How to count the number of characters entered?
0
My assignment is
In C++, use pointer to count the number of characters user entered. Print the output on screen
Here is what I have done. I do not know how to count the characters I entered.
#include <iostream>
using namespace std;
int main()
{
int string[20] = { 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 };
int sum = 0;
char a;
cout << "Enter less than 20 characters(no space) : ";
for (int i = 0; i < 20; i++)
{
cin >> a;
string[i] = a;
if (string[i] != 0)
sum = sum + 1;
else
break;
}
cout << endl;
cout << "The number of characters in " << *string << " is " << sum;
return 0;
}
c++ pointers
edited Nov 25 '18 at 12:57
Swordfish
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
add a comment |
0
My assignment is
In C++, use pointer to count the number of characters user entered. Print the output on screen
Here is what I have done. I do not know how to count the characters I entered.
#include <iostream>
using namespace std;
int main()
{
int string[20] = { 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 };
int sum = 0;
char a;
cout << "Enter less than 20 characters(no space) : ";
for (int i = 0; i < 20; i++)
{
cin >> a;
string[i] = a;
if (string[i] != 0)
sum = sum + 1;
else
break;
}
cout << endl;
cout << "The number of characters in " << *string << " is " << sum;
return 0;
}
c++ pointers
edited Nov 25 '18 at 12:57
Swordfish
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
3
Use a string directly. And display its length. (or say what the problem is, you can't display a integer array like this).
– Matthieu Brucher
Nov 25 '18 at 12:44
4
If you have questions about homework assignments, your teacher or instructor is the best resource for getting help. That's what they're being paid for, that's their job.
– Sam Varshavchik
Nov 25 '18 at 12:45
You have a variable namedstring- but it's an array ofints, which doesn't in any way resemble a string.
– Igor Tandetnik
Nov 25 '18 at 15:55
BTW, the usual definition of a string is zero or more characters, notint.
– Thomas Matthews
Nov 25 '18 at 18:20
Also, the assignment says to use a pointer. You don't have any pointers in your code. Definitely talk with the instructor and get some clarification.
– Thomas Matthews
Nov 25 '18 at 18:22
add a comment |
0
0
0
My assignment is
In C++, use pointer to count the number of characters user entered. Print the output on screen
Here is what I have done. I do not know how to count the characters I entered.
#include <iostream>
using namespace std;
int main()
{
int string[20] = { 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 };
int sum = 0;
char a;
cout << "Enter less than 20 characters(no space) : ";
for (int i = 0; i < 20; i++)
{
cin >> a;
string[i] = a;
if (string[i] != 0)
sum = sum + 1;
else
break;
}
cout << endl;
cout << "The number of characters in " << *string << " is " << sum;
return 0;
}
c++ pointers
edited Nov 25 '18 at 12:57
Swordfish
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
My assignment is
In C++, use pointer to count the number of characters user entered. Print the output on screen
Here is what I have done. I do not know how to count the characters I entered.
#include <iostream>
using namespace std;
int main()
{
int string[20] = { 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 };
int sum = 0;
char a;
cout << "Enter less than 20 characters(no space) : ";
for (int i = 0; i < 20; i++)
{
cin >> a;
string[i] = a;
if (string[i] != 0)
sum = sum + 1;
else
break;
}
cout << endl;
cout << "The number of characters in " << *string << " is " << sum;
return 0;
}
c++ pointers
c++ pointers
edited Nov 25 '18 at 12:57
Swordfish
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
edited Nov 25 '18 at 12:57
Swordfish
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
edited Nov 25 '18 at 12:57
Swordfish
1
edited Nov 25 '18 at 12:57
Swordfish
1
edited Nov 25 '18 at 12:57
Swordfish
1
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
asked Nov 25 '18 at 12:42
user10702014user10702014
1
1
3
Use a string directly. And display its length. (or say what the problem is, you can't display a integer array like this).
– Matthieu Brucher
Nov 25 '18 at 12:44
4
If you have questions about homework assignments, your teacher or instructor is the best resource for getting help. That's what they're being paid for, that's their job.
– Sam Varshavchik
Nov 25 '18 at 12:45
You have a variable namedstring- but it's an array ofints, which doesn't in any way resemble a string.
– Igor Tandetnik
Nov 25 '18 at 15:55
BTW, the usual definition of a string is zero or more characters, notint.
