code is not found by the server. You might be executing wrong url or file.
– Milind Singh
Nov 21 at 4:47
You should really consult a tutorial before proceeding with this project. User input direct to SQL is a red flag, as is plain text passwords. Also why iterate over the result set, isn't there only 1 user per username? If not that is a security problem as well because usernamejohncould be two people.
– user3783243
Nov 21 at 4:50
@user3783243 It has helped a lot. I've changed the code, can this be a better code? $numrows = mysql_num_rows($check); if ($numrows == 0) { die("ID does not exist. n"); }
– 황인규
Nov 21 at 5:01
You can't usemysql_functions withmysqli. Usemysqlieverywhere, you're going backwards many years if you go tomysql_
– user3783243
Nov 21 at 5:04
@MilindSingh In Unity I declare LoginUrI = 'localhost / escape_room / Login.php' as follows: Is this URL wrong?
– 황인규
Nov 21 at 5:05
|
show 4 more comments
0
0
0
<?php
$servername = "localhost";
$username="root";
$password="";
$dbName="escape_room";
$user_username = $_POST['Input_user'];
$user_password = $_POST['Input_pass'];
$conn = new mysqli($servername, $username, $password, $dbName);
if(!$conn){
die("Cound not Connect: " . mysqli_connect_error());
}
$sql = "SELECT pass FROM escape_room WHERE user = '".$user_username."' ";
$result = mysqli_query($conn, $sql);
//Get the result and confirm login
if(mysqli_num_rows($result)>0){
while($row = mysqli_fetch_assoc($result)){
if($row['pass'] == $user_password){
echo "login success";
echo $row['pass'];
}else{
echo "password incorrect";
echo "password is =". $row['pass'];
}
}
}else{
echo "user not found";
echo "password is =". $row['pass'];}
I created a WWWForm in Unity C Script and tried to get the value of Mysqlitedatabase by running Login.php on server XAMPP. However, I could not confirm whether the IDs match or not. Only code written in html language will appear in console.
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">
<head>
<title>Object not found!</title>
...
What should I do?
Thank you for reading.
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
public string LoginUrI;
// Use this for initialization
void Start () {
LoginUrI = "localhost/escape_room/Login.php";
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
WWW webRequest = new WWW(LoginUrI, form);
yield return webRequest;
Debug.Log(webRequest.text);
}
public void CreateAccountBtn()
{
}
}
+Add)
[ This is what I have implemented in the Unity C script. I have an InputField and I used an AddField method to accept that inputField and pass it to php. In addition, I created a WWW object to allow access to Login.php through the server. At the end, I tested via Debug.Log to see how well the logged-in results would look good. ]
php sqlite unity3d login xampp
asked Nov 21 at 4:43
황인규
255
<?php
$servername = "localhost";
$username="root";
$password="";
$dbName="escape_room";
$user_username = $_POST['Input_user'];
$user_password = $_POST['Input_pass'];
$conn = new mysqli($servername, $username, $password, $dbName);
if(!$conn){
die("Cound not Connect: " . mysqli_connect_error());
}
$sql = "SELECT pass FROM escape_room WHERE user = '".$user_username."' ";
$result = mysqli_query($conn, $sql);
//Get the result and confirm login
if(mysqli_num_rows($result)>0){
while($row = mysqli_fetch_assoc($result)){
if($row['pass'] == $user_password){
echo "login success";
echo $row['pass'];
}else{
echo "password incorrect";
echo "password is =". $row['pass'];
}
}
}else{
echo "user not found";
echo "password is =". $row['pass'];}
I created a WWWForm in Unity C Script and tried to get the value of Mysqlitedatabase by running Login.php on server XAMPP. However, I could not confirm whether the IDs match or not. Only code written in html language will appear in console.
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">
<head>
<title>Object not found!</title>
...
What should I do?
Thank you for reading.
