Tikz: Zero-padding node labels?
I define an array in the following way:
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathtruncatemacro{nodelabel}{x + y*n}
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
How can can I zero-pad the node labels such that I get c001
, c010
etc.?
tikz-pgf labels
add a comment |
I define an array in the following way:
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathtruncatemacro{nodelabel}{x + y*n}
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
How can can I zero-pad the node labels such that I get c001
, c010
etc.?
tikz-pgf labels
node at (x,y) (x) {c0nodelabel};
?
– marmot
Nov 30 at 14:32
1
Welcome to TeX.se. For your future questions, please don't post code fragments. Instead put them into complete compilable documents as I did in my answer. This makes it a lot easier for people to help you.
– Alan Munn
Nov 30 at 15:14
add a comment |
I define an array in the following way:
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathtruncatemacro{nodelabel}{x + y*n}
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
How can can I zero-pad the node labels such that I get c001
, c010
etc.?
tikz-pgf labels
I define an array in the following way:
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathtruncatemacro{nodelabel}{x + y*n}
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
How can can I zero-pad the node labels such that I get c001
, c010
etc.?
tikz-pgf labels
tikz-pgf labels
asked Nov 30 at 14:08
loris
284
284
node at (x,y) (x) {c0nodelabel};
?
– marmot
Nov 30 at 14:32
1
Welcome to TeX.se. For your future questions, please don't post code fragments. Instead put them into complete compilable documents as I did in my answer. This makes it a lot easier for people to help you.
– Alan Munn
Nov 30 at 15:14
add a comment |
node at (x,y) (x) {c0nodelabel};
?
– marmot
Nov 30 at 14:32
1
Welcome to TeX.se. For your future questions, please don't post code fragments. Instead put them into complete compilable documents as I did in my answer. This makes it a lot easier for people to help you.
– Alan Munn
Nov 30 at 15:14
node at (x,y) (x) {c0nodelabel};
?– marmot
Nov 30 at 14:32
node at (x,y) (x) {c0nodelabel};
?– marmot
Nov 30 at 14:32
1
1
Welcome to TeX.se. For your future questions, please don't post code fragments. Instead put them into complete compilable documents as I did in my answer. This makes it a lot easier for people to help you.
– Alan Munn
Nov 30 at 15:14
Welcome to TeX.se. For your future questions, please don't post code fragments. Instead put them into complete compilable documents as I did in my answer. This makes it a lot easier for people to help you.
– Alan Munn
Nov 30 at 15:14
add a comment |
3 Answers
3
active
oldest
votes
Another solution with siuntix
:
documentclass{article}
usepackage{siunitx}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y [evaluate=y as ni using {int(x+y*n)}] in {0,...,pgfmathresult} {
node at (x,y) {cnum[minimum-integer-digits=3]{ni}};
}
}
end{tikzpicture}
end{document}
add a comment |
Adapting the PGF answer given here: How to output a counter with leading zeros? we can use the same approach with your example. Instead of using pgfmathtruncatemacro
I've use pgfmathsetcounter
and then used the base conversion to pad the zeros.
documentclass{article}
usepackage{tikz}
newcounter{nodelabel}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathsetbasenumberlength{3}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathsetcounter{nodelabel}{x + y*n}
pgfmathbasetodecnodelabel{thevalue{nodelabel}}{10}%
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
end{document}
add a comment |
Update:
I may have misunderstood the question, because labels can be written naturally like this:
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {c0yx};
}
}
end{tikzpicture}
end{document}
Old answer:
You can use the macro opprint
from the xlop
package that prints the numbers as they are written useless zeros included.
For example 00000.000
will be written 00000.000
documentclass{article}
usepackage{tikz}
usepackage{xlop}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {copprint{0yx}};
}
}
end{tikzpicture}
end{document}
In fact I actually needc001
toc100
, so I went for Alan's first solution, as this is more general.
– loris
Dec 3 at 8:53
@loris You accepted Ignasi's answer, not Alan's. Is that a mistake on your part?
– AndréC
Dec 3 at 13:48
I subsequently switched to the Ignasi's solution because it avoids having to define a counter. I'm writing LaTeX blocks within an Orgmode file, so usingnum[minimum-integer-digits=3]
seemed slightly more self-contained. However, I have other arrays of labels to draw with different dimensions, but with continuous numbering across all arrays, so I may well need the counter after all.
