Loop through two Lists












0















lst = [2,4,6]
lst2 = [4,8,9]
new_lst =


how do i go through every element in lst and multiply them by lst2[0], then go thought every element in lst and multiply them by lst2[1] and finally go through every element in lst and multiply them by lst2[2].



I will add all the answers new_lst



new_lst = [2*4, 4*4, 6*4, 2*8, 4*8, 6*8, 2*9, 4*9, 6*9]










share|improve this question























  • Are you writing in LOOP or what language do you use?

    – Timothy Lukas H.
    Nov 25 '18 at 13:04











  • I am using Python.

    – Phil
    Nov 25 '18 at 14:18
















0















lst = [2,4,6]
lst2 = [4,8,9]
new_lst =


how do i go through every element in lst and multiply them by lst2[0], then go thought every element in lst and multiply them by lst2[1] and finally go through every element in lst and multiply them by lst2[2].



I will add all the answers new_lst



new_lst = [2*4, 4*4, 6*4, 2*8, 4*8, 6*8, 2*9, 4*9, 6*9]










share|improve this question























  • Are you writing in LOOP or what language do you use?

    – Timothy Lukas H.
    Nov 25 '18 at 13:04











  • I am using Python.

    – Phil
    Nov 25 '18 at 14:18














0












0








0








lst = [2,4,6]
lst2 = [4,8,9]
new_lst =


how do i go through every element in lst and multiply them by lst2[0], then go thought every element in lst and multiply them by lst2[1] and finally go through every element in lst and multiply them by lst2[2].



I will add all the answers new_lst



new_lst = [2*4, 4*4, 6*4, 2*8, 4*8, 6*8, 2*9, 4*9, 6*9]










share|improve this question














lst = [2,4,6]
lst2 = [4,8,9]
new_lst =


how do i go through every element in lst and multiply them by lst2[0], then go thought every element in lst and multiply them by lst2[1] and finally go through every element in lst and multiply them by lst2[2].



I will add all the answers new_lst



new_lst = [2*4, 4*4, 6*4, 2*8, 4*8, 6*8, 2*9, 4*9, 6*9]







loops






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 25 '18 at 12:58









PhilPhil

113




113













  • Are you writing in LOOP or what language do you use?

    – Timothy Lukas H.
    Nov 25 '18 at 13:04











  • I am using Python.

    – Phil
    Nov 25 '18 at 14:18



















  • Are you writing in LOOP or what language do you use?

    – Timothy Lukas H.
    Nov 25 '18 at 13:04











  • I am using Python.

    – Phil
    Nov 25 '18 at 14:18

















Are you writing in LOOP or what language do you use?

– Timothy Lukas H.
Nov 25 '18 at 13:04





Are you writing in LOOP or what language do you use?

– Timothy Lukas H.
Nov 25 '18 at 13:04













I am using Python.

– Phil
Nov 25 '18 at 14:18





I am using Python.

– Phil
Nov 25 '18 at 14:18












2 Answers
2






active

oldest

votes


















2














This may work,



lst = [2,4,6]
lst2 = [4,8,9]
new_lst =

for i in lst2:
# i will equal 4, then 8, then 9
for j in lst:
# j will equal 2, then 4, then 6
new_lst.append(i*j)

print(new_lst)
> [8, 16, 24, 16, 32, 48, 18, 36, 54]





share|improve this answer





















  • 1





    Thanks very much, that worked!

    – Phil
    Nov 25 '18 at 18:30



















1














I'm not based in Python, but in C# but because you didn't get any answer yet, I answer so you can try to rebuild:



In C# you would do:



List list = new List();



for(int i = 0; i < lst.length; i++)
{
for(int j = 0; j < lst2.length; j++)
{
list.Add(lst[i] * lst2[j]);
}
}





share|improve this answer



















  • 1





    Thank you for your advise!