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
public string LoginUrI;
// Use this for initialization
void Start () {
LoginUrI = "localhost/escape_room/Login.php";
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
WWW webRequest = new WWW(LoginUrI, form);
yield return webRequest;
Debug.Log(webRequest.text);
}
public void CreateAccountBtn()
{
}
}
+Add)
[ This is what I have implemented in the Unity C script. I have an InputField and I used an AddField method to accept that inputField and pass it to php. In addition, I created a WWW object to allow access to Login.php through the server. At the end, I tested via Debug.Log to see how well the logged-in results would look good. ]
php sqlite unity3d login xampp
php sqlite unity3d login xampp
asked Nov 21 at 4:43
황인규
255
asked Nov 21 at 4:43
황인규
255
edited Nov 21 at 6:09
asked Nov 21 at 4:43
황인규
255
asked Nov 21 at 4:43
황인규
255
asked Nov 21 at 4:43
황인규
255
255
PHP file containing the code is not found by the server. You might be executing wrong url or file.
– Milind Singh
Nov 21 at 4:47
You should really consult a tutorial before proceeding with this project. User input direct to SQL is a red flag, as is plain text passwords. Also why iterate over the result set, isn't there only 1 user per username? If not that is a security problem as well because usernamejohncould be two people.
– user3783243
Nov 21 at 4:50
@user3783243 It has helped a lot. I've changed the code, can this be a better code? $numrows = mysql_num_rows($check); if ($numrows == 0) { die("ID does not exist. n"); }
– 황인규
Nov 21 at 5:01
You can't usemysql_functions withmysqli. Usemysqlieverywhere, you're going backwards many years if you go tomysql_
– user3783243
Nov 21 at 5:04
@MilindSingh In Unity I declare LoginUrI = 'localhost / escape_room / Login.php' as follows: Is this URL wrong?
– 황인규
Nov 21 at 5:05
|
show 4 more comments
PHP file containing the code is not found by the server. You might be executing wrong url or file.
– Milind Singh
Nov 21 at 4:47
You should really consult a tutorial before proceeding with this project. User input direct to SQL is a red flag, as is plain text passwords. Also why iterate over the result set, isn't there only 1 user per username? If not that is a security problem as well because usernamejohncould be two people.
– user3783243
Nov 21 at 4:50
@user3783243 It has helped a lot. I've changed the code, can this be a better code? $numrows = mysql_num_rows($check); if ($numrows == 0) { die("ID does not exist. n"); }
– 황인규
Nov 21 at 5:01
You can't usemysql_functions withmysqli. Usemysqlieverywhere, you're going backwards many years if you go tomysql_
– user3783243
Nov 21 at 5:04
@MilindSingh In Unity I declare LoginUrI = 'localhost / escape_room / Login.php' as follows: Is this URL wrong?
– 황인규
Nov 21 at 5:05
PHP file containing the code is not found by the server. You might be executing wrong url or file.
– Milind Singh
Nov 21 at 4:47
PHP file containing the code is not found by the server. You might be executing wrong url or file.
– Milind Singh
Nov 21 at 4:47
You should really consult a tutorial before proceeding with this project. User input direct to SQL is a red flag, as is plain text passwords. Also why iterate over the result set, isn't there only 1 user per username? If not that is a security problem as well because username
john could be two people.– user3783243
Nov 21 at 4:50
You should really consult a tutorial before proceeding with this project. User input direct to SQL is a red flag, as is plain text passwords. Also why iterate over the result set, isn't there only 1 user per username? If not that is a security problem as well because username
john could be two people.– user3783243
Nov 21 at 4:50
@user3783243 It has helped a lot. I've changed the code, can this be a better code? $numrows = mysql_num_rows($check); if ($numrows == 0) { die("ID does not exist. n"); }
– 황인규
Nov 21 at 5:01
@user3783243 It has helped a lot. I've changed the code, can this be a better code? $numrows = mysql_num_rows($check); if ($numrows == 0) { die("ID does not exist. n"); }
– 황인규
Nov 21 at 5:01
You can't use
mysql_ functions with mysqli. Use mysqli everywhere, you're going backwards many years if you go to mysql_– user3783243
Nov 21 at 5:04
You can't use
mysql_ functions with mysqli. Use mysqli everywhere, you're going backwards many years if you go to mysql_– user3783243
Nov 21 at 5:04
@MilindSingh In Unity I declare LoginUrI = 'localhost / escape_room / Login.php' as follows: Is this URL wrong?
