Dynamically get different colors while building stacked bar graph in d3
I am trying to read a csv file in D3 and trying to build stacked bar graphs with 2 attributes, in the csv file I don't know how many unique values exist for a particular attribute. So depending on number of unique attributes I need that many different colors to draw stacked bar graph.
Is there any way to get different colors given an integer n like 10 or 15 in D3 or javascript?
javascript d3.js
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
asked Nov 20 at 21:31
Labeo
1,90752956
add a comment |
I am trying to read a csv file in D3 and trying to build stacked bar graphs with 2 attributes, in the csv file I don't know how many unique values exist for a particular attribute. So depending on number of unique attributes I need that many different colors to draw stacked bar graph.
Is there any way to get different colors given an integer n like 10 or 15 in D3 or javascript?
javascript d3.js
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
asked Nov 20 at 21:31
Labeo
1,90752956
read github.com/d3/d3-scale-chromatic, use the sequential colors or sample the rainbow scemes n times using a scaleLinear
– rioV8
Nov 21 at 0:15
add a comment |
I am trying to read a csv file in D3 and trying to build stacked bar graphs with 2 attributes, in the csv file I don't know how many unique values exist for a particular attribute. So depending on number of unique attributes I need that many different colors to draw stacked bar graph.
Is there any way to get different colors given an integer n like 10 or 15 in D3 or javascript?
javascript d3.js
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
asked Nov 20 at 21:31
Labeo
1,90752956
I am trying to read a csv file in D3 and trying to build stacked bar graphs with 2 attributes, in the csv file I don't know how many unique values exist for a particular attribute. So depending on number of unique attributes I need that many different colors to draw stacked bar graph.
Is there any way to get different colors given an integer n like 10 or 15 in D3 or javascript?
javascript d3.js
javascript d3.js
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
asked Nov 20 at 21:31
Labeo
1,90752956
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
asked Nov 20 at 21:31
Labeo
1,90752956
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
edited Nov 20 at 21:56
Pritam Banerjee
10.6k64364
10.6k64364
asked Nov 20 at 21:31
Labeo
1,90752956
asked Nov 20 at 21:31
Labeo
1,90752956
asked Nov 20 at 21:31
Labeo
1,90752956
1,90752956
read github.com/d3/d3-scale-chromatic, use the sequential colors or sample the rainbow scemes n times using a scaleLinear
– rioV8
Nov 21 at 0:15
add a comment |
read github.com/d3/d3-scale-chromatic, use the sequential colors or sample the rainbow scemes n times using a scaleLinear
– rioV8
Nov 21 at 0:15
read github.com/d3/d3-scale-chromatic, use the sequential colors or sample the rainbow scemes n times using a scaleLinear
– rioV8
Nov 21 at 0:15
read github.com/d3/d3-scale-chromatic, use the sequential colors or sample the rainbow scemes n times using a scaleLinear
– rioV8
Nov 21 at 0:15
add a comment |
1 Answer
1
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votes
You may try the following approach:
function generatePallete(n) {
const scale = t => d3.interpolateSinebow(t * 0.85);
return d3.range(n).map(i => scale(i / n))
}
You can replace d3.interpolateSinebow with any other sequential scale. I multiplied t by 0.85 because d3.interpolateSinebow is cyclical and start end end colors are the same.
Here is an example of generated palletes:
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may try the following approach:
function generatePallete(n) {
const scale = t => d3.interpolateSinebow(t * 0.85);
return d3.range(n).map(i => scale(i / n))
}
You can replace d3.interpolateSinebow with any other sequential scale. I multiplied t by 0.85 because d3.interpolateSinebow is cyclical and start end end colors are the same.
Here is an example of generated palletes:
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
add a comment |
You may try the following approach:
function generatePallete(n) {
const scale = t => d3.interpolateSinebow(t * 0.85);
return d3.range(n).map(i => scale(i / n))
}
You can replace d3.interpolateSinebow with any other sequential scale. I multiplied t by 0.85 because d3.interpolateSinebow is cyclical and start end end colors are the same.
Here is an example of generated palletes:
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
add a comment |
You may try the following approach:
function generatePallete(n) {
const scale = t => d3.interpolateSinebow(t * 0.85);
return d3.range(n).map(i => scale(i / n))
}
You can replace d3.interpolateSinebow with any other sequential scale. I multiplied t by 0.85 because d3.interpolateSinebow is cyclical and start end end colors are the same.
Here is an example of generated palletes:
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
You may try the following approach:
function generatePallete(n) {
const scale = t => d3.interpolateSinebow(t * 0.85);
return d3.range(n).map(i => scale(i / n))
}
You can replace d3.interpolateSinebow with any other sequential scale. I multiplied t by 0.85 because d3.interpolateSinebow is cyclical and start end end colors are the same.
Here is an example of generated palletes:
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
edited Nov 21 at 14:46
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
answered Nov 21 at 12:38
Yaroslav Sergienko
40016
40016
add a comment |
add a comment |
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read github.com/d3/d3-scale-chromatic, use the sequential colors or sample the rainbow scemes n times using a scaleLinear
– rioV8
Nov 21 at 0:15