    – Phil
    Nov 25 '18 at 18:30











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














This may work,



lst = [2,4,6]
lst2 = [4,8,9]
new_lst =

for i in lst2:
# i will equal 4, then 8, then 9
for j in lst:
# j will equal 2, then 4, then 6
new_lst.append(i*j)

print(new_lst)
> [8, 16, 24, 16, 32, 48, 18, 36, 54]





share|improve this answer





















  • 1





    Thanks very much, that worked!

    – Phil
    Nov 25 '18 at 18:30
















2














This may work,



lst = [2,4,6]
lst2 = [4,8,9]
new_lst =

for i in lst2:
# i will equal 4, then 8, then 9
for j in lst:
# j will equal 2, then 4, then 6
new_lst.append(i*j)

print(new_lst)
> [8, 16, 24, 16, 32, 48, 18, 36, 54]





share|improve this answer





















  • 1





    Thanks very much, that worked!

    – Phil
    Nov 25 '18 at 18:30














2












2








2







This may work,



lst = [2,4,6]
lst2 = [4,8,9]
new_lst =

for i in lst2:
# i will equal 4, then 8, then 9
for j in lst:
# j will equal 2, then 4, then 6
new_lst.append(i*j)

print(new_lst)
> [8, 16, 24, 16, 32, 48, 18, 36, 54]





share|improve this answer















This may work,



lst = [2,4,6]
lst2 = [4,8,9]
new_lst =

for i in lst2:
# i will equal 4, then 8, then 9
for j in lst:
# j will equal 2, then 4, then 6
new_lst.append(i*j)

print(new_lst)
> [8, 16, 24, 16, 32, 48, 18, 36, 54]






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 25 '18 at 16:16









Andrew F

1,0541412




1,0541412










answered Nov 25 '18 at 14:54









ChameeraChameera

628




628








  • 1





    Thanks very much, that worked!

    – Phil
    Nov 25 '18 at 18:30














  • 1





    Thanks very much, that worked!

    – Phil
    Nov 25 '18 at 18:30








1




1





Thanks very much, that worked!

– Phil
Nov 25 '18 at 18:30





Thanks very much, that worked!

– Phil
Nov 25 '18 at 18:30













1














I'm not based in Python, but in C# but because you didn't get any answer yet, I answer so you can try to rebuild:



In C# you would do:



List list = new List();



for(int i = 0; i < lst.length; i++)
{
for(int j = 0; j < lst2.length; j++)
{
list.Add(lst[i] * lst2[j]);
}
}





share|improve this answer



















  • 1





    Thank you for your advise!

    – Phil
    Nov 25 '18 at 18:30
















1














I'm not based in Python, but in C# but because you didn't get any answer yet, I answer so you can try to rebuild:



In C# you would do:



List list = new List();



for(int i = 0; i < lst.length; i++)
{
for(int j = 0; j < lst2.length; j++)
{
list.Add(lst[i] * lst2[j]);
}
}





share|improve this answer



















  • 1





    Thank you for your advise!

    – Phil
    Nov 25 '18 at 18:30














1












1








1







I'm not based in Python, but in C# but because you didn't get any answer yet, I answer so you can try to rebuild:



In C# you would do:



List list = new List();



for(int i = 0; i < lst.length; i++)
{
for(int j = 0; j < lst2.length; j++)
{
list.Add(lst[i] * lst2[j]);
}
}





share|improve this answer













I'm not based in Python, but in C# but because you didn't get any answer yet, I answer so you can try to rebuild:



In C# you would do:



List list = new List();



for(int i = 0; i < lst.length; i++)
{
for(int j = 0; j < lst2.length; j++)
{
list.Add(lst[i] * lst2[j]);
}
}






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 25 '18 at 14:39









Timothy Lukas H.Timothy Lukas H.

286212




286212








  • 1





    Thank you for your advise!

    – Phil
    Nov 25 '18 at 18:30














  • 1





    Thank you for your advise!

    – Phil
    Nov 25 '18 at 18:30








1




1





Thank you for your advise!

– Phil
Nov 25 '18 at 18:30





Thank you for your advise!

– Phil
Nov 25 '18 at 18:30


















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