– 황인규
Nov 21 at 5:05
@MilindSingh In Unity I declare LoginUrI = 'localhost / escape_room / Login.php' as follows: Is this URL wrong?
– 황인규
Nov 21 at 5:05
|
show 4 more comments
1 Answer
1
active
oldest
votes
0
- confirm your path on xampp, to be sure that this is your directory path C:xampphtdocsescape_roomLogin.php
- You need to actually post the form from unity first, see code below
- Debug the php alone without sql to make sure you're getting the correct data. see code.
WWWform
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
using UnityEngine.Networking;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
string LoginUrI = "http://localhost/escape_room/login.php";
// Use this for initialization
void Start () {
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
// Make Post Request
using (var w = UnityWebRequest.Post(LoginUrI, form))
{
yield return w.SendWebRequest();
if (w.isNetworkError || w.isHttpError) {
Debug.Log(w.error);
}
else {
Debug.Log(w.downloadHandler.text);
}
}
}
public void CreateAccountBtn()
{
}
}
Test php code, replace you Login.php with this to make sure you get the values first.
<?php
if(isset($_POST) && !empty($_POST)){
echo "Successful post";
var_dump($_POST);
} else die("Error: post not successful");
?>
answered Nov 21 at 6:53
comphonia
42828
Generic / unknown HTTP error. I am using xampp's server, MySql, and I don't know why I get an error.
– 황인규
Nov 21 at 7:24
I use both too, not sure why, does it work for other things?
– comphonia
Nov 21 at 7:27
No. I only ran it on my laptop.
– 황인규
Nov 21 at 7:35
copy the new C# code, just tested it in unity and its working. the public string was messing it up, I also set it outside of Start()
– comphonia
Nov 21 at 7:41
you should see the results as a unity debug, without having to go to the browser, so you know its posted
– comphonia
Nov 21 at 7:45
|
show 2 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
- confirm your path on xampp, to be sure that this is your directory path C:xampphtdocsescape_roomLogin.php
- You need to actually post the form from unity first, see code below
- Debug the php alone without sql to make sure you're getting the correct data. see code.
WWWform
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
using UnityEngine.Networking;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
string LoginUrI = "http://localhost/escape_room/login.php";
// Use this for initialization
void Start () {
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
// Make Post Request
using (var w = UnityWebRequest.Post(LoginUrI, form))
{
yield return w.SendWebRequest();
if (w.isNetworkError || w.isHttpError) {
Debug.Log(w.error);
}
else {
Debug.Log(w.downloadHandler.text);
}
}
}
public void CreateAccountBtn()
{
}
}
Test php code, replace you Login.php with this to make sure you get the values first.
<?php
if(isset($_POST) && !empty($_POST)){
echo "Successful post";
var_dump($_POST);
} else die("Error: post not successful");
?>
answered Nov 21 at 6:53
comphonia
42828
Generic / unknown HTTP error. I am using xampp's server, MySql, and I don't know why I get an error.
– 황인규
Nov 21 at 7:24
I use both too, not sure why, does it work for other things?
– comphonia
Nov 21 at 7:27
No. I only ran it on my laptop.
