CSS/jQuery selector to find elements which don't have a certain parent
I found solutions to check if the parent does not have a certain class using :parent
, but I want to have a node type excluded. In my case I only wants forms which are not placed withing an article
.
I found a solution with filter, but I was wondering if there is a selector only way to achieve the same:
$('form.frm').filter(function() {
return $(this).parent().is(":not(article)");
});
EDIT: This solution isn't perfect as it only works if the form.frm
is an immediate child of article. Sometimes I have a div in between.
Here a simplified DOM structure:
<div id="pageContent">
<articel>
<div class="box">
<form class="frm"></form>
</div>
</article>
<articel>
<form class="frm"></form>
</article>
</div>
javascript jquery html jquery-selectors
add a comment |
I found solutions to check if the parent does not have a certain class using :parent
, but I want to have a node type excluded. In my case I only wants forms which are not placed withing an article
.
I found a solution with filter, but I was wondering if there is a selector only way to achieve the same:
$('form.frm').filter(function() {
return $(this).parent().is(":not(article)");
});
EDIT: This solution isn't perfect as it only works if the form.frm
is an immediate child of article. Sometimes I have a div in between.
Here a simplified DOM structure:
<div id="pageContent">
<articel>
<div class="box">
<form class="frm"></form>
</div>
</article>
<articel>
<form class="frm"></form>
</article>
</div>
javascript jquery html jquery-selectors
1
Whats the parent of article element? Would be great if you can share relevant DOM
– Milind Anantwar
Nov 22 '18 at 14:08
You can produce a list of all elements that are not a child of an article.querySelectorAll(':not(article)>*')
but you really mean a list of all elements that are not a descendant of an article, right?
– Mr Lister
Nov 22 '18 at 14:10
add a comment |
I found solutions to check if the parent does not have a certain class using :parent
, but I want to have a node type excluded. In my case I only wants forms which are not placed withing an article
.
I found a solution with filter, but I was wondering if there is a selector only way to achieve the same:
$('form.frm').filter(function() {
return $(this).parent().is(":not(article)");
});
EDIT: This solution isn't perfect as it only works if the form.frm
is an immediate child of article. Sometimes I have a div in between.
Here a simplified DOM structure:
<div id="pageContent">
<articel>
<div class="box">
<form class="frm"></form>
</div>
</article>
<articel>
<form class="frm"></form>
</article>
</div>
javascript jquery html jquery-selectors
I found solutions to check if the parent does not have a certain class using :parent
, but I want to have a node type excluded. In my case I only wants forms which are not placed withing an article
.
I found a solution with filter, but I was wondering if there is a selector only way to achieve the same:
$('form.frm').filter(function() {
return $(this).parent().is(":not(article)");
});
EDIT: This solution isn't perfect as it only works if the form.frm
is an immediate child of article. Sometimes I have a div in between.
Here a simplified DOM structure:
<div id="pageContent">
<articel>
<div class="box">
<form class="frm"></form>
</div>
</article>
<articel>
<form class="frm"></form>
</article>
</div>
javascript jquery html jquery-selectors
javascript jquery html jquery-selectors
edited Nov 22 '18 at 14:43
Mohammad
15.5k123461
15.5k123461
asked Nov 22 '18 at 13:57
ThomasThomas
1,652525
1,652525
1
Whats the parent of article element? Would be great if you can share relevant DOM
– Milind Anantwar
Nov 22 '18 at 14:08
You can produce a list of all elements that are not a child of an article.querySelectorAll(':not(article)>*')
but you really mean a list of all elements that are not a descendant of an article, right?
– Mr Lister
Nov 22 '18 at 14:10
add a comment |
1
Whats the parent of article element? Would be great if you can share relevant DOM
– Milind Anantwar
Nov 22 '18 at 14:08
You can produce a list of all elements that are not a child of an article.querySelectorAll(':not(article)>*')
but you really mean a list of all elements that are not a descendant of an article, right?
– Mr Lister
Nov 22 '18 at 14:10
1
1
Whats the parent of article element? Would be great if you can share relevant DOM
– Milind Anantwar
Nov 22 '18 at 14:08
Whats the parent of article element? Would be great if you can share relevant DOM
– Milind Anantwar
Nov 22 '18 at 14:08
You can produce a list of all elements that are not a child of an article.
querySelectorAll(':not(article)>*')
but you really mean a list of all elements that are not a descendant of an article, right?– Mr Lister
Nov 22 '18 at 14:10
You can produce a list of all elements that are not a child of an article.
querySelectorAll(':not(article)>*')
but you really mean a list of all elements that are not a descendant of an article, right?– Mr Lister
Nov 22 '18 at 14:10
add a comment |
2 Answers
2
active
oldest
votes
Answer is a modification of Mohammad's. The difference is that this code is not using filter
, it is using not
:
$('form.frm').not('article form.frm')
This is more or less the same thing. You specify a global selector, then exclude the forms
you do not want (in this case, any form
that is a descendent of article
).
$('form.frm').not('article form.frm').css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Thanks, now the question, which solution is faster. Using the .not function or the filter with the .closest. I would assume the former...
– Thomas
Nov 22 '18 at 14:42
add a comment |
Use .closest()
to find any article
parent of element and check if length of selector is 0
.