– Thomas Matthews
Nov 25 '18 at 18:20
Also, the assignment says to use a pointer. You don't have any pointers in your code. Definitely talk with the instructor and get some clarification.
– Thomas Matthews
Nov 25 '18 at 18:22
add a comment |
3
Use a string directly. And display its length. (or say what the problem is, you can't display a integer array like this).
– Matthieu Brucher
Nov 25 '18 at 12:44
4
If you have questions about homework assignments, your teacher or instructor is the best resource for getting help. That's what they're being paid for, that's their job.
– Sam Varshavchik
Nov 25 '18 at 12:45
You have a variable namedstring- but it's an array ofints, which doesn't in any way resemble a string.
– Igor Tandetnik
Nov 25 '18 at 15:55
BTW, the usual definition of a string is zero or more characters, notint.
– Thomas Matthews
Nov 25 '18 at 18:20
Also, the assignment says to use a pointer. You don't have any pointers in your code. Definitely talk with the instructor and get some clarification.
– Thomas Matthews
Nov 25 '18 at 18:22
3
3
Use a string directly. And display its length. (or say what the problem is, you can't display a integer array like this).
– Matthieu Brucher
Nov 25 '18 at 12:44
Use a string directly. And display its length. (or say what the problem is, you can't display a integer array like this).
– Matthieu Brucher
Nov 25 '18 at 12:44
4
4
If you have questions about homework assignments, your teacher or instructor is the best resource for getting help. That's what they're being paid for, that's their job.
– Sam Varshavchik
Nov 25 '18 at 12:45
If you have questions about homework assignments, your teacher or instructor is the best resource for getting help. That's what they're being paid for, that's their job.
– Sam Varshavchik
Nov 25 '18 at 12:45
You have a variable named
string - but it's an array of ints, which doesn't in any way resemble a string.– Igor Tandetnik
Nov 25 '18 at 15:55
You have a variable named
string - but it's an array of ints, which doesn't in any way resemble a string.– Igor Tandetnik
Nov 25 '18 at 15:55
BTW, the usual definition of a string is zero or more characters, not
int.– Thomas Matthews
Nov 25 '18 at 18:20
BTW, the usual definition of a string is zero or more characters, not
int.– Thomas Matthews
Nov 25 '18 at 18:20
Also, the assignment says to use a pointer. You don't have any pointers in your code. Definitely talk with the instructor and get some clarification.
– Thomas Matthews
Nov 25 '18 at 18:22
Also, the assignment says to use a pointer. You don't have any pointers in your code. Definitely talk with the instructor and get some clarification.
– Thomas Matthews
Nov 25 '18 at 18:22
add a comment |
1 Answer
1
active
oldest
votes
0
From my understanding of the requirements, you'll need to use a pointer.
int main()
{
static const size_t MAX_CHARS = 20;
char text[MAX_CHARS] = {0};
std::cout << "Enter up to 20 characters, no spaces: ";
size_t quantity;
char c;
while (std::cin >> c)
{
if (quantity >= MAX_CHARS) break;
text[quantity++] = c;
}
// Count the characters using a pointer:
if (quantity < MAX_CHARS)
{
text[quantity] = '';
}
else
{
text[MAX_CHARS - 1] = '';
}
quantity = 0;
char * pointer = &text[0];
while (*pointer != '')
{
++quantity;
++pointer;
}
std::cout << "Characters entered: " << quantity << "n";
return 0;
}
I guess this is an exercise to understand pointers.
Otherwise, I suggest using std::string and std::string::length().
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
But after I entered your program, the results it shows are always“Characters entered: 0”
– user10702014
Nov 28 '18 at 13:27
add a comment |
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0
From my understanding of the requirements, you'll need to use a pointer.
int main()
{
static const size_t MAX_CHARS = 20;
char text[MAX_CHARS] = {0};
std::cout << "Enter up to 20 characters, no spaces: ";
size_t quantity;
char c;
while (std::cin >> c)
{
if (quantity >= MAX_CHARS) break;
text[quantity++] = c;
}
// Count the characters using a pointer:
if (quantity < MAX_CHARS)
{
text[quantity] = '';
}
else
{
text[MAX_CHARS - 1] = '';
}
quantity = 0;
char * pointer = &text[0];
while (*pointer != '')
{
++quantity;
++pointer;
}
std::cout << "Characters entered: " << quantity << "n";
return 0;
}
I guess this is an exercise to understand pointers.