– loris
Dec 4 at 9:25
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Another solution with siuntix
:
documentclass{article}
usepackage{siunitx}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y [evaluate=y as ni using {int(x+y*n)}] in {0,...,pgfmathresult} {
node at (x,y) {cnum[minimum-integer-digits=3]{ni}};
}
}
end{tikzpicture}
end{document}
add a comment |
Another solution with siuntix
:
documentclass{article}
usepackage{siunitx}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y [evaluate=y as ni using {int(x+y*n)}] in {0,...,pgfmathresult} {
node at (x,y) {cnum[minimum-integer-digits=3]{ni}};
}
}
end{tikzpicture}
end{document}
add a comment |
Another solution with siuntix
:
documentclass{article}
usepackage{siunitx}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y [evaluate=y as ni using {int(x+y*n)}] in {0,...,pgfmathresult} {
node at (x,y) {cnum[minimum-integer-digits=3]{ni}};
}
}
end{tikzpicture}
end{document}
Another solution with siuntix
:
documentclass{article}
usepackage{siunitx}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y [evaluate=y as ni using {int(x+y*n)}] in {0,...,pgfmathresult} {
node at (x,y) {cnum[minimum-integer-digits=3]{ni}};
}
}
end{tikzpicture}
end{document}
answered Nov 30 at 18:24
Ignasi
91.6k4165303
91.6k4165303
add a comment |
add a comment |
Adapting the PGF answer given here: How to output a counter with leading zeros? we can use the same approach with your example. Instead of using pgfmathtruncatemacro
I've use pgfmathsetcounter
and then used the base conversion to pad the zeros.
documentclass{article}
usepackage{tikz}
newcounter{nodelabel}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathsetbasenumberlength{3}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathsetcounter{nodelabel}{x + y*n}
pgfmathbasetodecnodelabel{thevalue{nodelabel}}{10}%
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
end{document}
add a comment |
Adapting the PGF answer given here: How to output a counter with leading zeros? we can use the same approach with your example. Instead of using pgfmathtruncatemacro
I've use pgfmathsetcounter
and then used the base conversion to pad the zeros.
documentclass{article}
usepackage{tikz}
newcounter{nodelabel}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathsetbasenumberlength{3}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathsetcounter{nodelabel}{x + y*n}
pgfmathbasetodecnodelabel{thevalue{nodelabel}}{10}%
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
end{document}
add a comment |
Adapting the PGF answer given here: How to output a counter with leading zeros? we can use the same approach with your example. Instead of using pgfmathtruncatemacro
I've use pgfmathsetcounter
and then used the base conversion to pad the zeros.
documentclass{article}
usepackage{tikz}
newcounter{nodelabel}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathsetbasenumberlength{3}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathsetcounter{nodelabel}{x + y*n}
pgfmathbasetodecnodelabel{thevalue{nodelabel}}{10}%
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
end{document}
Adapting the PGF answer given here: How to output a counter with leading zeros? we can use the same approach with your example. Instead of using pgfmathtruncatemacro
I've use pgfmathsetcounter
and then used the base conversion to pad the zeros.
documentclass{article}
usepackage{tikz}
newcounter{nodelabel}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathsetbasenumberlength{3}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
pgfmathsetcounter{nodelabel}{x + y*n}
pgfmathbasetodecnodelabel{thevalue{nodelabel}}{10}%
node at (x,y) (x) {cnodelabel};
}
}
end{tikzpicture}
end{document}
answered Nov 30 at 14:33
Alan Munn
158k27425699
158k27425699
add a comment |
add a comment |
Update:
I may have misunderstood the question, because labels can be written naturally like this:
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {c0yx};
}
}
end{tikzpicture}
end{document}
Old answer:
You can use the macro opprint
from the xlop
package that prints the numbers as they are written useless zeros included.
For example 00000.000
will be written 00000.000
documentclass{article}
usepackage{tikz}
usepackage{xlop}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {copprint{0yx}};
}
}
end{tikzpicture}
end{document}
In fact I actually needc001
toc100
, so I went for Alan's first solution, as this is more general.
– loris
Dec 3 at 8:53
@loris You accepted Ignasi's answer, not Alan's. Is that a mistake on your part?
– AndréC
Dec 3 at 13:48
I subsequently switched to the Ignasi's solution because it avoids having to define a counter. I'm writing LaTeX blocks within an Orgmode file, so usingnum[minimum-integer-digits=3]
seemed slightly more self-contained. However, I have other arrays of labels to draw with different dimensions, but with continuous numbering across all arrays, so I may well need the counter after all.
– loris
Dec 4 at 9:25
add a comment |
Update:
I may have misunderstood the question, because labels can be written naturally like this:
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {c0yx};
}
}
end{tikzpicture}
end{document}
Old answer:
You can use the macro opprint
from the xlop
package that prints the numbers as they are written useless zeros included.
For example 00000.000
will be written 00000.000
documentclass{article}
usepackage{tikz}
usepackage{xlop}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {copprint{0yx}};
}
}
end{tikzpicture}
end{document}
In fact I actually needc001
toc100
, so I went for Alan's first solution, as this is more general.
