make a javafx graphic interface show and hide by sending commands through a socket
0
Right now the solution I have is having a queue, and when something comes through the socket putting it the queue and then call stage.hide() or stage.show() depending what it is. But i´m having problem with the implementation. I have something like this:
private BlockingQueue<String> requests;
private Stage primaryStage;
public GraficInterface() {
requests = new LinkedBlockingQueue<String>();
}
@Override
public void start(Stage sp) {
try {
this.primaryStage = sp;
Parent root = FXMLLoader.load(getClass().getResource(...));
Scene scene = new Scene(root);
primaryStage.setScene(scene);
primaryStage.sizeToScene();
primaryStage.show();
} catch(Exception e) {
e.printStackTrace();
}
}
@Override
public void run() {
Thread stopper = new Thread(new Runnable() {
public void run() {
String message;
while (true) {
try {
message = requests.take();
if (message.equalsIgnoreCase("show")) {
primaryStage.show();
} else if (message.equalsIgnoreCase("hide")) {
primaryStage.hide();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
});
stopper.start();
launch();
}
public void addToGraficThread(String string) {
try {
this.requests.put(string);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
Things are working fine with the queue but I´m getting java.lang.NullPointerException when I do primaryStage.show() or primaryStage.hide()
What I´m trying to do it´s possible? Is there another way?
java javafx
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
add a comment |
0
Right now the solution I have is having a queue, and when something comes through the socket putting it the queue and then call stage.hide() or stage.show() depending what it is. But i´m having problem with the implementation. I have something like this:
private BlockingQueue<String> requests;
private Stage primaryStage;
public GraficInterface() {
requests = new LinkedBlockingQueue<String>();
}
@Override
public void start(Stage sp) {
try {
this.primaryStage = sp;
Parent root = FXMLLoader.load(getClass().getResource(...));
Scene scene = new Scene(root);
primaryStage.setScene(scene);
primaryStage.sizeToScene();
primaryStage.show();
} catch(Exception e) {
e.printStackTrace();
}
}
@Override
public void run() {
Thread stopper = new Thread(new Runnable() {
public void run() {
String message;
while (true) {
try {
message = requests.take();
if (message.equalsIgnoreCase("show")) {
primaryStage.show();
} else if (message.equalsIgnoreCase("hide")) {
primaryStage.hide();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
});
stopper.start();
launch();
}
public void addToGraficThread(String string) {
try {
this.requests.put(string);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
Things are working fine with the queue but I´m getting java.lang.NullPointerException when I do primaryStage.show() or primaryStage.hide()
What I´m trying to do it´s possible? Is there another way?
java javafx
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
You create another instance of yourApplicationclass when callingApplication.launch. In addition to thisApplication.launchis responsible for creating the primary stage and invoking thestartmethod, which means even if you fix the issue mentioned before, cannot be sure the field has been set from thestartmethod (in addition to not ensuring the new field value will eventually be available to the thread and modifying the GUI from a background thread).
– fabian
Nov 22 '18 at 20:36
mmmm, so this is not posible? could I Platform.exit() and then launch it again?
– daniel gon
Nov 23 '18 at 13:59
TheApplicationclass is the entry point of a javafx app, not just responsible for a single window. Many of your issues could be resolved by simply using thestartmethod to start to launch a thread starting/handling the socket connection. I recommend using aTask<Boolean>though, since it provides functionality for doing updates of it'svalueproperty on the JavaFX application thread. Exiting and relaunching won't work btw.
– fabian
Nov 23 '18 at 14:06
add a comment |
0
0
0
Right now the solution I have is having a queue, and when something comes through the socket putting it the queue and then call stage.hide() or stage.show() depending what it is. But i´m having problem with the implementation. I have something like this:
private BlockingQueue<String> requests;
private Stage primaryStage;
public GraficInterface() {
requests = new LinkedBlockingQueue<String>();
}
@Override
public void start(Stage sp) {
try {
this.primaryStage = sp;
Parent root = FXMLLoader.load(getClass().getResource(...));
Scene scene = new Scene(root);
primaryStage.setScene(scene);
primaryStage.sizeToScene();
primaryStage.show();
} catch(Exception e) {
e.printStackTrace();
}
}
@Override
public void run() {
Thread stopper = new Thread(new Runnable() {
public void run() {
String message;
while (true) {
try {
message = requests.take();
if (message.equalsIgnoreCase("show")) {
primaryStage.show();
} else if (message.equalsIgnoreCase("hide")) {
primaryStage.hide();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
});
stopper.start();
launch();
}
public void addToGraficThread(String string) {
try {
this.requests.put(string);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
Things are working fine with the queue but I´m getting java.lang.NullPointerException when I do primaryStage.show() or primaryStage.hide()
What I´m trying to do it´s possible? Is there another way?