– 황인규
Nov 21 at 7:35
copy the new C# code, just tested it in unity and its working. the public string was messing it up, I also set it outside of Start()
– comphonia
Nov 21 at 7:41
you should see the results as a unity debug, without having to go to the browser, so you know its posted
– comphonia
Nov 21 at 7:45
|
show 2 more comments
0
- confirm your path on xampp, to be sure that this is your directory path C:xampphtdocsescape_roomLogin.php
- You need to actually post the form from unity first, see code below
- Debug the php alone without sql to make sure you're getting the correct data. see code.
WWWform
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
using UnityEngine.Networking;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
string LoginUrI = "http://localhost/escape_room/login.php";
// Use this for initialization
void Start () {
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
// Make Post Request
using (var w = UnityWebRequest.Post(LoginUrI, form))
{
yield return w.SendWebRequest();
if (w.isNetworkError || w.isHttpError) {
Debug.Log(w.error);
}
else {
Debug.Log(w.downloadHandler.text);
}
}
}
public void CreateAccountBtn()
{
}
}
Test php code, replace you Login.php with this to make sure you get the values first.
<?php
if(isset($_POST) && !empty($_POST)){
echo "Successful post";
var_dump($_POST);
} else die("Error: post not successful");
?>
answered Nov 21 at 6:53
comphonia
42828
Generic / unknown HTTP error. I am using xampp's server, MySql, and I don't know why I get an error.
– 황인규
Nov 21 at 7:24
I use both too, not sure why, does it work for other things?
– comphonia
Nov 21 at 7:27
No. I only ran it on my laptop.
– 황인규
Nov 21 at 7:35
copy the new C# code, just tested it in unity and its working. the public string was messing it up, I also set it outside of Start()
– comphonia
Nov 21 at 7:41
you should see the results as a unity debug, without having to go to the browser, so you know its posted
– comphonia
Nov 21 at 7:45
|
show 2 more comments
0
0
0
- confirm your path on xampp, to be sure that this is your directory path C:xampphtdocsescape_roomLogin.php
- You need to actually post the form from unity first, see code below
- Debug the php alone without sql to make sure you're getting the correct data. see code.
WWWform
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
using UnityEngine.Networking;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
string LoginUrI = "http://localhost/escape_room/login.php";
// Use this for initialization
void Start () {
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
// Make Post Request
using (var w = UnityWebRequest.Post(LoginUrI, form))
{
yield return w.SendWebRequest();
if (w.isNetworkError || w.isHttpError) {
Debug.Log(w.error);
}
else {
Debug.Log(w.downloadHandler.text);
}
}
}
public void CreateAccountBtn()
{
}
}
Test php code, replace you Login.php with this to make sure you get the values first.
<?php
if(isset($_POST) && !empty($_POST)){
echo "Successful post";
var_dump($_POST);
} else die("Error: post not successful");
?>
answered Nov 21 at 6:53
comphonia
42828
- confirm your path on xampp, to be sure that this is your directory path C:xampphtdocsescape_roomLogin.php
- You need to actually post the form from unity first, see code below
- Debug the php alone without sql to make sure you're getting the correct data. see code.
WWWform
using System.Collections;
using System.Collections.Generic;
using UnityEngine.UI;
using UnityEngine;
using UnityEngine.Networking;
public class gamemanager : MonoBehaviour {
[Header("LoginPanel")]
public InputField ID;
public InputField PW;
[Header("CreateAccountPanel")]
public InputField New_ID;
public InputField New_PW;
string LoginUrI = "http://localhost/escape_room/login.php";
// Use this for initialization
void Start () {
}
public void LoginBtn()
{
StartCoroutine(LoginToDB(ID, PW));
}
IEnumerator LoginToDB(InputField username, InputField password)
{
Debug.Log(username.text);
Debug.Log(password.text);
WWWForm form = new WWWForm();
form.AddField("Input_user", username.text);
form.AddField("Input_pass", password.text);
// Make Post Request
using (var w = UnityWebRequest.Post(LoginUrI, form))
{
yield return w.SendWebRequest();
if (w.isNetworkError || w.isHttpError) {
Debug.Log(w.error);
}
else {
Debug.Log(w.downloadHandler.text);
}
}
}
public void CreateAccountBtn()
{
}
}
Test php code, replace you Login.php with this to make sure you get the values first.