– loris
Dec 3 at 8:53
@loris You accepted Ignasi's answer, not Alan's. Is that a mistake on your part?
– AndréC
Dec 3 at 13:48
I subsequently switched to the Ignasi's solution because it avoids having to define a counter. I'm writing LaTeX blocks within an Orgmode file, so usingnum[minimum-integer-digits=3]
seemed slightly more self-contained. However, I have other arrays of labels to draw with different dimensions, but with continuous numbering across all arrays, so I may well need the counter after all.
– loris
Dec 4 at 9:25
add a comment |
Update:
I may have misunderstood the question, because labels can be written naturally like this:
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {c0yx};
}
}
end{tikzpicture}
end{document}
Old answer:
You can use the macro opprint
from the xlop
package that prints the numbers as they are written useless zeros included.
For example 00000.000
will be written 00000.000
documentclass{article}
usepackage{tikz}
usepackage{xlop}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {copprint{0yx}};
}
}
end{tikzpicture}
end{document}
Update:
I may have misunderstood the question, because labels can be written naturally like this:
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {c0yx};
}
}
end{tikzpicture}
end{document}
Old answer:
You can use the macro opprint
from the xlop
package that prints the numbers as they are written useless zeros included.
For example 00000.000
will be written 00000.000
documentclass{article}
usepackage{tikz}
usepackage{xlop}
begin{document}
begin{tikzpicture}
defn{10}
pgfmathparse{int(n-1)}
foreach x in {0,...,pgfmathresult} {
foreach y in {0,...,pgfmathresult} {
node at (x,y) (x) {copprint{0yx}};
}
}
end{tikzpicture}
end{document}
edited Nov 30 at 19:20
answered Nov 30 at 19:10
AndréC
7,59511440
7,59511440
In fact I actually needc001
toc100
, so I went for Alan's first solution, as this is more general.
– loris
Dec 3 at 8:53
@loris You accepted Ignasi's answer, not Alan's. Is that a mistake on your part?
– AndréC
Dec 3 at 13:48
I subsequently switched to the Ignasi's solution because it avoids having to define a counter. I'm writing LaTeX blocks within an Orgmode file, so usingnum[minimum-integer-digits=3]
seemed slightly more self-contained. However, I have other arrays of labels to draw with different dimensions, but with continuous numbering across all arrays, so I may well need the counter after all.
– loris
Dec 4 at 9:25
add a comment |
In fact I actually needc001
toc100
, so I went for Alan's first solution, as this is more general.
– loris
Dec 3 at 8:53
@loris You accepted Ignasi's answer, not Alan's. Is that a mistake on your part?
– AndréC
Dec 3 at 13:48
I subsequently switched to the Ignasi's solution because it avoids having to define a counter. I'm writing LaTeX blocks within an Orgmode file, so usingnum[minimum-integer-digits=3]
seemed slightly more self-contained. However, I have other arrays of labels to draw with different dimensions, but with continuous numbering across all arrays, so I may well need the counter after all.
– loris
Dec 4 at 9:25
In fact I actually need
c001
to c100
, so I went for Alan's first solution, as this is more general.– loris
Dec 3 at 8:53
In fact I actually need
c001
to c100
, so I went for Alan's first solution, as this is more general.– loris
Dec 3 at 8:53
@loris You accepted Ignasi's answer, not Alan's. Is that a mistake on your part?
– AndréC
Dec 3 at 13:48
@loris You accepted Ignasi's answer, not Alan's. Is that a mistake on your part?
– AndréC
Dec 3 at 13:48
I subsequently switched to the Ignasi's solution because it avoids having to define a counter. I'm writing LaTeX blocks within an Orgmode file, so using
num[minimum-integer-digits=3]
seemed slightly more self-contained. However, I have other arrays of labels to draw with different dimensions, but with continuous numbering across all arrays, so I may well need the counter after all.– loris
Dec 4 at 9:25
I subsequently switched to the Ignasi's solution because it avoids having to define a counter. I'm writing LaTeX blocks within an Orgmode file, so using
num[minimum-integer-digits=3]
seemed slightly more self-contained. However, I have other arrays of labels to draw with different dimensions, but with continuous numbering across all arrays, so I may well need the counter after all.– loris
Dec 4 at 9:25
add a comment |
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node at (x,y) (x) {c0nodelabel};
?– marmot
Nov 30 at 14:32
1
Welcome to TeX.se. For your future questions, please don't post code fragments. Instead put them into complete compilable documents as I did in my answer. This makes it a lot easier for people to help you.
– Alan Munn
Nov 30 at 15:14