What is the distribution of $aX$ when $X$ is Gumbel? What is the distribution of $-X$ when $X$ is Gumbel?












1












$begingroup$


If $X$ is a random variable distributed as a Gumbel with location $gamma$ and scale $1$ (where $gamma$ is the Euler constant)



[Hence the mean is
$$
gamma-1timesgamma=0
$$

and the variance is
$$
pi^2/6times 1^2=pi^2/6
$$
]



(1) What is the distribution of $aX$ where $ain mathbb{R}$? $a$ should be $>0$?



(2) What is the distribution of $-X$?



I don't know if it is relevant, but here I'm using the definition of Gumbel as in Mathworld and Matlab (sign flipped with respect to the definition of Gumbel in Wikipedia)










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$endgroup$












  • $begingroup$
    Please show us what you have tried so far.
    $endgroup$
    – Stockfish
    Dec 14 '18 at 12:14










  • $begingroup$
    (1) I think that $aX$ is Gumbel with location $gamma$ and scale that should be adjusted. Maybe the new scale is simply $a$? (2) The Gumbel is not symmetric around zero. So I'm tempted to say that $-X$ is not Gumbel But I don't know what else can be said.
    $endgroup$
    – STF
    Dec 14 '18 at 12:17
















1












$begingroup$


If $X$ is a random variable distributed as a Gumbel with location $gamma$ and scale $1$ (where $gamma$ is the Euler constant)



[Hence the mean is
$$
gamma-1timesgamma=0
$$

and the variance is
$$
pi^2/6times 1^2=pi^2/6
$$
]



(1) What is the distribution of $aX$ where $ain mathbb{R}$? $a$ should be $>0$?



(2) What is the distribution of $-X$?



I don't know if it is relevant, but here I'm using the definition of Gumbel as in Mathworld and Matlab (sign flipped with respect to the definition of Gumbel in Wikipedia)










share|cite|improve this question











$endgroup$












  • $begingroup$
    Please show us what you have tried so far.
    $endgroup$
    – Stockfish
    Dec 14 '18 at 12:14










  • $begingroup$
    (1) I think that $aX$ is Gumbel with location $gamma$ and scale that should be adjusted. Maybe the new scale is simply $a$? (2) The Gumbel is not symmetric around zero. So I'm tempted to say that $-X$ is not Gumbel But I don't know what else can be said.
    $endgroup$
    – STF
    Dec 14 '18 at 12:17














1












1








1





$begingroup$


If $X$ is a random variable distributed as a Gumbel with location $gamma$ and scale $1$ (where $gamma$ is the Euler constant)



[Hence the mean is
$$
gamma-1timesgamma=0
$$

and the variance is
$$
pi^2/6times 1^2=pi^2/6
$$
]



(1) What is the distribution of $aX$ where $ain mathbb{R}$? $a$ should be $>0$?



(2) What is the distribution of $-X$?



I don't know if it is relevant, but here I'm using the definition of Gumbel as in Mathworld and Matlab (sign flipped with respect to the definition of Gumbel in Wikipedia)










share|cite|improve this question











$endgroup$




If $X$ is a random variable distributed as a Gumbel with location $gamma$ and scale $1$ (where $gamma$ is the Euler constant)



[Hence the mean is
$$
gamma-1timesgamma=0
$$

and the variance is
$$
pi^2/6times 1^2=pi^2/6
$$
]



(1) What is the distribution of $aX$ where $ain mathbb{R}$? $a$ should be $>0$?



(2) What is the distribution of $-X$?



I don't know if it is relevant, but here I'm using the definition of Gumbel as in Mathworld and Matlab (sign flipped with respect to the definition of Gumbel in Wikipedia)







probability probability-theory probability-distributions random-variables






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 14 '18 at 12:28







STF

















asked Dec 14 '18 at 11:59









STFSTF

111420




111420












  • $begingroup$
    Please show us what you have tried so far.
    $endgroup$
    – Stockfish
    Dec 14 '18 at 12:14










  • $begingroup$
    (1) I think that $aX$ is Gumbel with location $gamma$ and scale that should be adjusted. Maybe the new scale is simply $a$? (2) The Gumbel is not symmetric around zero. So I'm tempted to say that $-X$ is not Gumbel But I don't know what else can be said.
    $endgroup$
    – STF
    Dec 14 '18 at 12:17


















  • $begingroup$
    Please show us what you have tried so far.
    $endgroup$
    – Stockfish
    Dec 14 '18 at 12:14