<?php
if(isset($_POST) && !empty($_POST)){
echo "Successful post";
var_dump($_POST);
} else die("Error: post not successful");
?>
answered Nov 21 at 6:53
comphonia
42828
edited Nov 21 at 7:40
answered Nov 21 at 6:53
comphonia
42828
answered Nov 21 at 6:53
comphonia
42828
answered Nov 21 at 6:53
comphonia
42828
42828
Generic / unknown HTTP error. I am using xampp's server, MySql, and I don't know why I get an error.
– 황인규
Nov 21 at 7:24
I use both too, not sure why, does it work for other things?
– comphonia
Nov 21 at 7:27
No. I only ran it on my laptop.
– 황인규
Nov 21 at 7:35
copy the new C# code, just tested it in unity and its working. the public string was messing it up, I also set it outside of Start()
– comphonia
Nov 21 at 7:41
you should see the results as a unity debug, without having to go to the browser, so you know its posted
– comphonia
Nov 21 at 7:45
|
show 2 more comments
Generic / unknown HTTP error. I am using xampp's server, MySql, and I don't know why I get an error.
– 황인규
Nov 21 at 7:24
I use both too, not sure why, does it work for other things?
– comphonia
Nov 21 at 7:27
No. I only ran it on my laptop.
– 황인규
Nov 21 at 7:35
copy the new C# code, just tested it in unity and its working. the public string was messing it up, I also set it outside of Start()
– comphonia
Nov 21 at 7:41
you should see the results as a unity debug, without having to go to the browser, so you know its posted
– comphonia
Nov 21 at 7:45
Generic / unknown HTTP error. I am using xampp's server, MySql, and I don't know why I get an error.
– 황인규
Nov 21 at 7:24
Generic / unknown HTTP error. I am using xampp's server, MySql, and I don't know why I get an error.
– 황인규
Nov 21 at 7:24
I use both too, not sure why, does it work for other things?
– comphonia
Nov 21 at 7:27
I use both too, not sure why, does it work for other things?
– comphonia
Nov 21 at 7:27
No. I only ran it on my laptop.
– 황인규
Nov 21 at 7:35
No. I only ran it on my laptop.
– 황인규
Nov 21 at 7:35
copy the new C# code, just tested it in unity and its working. the public string was messing it up, I also set it outside of Start()
– comphonia
Nov 21 at 7:41
copy the new C# code, just tested it in unity and its working. the public string was messing it up, I also set it outside of Start()
– comphonia
Nov 21 at 7:41
you should see the results as a unity debug, without having to go to the browser, so you know its posted
– comphonia
Nov 21 at 7:45
you should see the results as a unity debug, without having to go to the browser, so you know its posted
– comphonia
Nov 21 at 7:45
|
show 2 more comments
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PHP file containing the code is not found by the server. You might be executing wrong url or file.
– Milind Singh
Nov 21 at 4:47
You should really consult a tutorial before proceeding with this project. User input direct to SQL is a red flag, as is plain text passwords. Also why iterate over the result set, isn't there only 1 user per username? If not that is a security problem as well because username
johncould be two people.– user3783243
Nov 21 at 4:50
@user3783243 It has helped a lot. I've changed the code, can this be a better code? $numrows = mysql_num_rows($check); if ($numrows == 0) { die("ID does not exist. n"); }
– 황인규
Nov 21 at 5:01
You can't use
mysql_functions withmysqli. Usemysqlieverywhere, you're going backwards many years if you go tomysql_– user3783243
Nov 21 at 5:04
@MilindSingh In Unity I declare LoginUrI = 'localhost / escape_room / Login.php' as follows: Is this URL wrong?
– 황인규
Nov 21 at 5:05