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Also you can select all .frm
and use .not()
to exclude
all element has article
parent.
$('.frm').not($('article').find('.frm')).css('color', 'red');
I just found this solution as well, but still wondering if there is a way to achieve this without filter
– Thomas
Nov 22 '18 at 14:33
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Answer is a modification of Mohammad's. The difference is that this code is not using filter
, it is using not
:
$('form.frm').not('article form.frm')
This is more or less the same thing. You specify a global selector, then exclude the forms
you do not want (in this case, any form
that is a descendent of article
).
$('form.frm').not('article form.frm').css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Thanks, now the question, which solution is faster. Using the .not function or the filter with the .closest. I would assume the former...
– Thomas
Nov 22 '18 at 14:42
add a comment |
Answer is a modification of Mohammad's. The difference is that this code is not using filter
, it is using not
:
$('form.frm').not('article form.frm')
This is more or less the same thing. You specify a global selector, then exclude the forms
you do not want (in this case, any form
that is a descendent of article
).
$('form.frm').not('article form.frm').css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Thanks, now the question, which solution is faster. Using the .not function or the filter with the .closest. I would assume the former...
– Thomas
Nov 22 '18 at 14:42
add a comment |
Answer is a modification of Mohammad's. The difference is that this code is not using filter
, it is using not
:
$('form.frm').not('article form.frm')
This is more or less the same thing. You specify a global selector, then exclude the forms
you do not want (in this case, any form
that is a descendent of article
).
$('form.frm').not('article form.frm').css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Answer is a modification of Mohammad's. The difference is that this code is not using filter
, it is using not
:
$('form.frm').not('article form.frm')
This is more or less the same thing. You specify a global selector, then exclude the forms
you do not want (in this case, any form
that is a descendent of article
).
$('form.frm').not('article form.frm').css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
$('form.frm').not('article form.frm').css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
$('form.frm').not('article form.frm').css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
answered Nov 22 '18 at 14:37
Richard Parnaby-KingRichard Parnaby-King
9,686857110
9,686857110
Thanks, now the question, which solution is faster. Using the .not function or the filter with the .closest. I would assume the former...
– Thomas
Nov 22 '18 at 14:42
add a comment |
Thanks, now the question, which solution is faster. Using the .not function or the filter with the .closest. I would assume the former...
– Thomas
Nov 22 '18 at 14:42
Thanks, now the question, which solution is faster. Using the .not function or the filter with the .closest. I would assume the former...
– Thomas
Nov 22 '18 at 14:42
Thanks, now the question, which solution is faster. Using the .not function or the filter with the .closest. I would assume the former...
– Thomas
Nov 22 '18 at 14:42
add a comment |
Use .closest()
to find any article
parent of element and check if length of selector is 0
.
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Also you can select all .frm
and use .not()
to exclude
all element has article
parent.
$('.frm').not($('article').find('.frm')).css('color', 'red');
I just found this solution as well, but still wondering if there is a way to achieve this without filter
– Thomas
Nov 22 '18 at 14:33
add a comment |
Use .closest()
to find any article
parent of element and check if length of selector is 0
.
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Also you can select all .frm
and use .not()
to exclude
all element has article
parent.
$('.frm').not($('article').find('.frm')).css('color', 'red');
I just found this solution as well, but still wondering if there is a way to achieve this without filter
– Thomas
Nov 22 '18 at 14:33
add a comment |
Use .closest()
to find any article
parent of element and check if length of selector is 0
.
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Also you can select all .frm
and use .not()
to exclude
all element has article
parent.
$('.frm').not($('article').find('.frm')).css('color', 'red');
Use .closest()
to find any article
parent of element and check if length of selector is 0
.
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
Also you can select all .frm
and use .not()
to exclude
all element has article
parent.
$('.frm').not($('article').find('.frm')).css('color', 'red');
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
$('form.frm').filter(function() {
return $(this).closest('article').length == 0;
}).css('color', 'red');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="pageContent">
<article>
<div class="box">
<form class="frm">article > div</form>
</div>
</article>
<article>
<form class="frm">article</form>
</article>
<div class="box">
<form class="frm">div</form>
</div>
</div>
edited Nov 22 '18 at 14:37
answered Nov 22 '18 at 14:32
MohammadMohammad
15.5k123461
15.5k123461
I just found this solution as well, but still wondering if there is a way to achieve this without filter
– Thomas
Nov 22 '18 at 14:33
add a comment |
I just found this solution as well, but still wondering if there is a way to achieve this without filter
– Thomas
Nov 22 '18 at 14:33
I just found this solution as well, but still wondering if there is a way to achieve this without filter
– Thomas
Nov 22 '18 at 14:33
I just found this solution as well, but still wondering if there is a way to achieve this without filter
– Thomas
Nov 22 '18 at 14:33
add a comment |
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1
Whats the parent of article element? Would be great if you can share relevant DOM
– Milind Anantwar
Nov 22 '18 at 14:08
You can produce a list of all elements that are not a child of an article.
querySelectorAll(':not(article)>*')
but you really mean a list of all elements that are not a descendant of an article, right?– Mr Lister
Nov 22 '18 at 14:10