Parse CSV in Google Spreadsheets












0















I'm trying to automatically parse a CSV document into separate cells in Google Spreadsheets. I'm using the script below, however, it just presents the , separated value, whereas, I need those values appear in individual cells. Any ideas?



function importCSVFromWeb() {
var csvUrl = "https://ctrlq.org/data.csv";
var csvContent = UrlFetchApp.fetch(csvUrl).getContentText();
var csvData = Utilities.parseCsv(csvContent);
var sheet = SpreadsheetApp.getActiveSheet();
sheet.getRange(1, 1, csvData.length, csvData[0].length).setValues(csvData);
}









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  • 3





    Welcome to Stack Overflow. Consider editing your question. Avoid unnecessary bolding your text and post your code here instead of a link to an image. stackoverflow.com/help/how-to-ask

    – ETO
    Nov 22 '18 at 22:54








  • 1





    add code as text, not as image

    – barbsan
    Nov 23 '18 at 10:40











  • @barbsan thanks for the tip. Done. Would you know how the problem I described can be solved?

    – Renat Ishmukhamedov
    Nov 28 '18 at 14:20











  • Have you tried passing delimiter? Like Utilities.parseCsv(csvContent, ",");

    – barbsan
    Nov 28 '18 at 14:24













  • @RenatIshmukhamedov I've run your code and it works perfectly. The problem is probably in your csv file, and you need to share it, or a sample of it, so we can understand the layout and any issues. I'm assuming that you are NOT using the csvUrl above, because it doesn't exist.

    – Tedinoz
    Dec 6 '18 at 3:41


















0















I'm trying to automatically parse a CSV document into separate cells in Google Spreadsheets. I'm using the script below, however, it just presents the , separated value, whereas, I need those values appear in individual cells. Any ideas?



function importCSVFromWeb() {
var csvUrl = "https://ctrlq.org/data.csv";
var csvContent = UrlFetchApp.fetch(csvUrl).getContentText();
var csvData = Utilities.parseCsv(csvContent);
var sheet = SpreadsheetApp.getActiveSheet();
sheet.getRange(1, 1, csvData.length, csvData[0].length).setValues(csvData);
}









share|improve this question




















  • 3





    Welcome to Stack Overflow. Consider editing your question. Avoid unnecessary bolding your text and post your code here instead of a link to an image. stackoverflow.com/help/how-to-ask

    – ETO
    Nov 22 '18 at 22:54








  • 1





    add code as text, not as image

    – barbsan
    Nov 23 '18 at 10:40











  • @barbsan thanks for the tip. Done. Would you know how the problem I described can be solved?

    – Renat Ishmukhamedov
    Nov 28 '18 at 14:20











  • Have you tried passing delimiter? Like Utilities.parseCsv(csvContent, ",");

    – barbsan
    Nov 28 '18 at 14:24













  • @RenatIshmukhamedov I've run your code and it works perfectly. The problem is probably in your csv file, and you need to share it, or a sample of it, so we can understand the layout and any issues. I'm assuming that you are NOT using the csvUrl above, because it doesn't exist.

    – Tedinoz
    Dec 6 '18 at 3:41
















0












0








0








I'm trying to automatically parse a CSV document into separate cells in Google Spreadsheets. I'm using the script below, however, it just presents the , separated value, whereas, I need those values appear in individual cells. Any ideas?



function importCSVFromWeb() {
var csvUrl = "https://ctrlq.org/data.csv";
var csvContent = UrlFetchApp.fetch(csvUrl).getContentText();
var csvData = Utilities.parseCsv(csvContent);
var sheet = SpreadsheetApp.getActiveSheet();
sheet.getRange(1, 1, csvData.length, csvData[0].length).setValues(csvData);
}









share|improve this question
















I'm trying to automatically parse a CSV document into separate cells in Google Spreadsheets. I'm using the script below, however, it just presents the , separated value, whereas, I need those values appear in individual cells. Any ideas?