java javafx
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
Right now the solution I have is having a queue, and when something comes through the socket putting it the queue and then call stage.hide() or stage.show() depending what it is. But i´m having problem with the implementation. I have something like this:
private BlockingQueue<String> requests;
private Stage primaryStage;
public GraficInterface() {
requests = new LinkedBlockingQueue<String>();
}
@Override
public void start(Stage sp) {
try {
this.primaryStage = sp;
Parent root = FXMLLoader.load(getClass().getResource(...));
Scene scene = new Scene(root);
primaryStage.setScene(scene);
primaryStage.sizeToScene();
primaryStage.show();
} catch(Exception e) {
e.printStackTrace();
}
}
@Override
public void run() {
Thread stopper = new Thread(new Runnable() {
public void run() {
String message;
while (true) {
try {
message = requests.take();
if (message.equalsIgnoreCase("show")) {
primaryStage.show();
} else if (message.equalsIgnoreCase("hide")) {
primaryStage.hide();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
});
stopper.start();
launch();
}
public void addToGraficThread(String string) {
try {
this.requests.put(string);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
Things are working fine with the queue but I´m getting java.lang.NullPointerException when I do primaryStage.show() or primaryStage.hide()
What I´m trying to do it´s possible? Is there another way?
java javafx
java javafx
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
asked Nov 22 '18 at 20:19
daniel gondaniel gon
496
496
You create another instance of yourApplicationclass when callingApplication.launch. In addition to thisApplication.launchis responsible for creating the primary stage and invoking thestartmethod, which means even if you fix the issue mentioned before, cannot be sure the field has been set from thestartmethod (in addition to not ensuring the new field value will eventually be available to the thread and modifying the GUI from a background thread).
– fabian
Nov 22 '18 at 20:36
mmmm, so this is not posible? could I Platform.exit() and then launch it again?
– daniel gon
Nov 23 '18 at 13:59
TheApplicationclass is the entry point of a javafx app, not just responsible for a single window. Many of your issues could be resolved by simply using thestartmethod to start to launch a thread starting/handling the socket connection. I recommend using aTask<Boolean>though, since it provides functionality for doing updates of it'svalueproperty on the JavaFX application thread. Exiting and relaunching won't work btw.
– fabian
Nov 23 '18 at 14:06
add a comment |
You create another instance of yourApplicationclass when callingApplication.launch. In addition to thisApplication.launchis responsible for creating the primary stage and invoking thestartmethod, which means even if you fix the issue mentioned before, cannot be sure the field has been set from thestartmethod (in addition to not ensuring the new field value will eventually be available to the thread and modifying the GUI from a background thread).
– fabian
Nov 22 '18 at 20:36
mmmm, so this is not posible? could I Platform.exit() and then launch it again?
– daniel gon
Nov 23 '18 at 13:59
TheApplicationclass is the entry point of a javafx app, not just responsible for a single window. Many of your issues could be resolved by simply using thestartmethod to start to launch a thread starting/handling the socket connection. I recommend using aTask<Boolean>though, since it provides functionality for doing updates of it'svalueproperty on the JavaFX application thread. Exiting and relaunching won't work btw.
– fabian
Nov 23 '18 at 14:06
You create another instance of your
Application class when calling Application.launch. In addition to this Application.launch is responsible for creating the primary stage and invoking the start method, which means even if you fix the issue mentioned before, cannot be sure the field has been set from the start method (in addition to not ensuring the new field value will eventually be available to the thread and modifying the GUI from a background thread).– fabian
Nov 22 '18 at 20:36
You create another instance of your
Application class when calling Application.launch. In addition to this Application.launch is responsible for creating the primary stage and invoking the start method, which means even if you fix the issue mentioned before, cannot be sure the field has been set from the start method (in addition to not ensuring the new field value will eventually be available to the thread and modifying the GUI from a background thread).– fabian
Nov 22 '18 at 20:36
mmmm, so this is not posible? could I Platform.exit() and then launch it again?
– daniel gon
Nov 23 '18 at 13:59
mmmm, so this is not posible? could I Platform.exit() and then launch it again?
– daniel gon
Nov 23 '18 at 13:59
The
Application class is the entry point of a javafx app, not just responsible for a single window. Many of your issues could be resolved by simply using the start method to start to launch a thread starting/handling the socket connection. I recommend using a Task<Boolean> though, since it provides functionality for doing updates of it's value property on the JavaFX application thread. Exiting and relaunching won't work btw.– fabian
Nov 23 '18 at 14:06
The
Application class is the entry point of a javafx app, not just responsible for a single window. Many of your issues could be resolved by simply using the start method to start to launch a thread starting/handling the socket connection. I recommend using a Task<Boolean> though, since it provides functionality for doing updates of it's value property on the JavaFX application thread. Exiting and relaunching won't work btw.– fabian
Nov 23 '18 at 14:06
add a comment |
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You create another instance of your
Applicationclass when callingApplication.launch. In addition to thisApplication.launchis responsible for creating the primary stage and invoking thestartmethod, which means even if you fix the issue mentioned before, cannot be sure the field has been set from thestartmethod (in addition to not ensuring the new field value will eventually be available to the thread and modifying the GUI from a background thread).– fabian
Nov 22 '18 at 20:36
mmmm, so this is not posible? could I Platform.exit() and then launch it again?
– daniel gon
Nov 23 '18 at 13:59
The
Applicationclass is the entry point of a javafx app, not just responsible for a single window. Many of your issues could be resolved by simply using thestartmethod to start to launch a thread starting/handling the socket connection. I recommend using aTask<Boolean>though, since it provides functionality for doing updates of it'svalueproperty on the JavaFX application thread. Exiting and relaunching won't work btw.– fabian
Nov 23 '18 at 14:06