The second derivative of a mean square error












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$begingroup$


I'm not very familiar with multivariable calculus, I really hope someone could help me check whether or not the following computation is right.



Here's the mean square error of which I have to take the second derivative with respect to $phi$
$$L(phi)={1over N}sum_{n=1}^N{Vert V_phi(s_n)-hat V_nVert^2over 2sigma^2}$$



where $hat V_n$ and $sigma$ are constants, and $V_phi(s_n)$ is a function of $s_n$ and $phi$.



Here's how I do the math
$$
begin{align}
{partial^2L(phi)over partialphi^2}&={partialover partial phi}left({partial V_phi(s_n)over partial phi}{partial L(phi)over partial V_phi(s_n)}right)\
&={partial V_phi(s_n)over partial phi}{partial^2L(phi)over partial V_phi(s_n)^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{partial L(phi)overpartial V_phi(s_n)}\
&={partial V_phi(s_n)over partial phi}{1over sigma^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{1over N}sum_{n=1}^N{V_phi(s_n)-hat V_noversigma^2}
end{align}
$$



Did I do it right?



By the way, I'm not so sure whether I have to use $nabla_theta$ or $partial$ in this context. I frequently see both in papers and I've done some search -- it seems to me that $nabla_phi$ is more sensible, but I seldom see it used in the second derivative. Did I misuse symbols?



Thanks in advance :-)










share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    I'm not very familiar with multivariable calculus, I really hope someone could help me check whether or not the following computation is right.



    Here's the mean square error of which I have to take the second derivative with respect to $phi$
    $$L(phi)={1over N}sum_{n=1}^N{Vert V_phi(s_n)-hat V_nVert^2over 2sigma^2}$$



    where $hat V_n$ and $sigma$ are constants, and $V_phi(s_n)$ is a function of $s_n$ and $phi$.



    Here's how I do the math
    $$
    begin{align}
    {partial^2L(phi)over partialphi^2}&={partialover partial phi}left({partial V_phi(s_n)over partial phi}{partial L(phi)over partial V_phi(s_n)}right)\
    &={partial V_phi(s_n)over partial phi}{partial^2L(phi)over partial V_phi(s_n)^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{partial L(phi)overpartial V_phi(s_n)}\
    &={partial V_phi(s_n)over partial phi}{1over sigma^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{1over N}sum_{n=1}^N{V_phi(s_n)-hat V_noversigma^2}
    end{align}
    $$



    Did I do it right?



    By the way, I'm not so sure whether I have to use $nabla_theta$ or $partial$ in this context. I frequently see both in papers and I've done some search -- it seems to me that $nabla_phi$ is more sensible, but I seldom see it used in the second derivative. Did I misuse symbols?



    Thanks in advance :-)










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      I'm not very familiar with multivariable calculus, I really hope someone could help me check whether or not the following computation is right.



      Here's the mean square error of which I have to take the second derivative with respect to $phi$
      $$L(phi)={1over N}sum_{n=1}^N{Vert V_phi(s_n)-hat V_nVert^2over 2sigma^2}$$



      where $hat V_n$ and $sigma$ are constants, and $V_phi(s_n)$ is a function of $s_n$ and $phi$.



      Here's how I do the math
      $$
      begin{align}
      {partial^2L(phi)over partialphi^2}&={partialover partial phi}left({partial V_phi(s_n)over partial phi}{partial L(phi)over partial V_phi(s_n)}right)\
      &={partial V_phi(s_n)over partial phi}{partial^2L(phi)over partial V_phi(s_n)^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{partial L(phi)overpartial V_phi(s_n)}\
      &={partial V_phi(s_n)over partial phi}{1over sigma^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{1over N}sum_{n=1}^N{V_phi(s_n)-hat V_noversigma^2}
      end{align}
      $$



      Did I do it right?



      By the way, I'm not so sure whether I have to use $nabla_theta$ or $partial$ in this context. I frequently see both in papers and I've done some search -- it seems to me that $nabla_phi$ is more sensible, but I seldom see it used in the second derivative. Did I misuse symbols?



      Thanks in advance :-)










      share|cite|improve this question











      $endgroup$




      I'm not very familiar with multivariable calculus, I really hope someone could help me check whether or not the following computation is right.



      Here's the mean square error of which I have to take the second derivative with respect to $phi$
      $$L(phi)={1over N}sum_{n=1}^N{Vert V_phi(s_n)-hat V_nVert^2over 2sigma^2}$$



      where $hat V_n$ and $sigma$ are constants, and $V_phi(s_n)$ is a function of $s_n$ and $phi$.



      Here's how I do the math
      $$
      begin{align}
      {partial^2L(phi)over partialphi^2}&={partialover partial phi}left({partial V_phi(s_n)over partial phi}{partial L(phi)over partial V_phi(s_n)}right)\
      &={partial V_phi(s_n)over partial phi}{partial^2L(phi)over partial V_phi(s_n)^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{partial L(phi)overpartial V_phi(s_n)}\
      &={partial V_phi(s_n)over partial phi}{1over sigma^2}{partial V_phi(s_n)over partial phi}^T+{partial^2V_phi(s_n)over partialphi^2}{1over N}sum_{n=1}^N{V_phi(s_n)-hat V_noversigma^2}
      end{align}
      $$



      Did I do it right?



      By the way, I'm not so sure whether I have to use $nabla_theta$ or $partial$ in this context. I frequently see both in papers and I've done some search -- it seems to me that $nabla_phi$ is more sensible, but I seldom see it used in the second derivative. Did I misuse symbols?



      Thanks in advance :-)







      multivariable-calculus derivatives partial-derivative






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      edited Dec 31 '18 at 0:40







      Sherwin Chen

















      asked Dec 27 '18 at 2:42









      Sherwin ChenSherwin Chen

      1657




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