Otherwise, I suggest using std::string and std::string::length().
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
But after I entered your program, the results it shows are always“Characters entered: 0”
– user10702014
Nov 28 '18 at 13:27
add a comment |
0
From my understanding of the requirements, you'll need to use a pointer.
int main()
{
static const size_t MAX_CHARS = 20;
char text[MAX_CHARS] = {0};
std::cout << "Enter up to 20 characters, no spaces: ";
size_t quantity;
char c;
while (std::cin >> c)
{
if (quantity >= MAX_CHARS) break;
text[quantity++] = c;
}
// Count the characters using a pointer:
if (quantity < MAX_CHARS)
{
text[quantity] = '';
}
else
{
text[MAX_CHARS - 1] = '';
}
quantity = 0;
char * pointer = &text[0];
while (*pointer != '')
{
++quantity;
++pointer;
}
std::cout << "Characters entered: " << quantity << "n";
return 0;
}
I guess this is an exercise to understand pointers.
Otherwise, I suggest using std::string and std::string::length().
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
But after I entered your program, the results it shows are always“Characters entered: 0”
– user10702014
Nov 28 '18 at 13:27
add a comment |
0
0
0
From my understanding of the requirements, you'll need to use a pointer.
int main()
{
static const size_t MAX_CHARS = 20;
char text[MAX_CHARS] = {0};
std::cout << "Enter up to 20 characters, no spaces: ";
size_t quantity;
char c;
while (std::cin >> c)
{
if (quantity >= MAX_CHARS) break;
text[quantity++] = c;
}
// Count the characters using a pointer:
if (quantity < MAX_CHARS)
{
text[quantity] = '';
}
else
{
text[MAX_CHARS - 1] = '';
}
quantity = 0;
char * pointer = &text[0];
while (*pointer != '')
{
++quantity;
++pointer;
}
std::cout << "Characters entered: " << quantity << "n";
return 0;
}
I guess this is an exercise to understand pointers.
Otherwise, I suggest using std::string and std::string::length().
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
From my understanding of the requirements, you'll need to use a pointer.
int main()
{
static const size_t MAX_CHARS = 20;
char text[MAX_CHARS] = {0};
std::cout << "Enter up to 20 characters, no spaces: ";
size_t quantity;
char c;
while (std::cin >> c)
{
if (quantity >= MAX_CHARS) break;
text[quantity++] = c;
}
// Count the characters using a pointer:
if (quantity < MAX_CHARS)
{
text[quantity] = '';
}
else
{
text[MAX_CHARS - 1] = '';
}
quantity = 0;
char * pointer = &text[0];
while (*pointer != '')
{
++quantity;
++pointer;
}
std::cout << "Characters entered: " << quantity << "n";
return 0;
}
I guess this is an exercise to understand pointers.
Otherwise, I suggest using std::string and std::string::length().
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
answered Nov 25 '18 at 18:35
Thomas MatthewsThomas Matthews
44.6k1174123
44.6k1174123
But after I entered your program, the results it shows are always“Characters entered: 0”
– user10702014
Nov 28 '18 at 13:27
add a comment |
But after I entered your program, the results it shows are always“Characters entered: 0”
– user10702014
Nov 28 '18 at 13:27
But after I entered your program, the results it shows are always“Characters entered: 0”
– user10702014
Nov 28 '18 at 13:27
But after I entered your program, the results it shows are always“Characters entered: 0”
– user10702014
Nov 28 '18 at 13:27
add a comment |
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3
Use a string directly. And display its length. (or say what the problem is, you can't display a integer array like this).
– Matthieu Brucher
Nov 25 '18 at 12:44
4
If you have questions about homework assignments, your teacher or instructor is the best resource for getting help. That's what they're being paid for, that's their job.
– Sam Varshavchik
Nov 25 '18 at 12:45
You have a variable named
string- but it's an array ofints, which doesn't in any way resemble a string.– Igor Tandetnik
Nov 25 '18 at 15:55
BTW, the usual definition of a string is zero or more characters, not
int.– Thomas Matthews
Nov 25 '18 at 18:20
Also, the assignment says to use a pointer. You don't have any pointers in your code. Definitely talk with the instructor and get some clarification.
– Thomas Matthews
Nov 25 '18 at 18:22