For $H$ the orthocenter of $triangle ABC$, prove $|AH|h_a+|BH|h_b+|CH|h_c=frac12left(a^2+b^2+c^2right)$...












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Given acute $triangle ABC$ with orthocenter $H$, prove $$|AH|,h_a+|BH|,h_b+|CH|,h_c=frac12left(a^2+b^2+c^2right)$$




I tried to do something with the perimeter, area, half-perimeter, but I can't solve it. I am not good at contest problems, and I just started practicing. I'll be glad if I get an answer or just guidelines. I couldn't seem to find this problem solved or guidelines for it anywhere.










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closed as off-topic by T. Bongers, Théophile, KReiser, Alexander Gruber Nov 30 at 3:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – T. Bongers, Théophile, KReiser, Alexander Gruber

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Welcome to MSE. What work have you done so far?
    – Théophile
    Nov 29 at 21:00










  • Please define all objects that appear, starting with the triangle and $ha$ (which may be some $h_a$, typed as h_a in LaTeX), in the text, not (only) in the title. Then please show the own efforts to solve. Else there are some people that downvote from the start.
    – dan_fulea
    Nov 29 at 21:01










  • If you don't want your question to get downvoted, you should include more context such as your own attempt at a solution. math.meta.stackexchange.com/questions/26017/…
    – Ryan Greyling
    Nov 29 at 21:02










  • What are $h_a$, $h_b$, $h_c$? Are they the lengths of the altitudes from $A$, $B$, $C$?
    – Blue
    Nov 29 at 21:18










  • I believe so. It wasn't specified in the problem.
    – Pero
    Nov 29 at 21:20
















0















Given acute $triangle ABC$ with orthocenter $H$, prove $$|AH|,h_a+|BH|,h_b+|CH|,h_c=frac12left(a^2+b^2+c^2right)$$




I tried to do something with the perimeter, area, half-perimeter, but I can't solve it. I am not good at contest problems, and I just started practicing. I'll be glad if I get an answer or just guidelines. I couldn't seem to find this problem solved or guidelines for it anywhere.










share|cite|improve this question















closed as off-topic by T. Bongers, Théophile, KReiser, Alexander Gruber Nov 30 at 3:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – T. Bongers, Théophile, KReiser, Alexander Gruber

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Welcome to MSE. What work have you done so far?
    – Théophile
    Nov 29 at 21:00










  • Please define all objects that appear, starting with the triangle and $ha$ (which may be some $h_a$, typed as h_a in LaTeX), in the text, not (only) in the title. Then please show the own efforts to solve. Else there are some people that downvote from the start.
    – dan_fulea
    Nov 29 at 21:01










  • If you don't want your question to get downvoted, you should include more context such as your own attempt at a solution. math.meta.stackexchange.com/questions/26017/…
    – Ryan Greyling
    Nov 29 at 21:02










  • What are $h_a$, $h_b$, $h_c$? Are they the lengths of the altitudes from $A$, $B$, $C$?
    – Blue
    Nov 29 at 21:18










  • I believe so. It wasn't specified in the problem.
    – Pero
    Nov 29 at 21:20














0












0








0








Given acute $triangle ABC$ with orthocenter $H$, prove $$|AH|,h_a+|BH|,h_b+|CH|,h_c=frac12left(a^2+b^2+c^2right)$$




I tried to do something with the perimeter, area, half-perimeter, but I can't solve it. I am not good at contest problems, and I just started practicing. I'll be glad if I get an answer or just guidelines. I couldn't seem to find this problem solved or guidelines for it anywhere.










share|cite|improve this question
















Given acute $triangle ABC$ with orthocenter $H$, prove $$|AH|,h_a+|BH|,h_b+|CH|,h_c=frac12left(a^2+b^2+c^2right)$$




I tried to do something with the perimeter, area, half-perimeter, but I can't solve it. I am not good at contest problems, and I just started practicing. I'll be glad if I get an answer or just guidelines. I couldn't seem to find this problem solved or guidelines for it anywhere.







geometry






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edited Nov 29 at 21:17









Blue

47.6k870151




47.6k870151










asked Nov 29 at 20:54









Pero

1307




1307




closed as off-topic by T. Bongers, Théophile, KReiser, Alexander Gruber Nov 30 at 3:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – T. Bongers, Théophile, KReiser, Alexander Gruber

