Counterexample for $E[X|Y]=E[X]$ implies $X$ and $Y$ independent
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Statement: $E[X|Y]=E[X]$ implies $X$ and $Y$ independent.
I quite sure that it's not true, And I trying to find an Counterexample for this. but it's hard for me to find one.
probability conditional-expectation
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add a comment |
$begingroup$
Statement: $E[X|Y]=E[X]$ implies $X$ and $Y$ independent.
I quite sure that it's not true, And I trying to find an Counterexample for this. but it's hard for me to find one.
probability conditional-expectation
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2
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See the following post: Is there any counterexample to show that $X,Y$ are two random variables and $E(Xmid Y)=E(X)$, but $X$ and $Y$ are not independent.
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– projectilemotion
Dec 14 '18 at 12:01
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I didn't found it before. Thank you
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– Mr.OY
Dec 14 '18 at 12:24
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After three rather basic questions about conditional expectations in the measure theory sense of the term... Do you have any textbook on the subject at your disposal? Otherwise, I can already predict the long string of elementary questions you are susceptible to ask about it...
$endgroup$
– Did
Dec 14 '18 at 12:39
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@Did I got one, but it seems not to have everything in it, and there are some that points that are not clear, and of course there are questions which I need to figure, such as this one. about those 3 questions, expect for the second one none of them seems to me basic.
$endgroup$
– Mr.OY
Dec 14 '18 at 12:51
$begingroup$
The present one is explained in every decent source on the subject.
$endgroup$
– Did
Dec 14 '18 at 13:57
add a comment |
$begingroup$
Statement: $E[X|Y]=E[X]$ implies $X$ and $Y$ independent.
I quite sure that it's not true, And I trying to find an Counterexample for this. but it's hard for me to find one.
probability conditional-expectation
$endgroup$
Statement: $E[X|Y]=E[X]$ implies $X$ and $Y$ independent.
I quite sure that it's not true, And I trying to find an Counterexample for this. but it's hard for me to find one.
probability conditional-expectation
probability conditional-expectation
asked Dec 14 '18 at 11:57
Mr.OYMr.OY
16610
16610
2
$begingroup$
See the following post: Is there any counterexample to show that $X,Y$ are two random variables and $E(Xmid Y)=E(X)$, but $X$ and $Y$ are not independent.
$endgroup$
– projectilemotion
Dec 14 '18 at 12:01
$begingroup$
I didn't found it before. Thank you
$endgroup$
– Mr.OY
Dec 14 '18 at 12:24
$begingroup$
After three rather basic questions about conditional expectations in the measure theory sense of the term... Do you have any textbook on the subject at your disposal? Otherwise, I can already predict the long string of elementary questions you are susceptible to ask about it...
$endgroup$
– Did
Dec 14 '18 at 12:39
$begingroup$
@Did I got one, but it seems not to have everything in it, and there are some that points that are not clear, and of course there are questions which I need to figure, such as this one. about those 3 questions, expect for the second one none of them seems to me basic.
$endgroup$
– Mr.OY
Dec 14 '18 at 12:51
$begingroup$
The present one is explained in every decent source on the subject.
$endgroup$
– Did
Dec 14 '18 at 13:57
add a comment |
2
$begingroup$
See the following post: Is there any counterexample to show that $X,Y$ are two random variables and $E(Xmid Y)=E(X)$, but $X$ and $Y$ are not independent.
$endgroup$
– projectilemotion
Dec 14 '18 at 12:01
$begingroup$
I didn't found it before. Thank you
$endgroup$
– Mr.OY
Dec 14 '18 at 12:24
$begingroup$
After three rather basic questions about conditional expectations in the measure theory sense of the term... Do you have any textbook on the subject at your disposal? Otherwise, I can already predict the long string of elementary questions you are susceptible to ask about it...
$endgroup$
– Did
Dec 14 '18 at 12:39
$begingroup$
@Did I got one, but it seems not to have everything in it, and there are some that points that are not clear, and of course there are questions which I need to figure, such as this one. about those 3 questions, expect for the second one none of them seems to me basic.
$endgroup$
– Mr.OY
Dec 14 '18 at 12:51
$begingroup$
The present one is explained in every decent source on the subject.
$endgroup$
– Did
Dec 14 '18 at 13:57
2
2
$begingroup$
See the following post: Is there any counterexample to show that $X,Y$ are two random variables and $E(Xmid Y)=E(X)$, but $X$ and $Y$ are not independent.
$endgroup$
– projectilemotion
Dec 14 '18 at 12:01
$begingroup$
See the following post: Is there any counterexample to show that $X,Y$ are two random variables and $E(Xmid Y)=E(X)$, but $X$ and $Y$ are not independent.
$endgroup$
– projectilemotion
Dec 14 '18 at 12:01
$begingroup$
I didn't found it before. Thank you
$endgroup$
– Mr.OY
Dec 14 '18 at 12:24
$begingroup$
I didn't found it before. Thank you
$endgroup$
– Mr.OY
Dec 14 '18 at 12:24
$begingroup$
After three rather basic questions about conditional expectations in the measure theory sense of the term... Do you have any textbook on the subject at your disposal? Otherwise, I can already predict the long string of elementary questions you are susceptible to ask about it...
$endgroup$
– Did
Dec 14 '18 at 12:39
$begingroup$
After three rather basic questions about conditional expectations in the measure theory sense of the term... Do you have any textbook on the subject at your disposal? Otherwise, I can already predict the long string of elementary questions you are susceptible to ask about it...
$endgroup$
– Did
Dec 14 '18 at 12:39
$begingroup$
@Did I got one, but it seems not to have everything in it, and there are some that points that are not clear, and of course there are questions which I need to figure, such as this one. about those 3 questions, expect for the second one none of them seems to me basic.
$endgroup$
– Mr.OY
Dec 14 '18 at 12:51
$begingroup$
@Did I got one, but it seems not to have everything in it, and there are some that points that are not clear, and of course there are questions which I need to figure, such as this one. about those 3 questions, expect for the second one none of them seems to me basic.
$endgroup$
– Mr.OY
Dec 14 '18 at 12:51
$begingroup$
The present one is explained in every decent source on the subject.
$endgroup$
– Did
Dec 14 '18 at 13:57
$begingroup$
The present one is explained in every decent source on the subject.
$endgroup$
– Did
Dec 14 '18 at 13:57
add a comment |
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$begingroup$
See the following post: Is there any counterexample to show that $X,Y$ are two random variables and $E(Xmid Y)=E(X)$, but $X$ and $Y$ are not independent.
$endgroup$
– projectilemotion
Dec 14 '18 at 12:01
$begingroup$
I didn't found it before. Thank you
$endgroup$
– Mr.OY
Dec 14 '18 at 12:24
$begingroup$
After three rather basic questions about conditional expectations in the measure theory sense of the term... Do you have any textbook on the subject at your disposal? Otherwise, I can already predict the long string of elementary questions you are susceptible to ask about it...
$endgroup$
– Did
Dec 14 '18 at 12:39
$begingroup$
@Did I got one, but it seems not to have everything in it, and there are some that points that are not clear, and of course there are questions which I need to figure, such as this one. about those 3 questions, expect for the second one none of them seems to me basic.
$endgroup$
– Mr.OY
Dec 14 '18 at 12:51
$begingroup$
The present one is explained in every decent source on the subject.
$endgroup$
– Did
Dec 14 '18 at 13:57