  • $begingroup$
    (1) I think that $aX$ is Gumbel with location $gamma$ and scale that should be adjusted. Maybe the new scale is simply $a$? (2) The Gumbel is not symmetric around zero. So I'm tempted to say that $-X$ is not Gumbel But I don't know what else can be said.
    $endgroup$
    – STF
    Dec 14 '18 at 12:17
















$begingroup$
Please show us what you have tried so far.
$endgroup$
– Stockfish
Dec 14 '18 at 12:14




$begingroup$
Please show us what you have tried so far.
$endgroup$
– Stockfish
Dec 14 '18 at 12:14












$begingroup$
(1) I think that $aX$ is Gumbel with location $gamma$ and scale that should be adjusted. Maybe the new scale is simply $a$? (2) The Gumbel is not symmetric around zero. So I'm tempted to say that $-X$ is not Gumbel But I don't know what else can be said.
$endgroup$
– STF
Dec 14 '18 at 12:17




$begingroup$
(1) I think that $aX$ is Gumbel with location $gamma$ and scale that should be adjusted. Maybe the new scale is simply $a$? (2) The Gumbel is not symmetric around zero. So I'm tempted to say that $-X$ is not Gumbel But I don't know what else can be said.
$endgroup$
– STF
Dec 14 '18 at 12:17










1 Answer
1






active

oldest

votes


















2












$begingroup$

Still a Gumbel distribution.



As with Normal distributions, the family of Gumbel distributions includes all pdfs of the form $|beta|^{-1}fleft(frac{x-mu}{beta}right)$, where $f$ is in the family. So $Xmapsto aX$ just scales $beta$ to $abeta$, including in the case $a=-1$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thanks. But for $a=-1$ then the new scale would be $-beta$ which is $<0$ (which is not possible, right?). Shouldn't we impose $a>0$?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19












  • $begingroup$
    What about point (2) of my question?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19










  • $begingroup$
    @STF (2) is, as explained, a special case of (1). You shouldn't worry about $beta<0$ as long as you see the sign of $beta$ as saying whether it's a left- or right-handed Gumbel distribution. This is an area where the situation is very different from the Normal distribution, because the pdf isn't even.
    $endgroup$
    – J.G.
    Dec 14 '18 at 12:55










  • $begingroup$
    could you given a look to this other question of mine if you have some time? Thanks math.stackexchange.com/questions/3039451/…
    $endgroup$
    – STF
    Dec 14 '18 at 16:26











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

Still a Gumbel distribution.



As with Normal distributions, the family of Gumbel distributions includes all pdfs of the form $|beta|^{-1}fleft(frac{x-mu}{beta}right)$, where $f$ is in the family. So $Xmapsto aX$ just scales $beta$ to $abeta$, including in the case $a=-1$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thanks. But for $a=-1$ then the new scale would be $-beta$ which is $<0$ (which is not possible, right?). Shouldn't we impose $a>0$?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19












  • $begingroup$
    What about point (2) of my question?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19










  • $begingroup$
    @STF (2) is, as explained, a special case of (1). You shouldn't worry about $beta<0$ as long as you see the sign of $beta$ as saying whether it's a left- or right-handed Gumbel distribution. This is an area where the situation is very different from the Normal distribution, because the pdf isn't even.
    $endgroup$
    – J.G.
    Dec 14 '18 at 12:55










  • $begingroup$
    could you given a look to this other question of mine if you have some time? Thanks math.stackexchange.com/questions/3039451/…
    $endgroup$
    – STF
    Dec 14 '18 at 16:26
















2












$begingroup$

Still a Gumbel distribution.



As with Normal distributions, the family of Gumbel distributions includes all pdfs of the form $|beta|^{-1}fleft(frac{x-mu}{beta}right)$, where $f$ is in the family. So $Xmapsto aX$ just scales $beta$ to $abeta$, including in the case $a=-1$.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Thanks. But for $a=-1$ then the new scale would be $-beta$ which is $<0$ (which is not possible, right?). Shouldn't we impose $a>0$?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19












  • $begingroup$
    What about point (2) of my question?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19










  • $begingroup$
    @STF (2) is, as explained, a special case of (1). You shouldn't worry about $beta<0$ as long as you see the sign of $beta$ as saying whether it's a left- or right-handed Gumbel distribution. This is an area where the situation is very different from the Normal distribution, because the pdf isn't even.
    $endgroup$
    – J.G.
    Dec 14 '18 at 12:55










  • $begingroup$
    could you given a look to this other question of mine if you have some time? Thanks math.stackexchange.com/questions/3039451/…
    $endgroup$
    – STF
    Dec 14 '18 at 16:26














2












2








2





$begingroup$

Still a Gumbel distribution.