function importCSVFromWeb() {
var csvUrl = "https://ctrlq.org/data.csv";
var csvContent = UrlFetchApp.fetch(csvUrl).getContentText();
var csvData = Utilities.parseCsv(csvContent);
var sheet = SpreadsheetApp.getActiveSheet();
sheet.getRange(1, 1, csvData.length, csvData[0].length).setValues(csvData);
}






google-apps-script google-sheets






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 28 '18 at 14:19







Renat Ishmukhamedov

















asked Nov 22 '18 at 21:58









Renat IshmukhamedovRenat Ishmukhamedov

11




11








  • 3





    Welcome to Stack Overflow. Consider editing your question. Avoid unnecessary bolding your text and post your code here instead of a link to an image. stackoverflow.com/help/how-to-ask

    – ETO
    Nov 22 '18 at 22:54








  • 1





    add code as text, not as image

    – barbsan
    Nov 23 '18 at 10:40











  • @barbsan thanks for the tip. Done. Would you know how the problem I described can be solved?

    – Renat Ishmukhamedov
    Nov 28 '18 at 14:20











  • Have you tried passing delimiter? Like Utilities.parseCsv(csvContent, ",");

    – barbsan
    Nov 28 '18 at 14:24













  • @RenatIshmukhamedov I've run your code and it works perfectly. The problem is probably in your csv file, and you need to share it, or a sample of it, so we can understand the layout and any issues. I'm assuming that you are NOT using the csvUrl above, because it doesn't exist.

    – Tedinoz
    Dec 6 '18 at 3:41
















  • 3





    Welcome to Stack Overflow. Consider editing your question. Avoid unnecessary bolding your text and post your code here instead of a link to an image. stackoverflow.com/help/how-to-ask

    – ETO
    Nov 22 '18 at 22:54








  • 1





    add code as text, not as image

    – barbsan
    Nov 23 '18 at 10:40











  • @barbsan thanks for the tip. Done. Would you know how the problem I described can be solved?

    – Renat Ishmukhamedov
    Nov 28 '18 at 14:20











  • Have you tried passing delimiter? Like Utilities.parseCsv(csvContent, ",");

    – barbsan
    Nov 28 '18 at 14:24













  • @RenatIshmukhamedov I've run your code and it works perfectly. The problem is probably in your csv file, and you need to share it, or a sample of it, so we can understand the layout and any issues. I'm assuming that you are NOT using the csvUrl above, because it doesn't exist.

    – Tedinoz
    Dec 6 '18 at 3:41










3




3





Welcome to Stack Overflow. Consider editing your question. Avoid unnecessary bolding your text and post your code here instead of a link to an image. stackoverflow.com/help/how-to-ask

– ETO
Nov 22 '18 at 22:54







Welcome to Stack Overflow. Consider editing your question. Avoid unnecessary bolding your text and post your code here instead of a link to an image. stackoverflow.com/help/how-to-ask

– ETO
Nov 22 '18 at 22:54






1




1





add code as text, not as image

– barbsan
Nov 23 '18 at 10:40





add code as text, not as image

– barbsan
Nov 23 '18 at 10:40













@barbsan thanks for the tip. Done. Would you know how the problem I described can be solved?

– Renat Ishmukhamedov
Nov 28 '18 at 14:20





@barbsan thanks for the tip. Done. Would you know how the problem I described can be solved?

– Renat Ishmukhamedov
Nov 28 '18 at 14:20













Have you tried passing delimiter? Like Utilities.parseCsv(csvContent, ",");

– barbsan
Nov 28 '18 at 14:24







Have you tried passing delimiter? Like Utilities.parseCsv(csvContent, ",");

– barbsan
Nov 28 '18 at 14:24















@RenatIshmukhamedov I've run your code and it works perfectly. The problem is probably in your csv file, and you need to share it, or a sample of it, so we can understand the layout and any issues. I'm assuming that you are NOT using the csvUrl above, because it doesn't exist.

– Tedinoz
Dec 6 '18 at 3:41







@RenatIshmukhamedov I've run your code and it works perfectly. The problem is probably in your csv file, and you need to share it, or a sample of it, so we can understand the layout and any issues. I'm assuming that you are NOT using the csvUrl above, because it doesn't exist.

– Tedinoz
Dec 6 '18 at 3:41














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