Selection Args as integers not string
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I have this method that takes an integer input and returns the row, it should take the employee id and returns its name, title, phone, email.
Meanwhile rawquery selection args use strings and doesn't work with integers, how can i fix that?
public Cursor getEmpData(Integer ID)
{
EmpDept = getReadableDatabase();
Integer empRow = {ID};
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID);
if (c != null)
{
c.moveToFirst();
}
EmpDept.close();
return c;
}
android database sqlite asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
add a comment |
I have this method that takes an integer input and returns the row, it should take the employee id and returns its name, title, phone, email.
Meanwhile rawquery selection args use strings and doesn't work with integers, how can i fix that?
public Cursor getEmpData(Integer ID)
{
EmpDept = getReadableDatabase();
Integer empRow = {ID};
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID);
if (c != null)
{
c.moveToFirst();
}
EmpDept.close();
return c;
}
asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
add a comment |
I have this method that takes an integer input and returns the row, it should take the employee id and returns its name, title, phone, email.
Meanwhile rawquery selection args use strings and doesn't work with integers, how can i fix that?
public Cursor getEmpData(Integer ID)
{
EmpDept = getReadableDatabase();
Integer empRow = {ID};
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID);
if (c != null)
{
c.moveToFirst();
}
EmpDept.close();
return c;
}
asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
I have this method that takes an integer input and returns the row, it should take the employee id and returns its name, title, phone, email.
Meanwhile rawquery selection args use strings and doesn't work with integers, how can i fix that?
public Cursor getEmpData(Integer ID)
{
EmpDept = getReadableDatabase();
Integer empRow = {ID};
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID);
if (c != null)
{
c.moveToFirst();
}
EmpDept.close();
return c;
}
asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
asked Nov 26 '18 at 20:32
AspiringLillyAspiringLilly
205
205
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
The 2nd argument of rawQuery must be an array of String:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", new String {ID.toString()});
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
worked out, thanks
– AspiringLilly
Nov 26 '18 at 20:50
add a comment |
Just use toString(), like with any other Object:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID.toString());
If you decide to use the primitive int instead, String.valueOf(ID) will do the same thing.
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The 2nd argument of rawQuery must be an array of String:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", new String {ID.toString()});
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
worked out, thanks
– AspiringLilly
Nov 26 '18 at 20:50
add a comment |
The 2nd argument of rawQuery must be an array of String:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", new String {ID.toString()});
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
worked out, thanks
– AspiringLilly
Nov 26 '18 at 20:50
add a comment |
The 2nd argument of rawQuery must be an array of String:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", new String {ID.toString()});
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
The 2nd argument of rawQuery must be an array of String:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", new String {ID.toString()});
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
answered Nov 26 '18 at 20:42
forpasforpas
20.4k4830
20.4k4830
worked out, thanks
– AspiringLilly
Nov 26 '18 at 20:50
add a comment |
worked out, thanks
– AspiringLilly
Nov 26 '18 at 20:50
worked out, thanks
– AspiringLilly
Nov 26 '18 at 20:50
worked out, thanks
– AspiringLilly
Nov 26 '18 at 20:50
add a comment |
Just use toString(), like with any other Object:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID.toString());
If you decide to use the primitive int instead, String.valueOf(ID) will do the same thing.
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
add a comment |
Just use toString(), like with any other Object:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID.toString());
If you decide to use the primitive int instead, String.valueOf(ID) will do the same thing.
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
add a comment |
Just use toString(), like with any other Object:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID.toString());
If you decide to use the primitive int instead, String.valueOf(ID) will do the same thing.
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
Just use toString(), like with any other Object:
Cursor c = EmpDept.rawQuery("Select name, Title, phone, email from Employee where EmpID like ?", ID.toString());
If you decide to use the primitive int instead, String.valueOf(ID) will do the same thing.
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
answered Nov 26 '18 at 20:34
TheWandererTheWanderer
7,85931230
7,85931230
add a comment |
add a comment |
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