why I must write the code with four backslashes instead of two?
I want to write the code like that document.querySelector('#foobar'); and it does not work
<div id="foobar"></div>
<div id="foo:bar"></div>
<script>
document.querySelector('#foo\\bar'); // Match the first div
document.querySelector('#foo\:bar'); // Match the second div
</script>
javascript dom jsdom
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I want to write the code like that document.querySelector('#foobar'); and it does not work
<div id="foobar"></div>
<div id="foo:bar"></div>
<script>
document.querySelector('#foo\\bar'); // Match the first div
document.querySelector('#foo\:bar'); // Match the second div
</script>
javascript dom jsdom
add a comment |
I want to write the code like that document.querySelector('#foobar'); and it does not work
<div id="foobar"></div>
<div id="foo:bar"></div>
<script>
document.querySelector('#foo\\bar'); // Match the first div
document.querySelector('#foo\:bar'); // Match the second div
</script>
javascript dom jsdom
I want to write the code like that document.querySelector('#foobar'); and it does not work
<div id="foobar"></div>
<div id="foo:bar"></div>
<script>
document.querySelector('#foo\\bar'); // Match the first div
document.querySelector('#foo\:bar'); // Match the second div
</script>
javascript dom jsdom
javascript dom jsdom
asked Nov 24 '18 at 13:06
Eng Abdullah MorsyEng Abdullah Morsy
52
52
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1 Answer
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JavaScript string syntax uses the backslash as an escaping mechanism for special characters. In order to get a string to end up with a single backslash, you have to double it.
Then, CSS selector syntax for querySelector() also uses the backslash character as a special escape sequence start, and so it's the same thing all over again.
Thus parsing the string reduces the backslashes to two, and then interpreting the selector results in querySelector() looking for just a single backslash.
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
JavaScript string syntax uses the backslash as an escaping mechanism for special characters. In order to get a string to end up with a single backslash, you have to double it.
Then, CSS selector syntax for querySelector() also uses the backslash character as a special escape sequence start, and so it's the same thing all over again.
Thus parsing the string reduces the backslashes to two, and then interpreting the selector results in querySelector() looking for just a single backslash.
add a comment |
JavaScript string syntax uses the backslash as an escaping mechanism for special characters. In order to get a string to end up with a single backslash, you have to double it.
Then, CSS selector syntax for querySelector() also uses the backslash character as a special escape sequence start, and so it's the same thing all over again.
Thus parsing the string reduces the backslashes to two, and then interpreting the selector results in querySelector() looking for just a single backslash.
add a comment |
JavaScript string syntax uses the backslash as an escaping mechanism for special characters. In order to get a string to end up with a single backslash, you have to double it.
Then, CSS selector syntax for querySelector() also uses the backslash character as a special escape sequence start, and so it's the same thing all over again.
Thus parsing the string reduces the backslashes to two, and then interpreting the selector results in querySelector() looking for just a single backslash.
JavaScript string syntax uses the backslash as an escaping mechanism for special characters. In order to get a string to end up with a single backslash, you have to double it.
Then, CSS selector syntax for querySelector() also uses the backslash character as a special escape sequence start, and so it's the same thing all over again.
Thus parsing the string reduces the backslashes to two, and then interpreting the selector results in querySelector() looking for just a single backslash.
answered Nov 24 '18 at 13:09
PointyPointy
318k44458521
318k44458521
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