As with Normal distributions, the family of Gumbel distributions includes all pdfs of the form $|beta|^{-1}fleft(frac{x-mu}{beta}right)$, where $f$ is in the family. So $Xmapsto aX$ just scales $beta$ to $abeta$, including in the case $a=-1$.






share|cite|improve this answer











$endgroup$



Still a Gumbel distribution.



As with Normal distributions, the family of Gumbel distributions includes all pdfs of the form $|beta|^{-1}fleft(frac{x-mu}{beta}right)$, where $f$ is in the family. So $Xmapsto aX$ just scales $beta$ to $abeta$, including in the case $a=-1$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Dec 16 '18 at 15:34









Davide Giraudo

126k16150261




126k16150261










answered Dec 14 '18 at 12:16









J.G.J.G.

26.1k22539




26.1k22539












  • $begingroup$
    Thanks. But for $a=-1$ then the new scale would be $-beta$ which is $<0$ (which is not possible, right?). Shouldn't we impose $a>0$?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19












  • $begingroup$
    What about point (2) of my question?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19










  • $begingroup$
    @STF (2) is, as explained, a special case of (1). You shouldn't worry about $beta<0$ as long as you see the sign of $beta$ as saying whether it's a left- or right-handed Gumbel distribution. This is an area where the situation is very different from the Normal distribution, because the pdf isn't even.
    $endgroup$
    – J.G.
    Dec 14 '18 at 12:55










  • $begingroup$
    could you given a look to this other question of mine if you have some time? Thanks math.stackexchange.com/questions/3039451/…
    $endgroup$
    – STF
    Dec 14 '18 at 16:26


















  • $begingroup$
    Thanks. But for $a=-1$ then the new scale would be $-beta$ which is $<0$ (which is not possible, right?). Shouldn't we impose $a>0$?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19












  • $begingroup$
    What about point (2) of my question?
    $endgroup$
    – STF
    Dec 14 '18 at 12:19










  • $begingroup$
    @STF (2) is, as explained, a special case of (1). You shouldn't worry about $beta<0$ as long as you see the sign of $beta$ as saying whether it's a left- or right-handed Gumbel distribution. This is an area where the situation is very different from the Normal distribution, because the pdf isn't even.
    $endgroup$
    – J.G.
    Dec 14 '18 at 12:55










  • $begingroup$
    could you given a look to this other question of mine if you have some time? Thanks math.stackexchange.com/questions/3039451/…
    $endgroup$
    – STF
    Dec 14 '18 at 16:26
















$begingroup$
Thanks. But for $a=-1$ then the new scale would be $-beta$ which is $<0$ (which is not possible, right?). Shouldn't we impose $a>0$?
$endgroup$
– STF
Dec 14 '18 at 12:19






$begingroup$
Thanks. But for $a=-1$ then the new scale would be $-beta$ which is $<0$ (which is not possible, right?). Shouldn't we impose $a>0$?
$endgroup$
– STF
Dec 14 '18 at 12:19














$begingroup$
What about point (2) of my question?
$endgroup$
– STF
Dec 14 '18 at 12:19




$begingroup$
What about point (2) of my question?
$endgroup$
– STF
Dec 14 '18 at 12:19












$begingroup$
@STF (2) is, as explained, a special case of (1). You shouldn't worry about $beta<0$ as long as you see the sign of $beta$ as saying whether it's a left- or right-handed Gumbel distribution. This is an area where the situation is very different from the Normal distribution, because the pdf isn't even.
$endgroup$
– J.G.
Dec 14 '18 at 12:55




$begingroup$
@STF (2) is, as explained, a special case of (1). You shouldn't worry about $beta<0$ as long as you see the sign of $beta$ as saying whether it's a left- or right-handed Gumbel distribution. This is an area where the situation is very different from the Normal distribution, because the pdf isn't even.
$endgroup$
– J.G.
Dec 14 '18 at 12:55












$begingroup$
could you given a look to this other question of mine if you have some time? Thanks math.stackexchange.com/questions/3039451/…
$endgroup$
– STF
Dec 14 '18 at 16:26




$begingroup$
could you given a look to this other question of mine if you have some time? Thanks math.stackexchange.com/questions/3039451/…
$endgroup$
– STF
Dec 14 '18 at 16:26


















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