EMU8086 adds value to wrong register
var1 db 1h, 2h
var2 db 2h
MOV AL, [var1 + 1]
MOV [var2], AL
If I emulate this code, I see EMU8086 set up AH (not AL) part of register AX. Why?
nasm emu8086
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var1 db 1h, 2h
var2 db 2h
MOV AL, [var1 + 1]
MOV [var2], AL
If I emulate this code, I see EMU8086 set up AH (not AL) part of register AX. Why?
nasm emu8086
add a comment |
var1 db 1h, 2h
var2 db 2h
MOV AL, [var1 + 1]
MOV [var2], AL
If I emulate this code, I see EMU8086 set up AH (not AL) part of register AX. Why?
nasm emu8086
var1 db 1h, 2h
var2 db 2h
MOV AL, [var1 + 1]
MOV [var2], AL
If I emulate this code, I see EMU8086 set up AH (not AL) part of register AX. Why?
nasm emu8086
nasm emu8086
asked Nov 25 '18 at 12:52
Bartłomiej StasiakBartłomiej Stasiak
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EMU8086 begins to process at the beginning (var1) and interpretes the bytes as instruction and following bytes accordingly. So, the code looks for EMU8086 like
ADD [BP+SI], AX
ADD AH, [BX + SI] + 00001
MOV [00002], AL
As you can see, this code changes AH but not AL. In short: EMU8086 requires a proper DOS program.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
EMU8086 begins to process at the beginning (var1) and interpretes the bytes as instruction and following bytes accordingly. So, the code looks for EMU8086 like
ADD [BP+SI], AX
ADD AH, [BX + SI] + 00001
MOV [00002], AL
As you can see, this code changes AH but not AL. In short: EMU8086 requires a proper DOS program.
add a comment |
EMU8086 begins to process at the beginning (var1) and interpretes the bytes as instruction and following bytes accordingly. So, the code looks for EMU8086 like
ADD [BP+SI], AX
ADD AH, [BX + SI] + 00001
MOV [00002], AL
As you can see, this code changes AH but not AL. In short: EMU8086 requires a proper DOS program.
add a comment |
EMU8086 begins to process at the beginning (var1) and interpretes the bytes as instruction and following bytes accordingly. So, the code looks for EMU8086 like
ADD [BP+SI], AX
ADD AH, [BX + SI] + 00001
MOV [00002], AL
As you can see, this code changes AH but not AL. In short: EMU8086 requires a proper DOS program.
EMU8086 begins to process at the beginning (var1) and interpretes the bytes as instruction and following bytes accordingly. So, the code looks for EMU8086 like
ADD [BP+SI], AX
ADD AH, [BX + SI] + 00001
MOV [00002], AL
As you can see, this code changes AH but not AL. In short: EMU8086 requires a proper DOS program.
answered Nov 25 '18 at 16:07
rkhbrkhb
11.4k72142
11.4k72142
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