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by T. Bongers, Théophile, KReiser, Alexander Gruber Nov 30 at 3:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – T. Bongers, Théophile, KReiser, Alexander Gruber

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Welcome to MSE. What work have you done so far?
    – Théophile
    Nov 29 at 21:00










  • Please define all objects that appear, starting with the triangle and $ha$ (which may be some $h_a$, typed as h_a in LaTeX), in the text, not (only) in the title. Then please show the own efforts to solve. Else there are some people that downvote from the start.
    – dan_fulea
    Nov 29 at 21:01










  • If you don't want your question to get downvoted, you should include more context such as your own attempt at a solution. math.meta.stackexchange.com/questions/26017/…
    – Ryan Greyling
    Nov 29 at 21:02










  • What are $h_a$, $h_b$, $h_c$? Are they the lengths of the altitudes from $A$, $B$, $C$?
    – Blue
    Nov 29 at 21:18










  • I believe so. It wasn't specified in the problem.
    – Pero
    Nov 29 at 21:20


















  • Welcome to MSE. What work have you done so far?
    – Théophile
    Nov 29 at 21:00










  • Please define all objects that appear, starting with the triangle and $ha$ (which may be some $h_a$, typed as h_a in LaTeX), in the text, not (only) in the title. Then please show the own efforts to solve. Else there are some people that downvote from the start.
    – dan_fulea
    Nov 29 at 21:01










  • If you don't want your question to get downvoted, you should include more context such as your own attempt at a solution. math.meta.stackexchange.com/questions/26017/…
    – Ryan Greyling
    Nov 29 at 21:02










  • What are $h_a$, $h_b$, $h_c$? Are they the lengths of the altitudes from $A$, $B$, $C$?
    – Blue
    Nov 29 at 21:18










  • I believe so. It wasn't specified in the problem.
    – Pero
    Nov 29 at 21:20
















Welcome to MSE. What work have you done so far?
– Théophile
Nov 29 at 21:00




Welcome to MSE. What work have you done so far?
– Théophile
Nov 29 at 21:00












Please define all objects that appear, starting with the triangle and $ha$ (which may be some $h_a$, typed as h_a in LaTeX), in the text, not (only) in the title. Then please show the own efforts to solve. Else there are some people that downvote from the start.
– dan_fulea
Nov 29 at 21:01




Please define all objects that appear, starting with the triangle and $ha$ (which may be some $h_a$, typed as h_a in LaTeX), in the text, not (only) in the title. Then please show the own efforts to solve. Else there are some people that downvote from the start.
– dan_fulea
Nov 29 at 21:01












If you don't want your question to get downvoted, you should include more context such as your own attempt at a solution. math.meta.stackexchange.com/questions/26017/…
– Ryan Greyling
Nov 29 at 21:02




If you don't want your question to get downvoted, you should include more context such as your own attempt at a solution. math.meta.stackexchange.com/questions/26017/…
– Ryan Greyling
Nov 29 at 21:02












What are $h_a$, $h_b$, $h_c$? Are they the lengths of the altitudes from $A$, $B$, $C$?
– Blue
Nov 29 at 21:18




What are $h_a$, $h_b$, $h_c$? Are they the lengths of the altitudes from $A$, $B$, $C$?
– Blue
Nov 29 at 21:18












I believe so. It wasn't specified in the problem.
– Pero
Nov 29 at 21:20




I believe so. It wasn't specified in the problem.
– Pero
Nov 29 at 21:20










1 Answer
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If $A',B',C'$ are feet of the altitudes, from $ABA'sim AHC'$ we have $AHcdot h_a= ABcdot AC'$. Similarly, from $BAB'sim BHC'$, $BHcdot h_b= ABcdot BC'$ follows. By adding we have $AHcdot h_a+BHcdot h_b=AB(AC'+BC')= AB^2=c^2$. By symmetry, $BHcdot h_b+CHcdot h_c= a^2$ and $AHcdot h_a+CHcdot h_c= b^2$. Now just add these three equations.






share|cite|improve this answer




























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    If $A',B',C'$ are feet of the altitudes, from $ABA'sim AHC'$ we have $AHcdot h_a= ABcdot AC'$. Similarly, from $BAB'sim BHC'$, $BHcdot h_b= ABcdot BC'$ follows. By adding we have $AHcdot h_a+BHcdot h_b=AB(AC'+BC')= AB^2=c^2$. By symmetry, $BHcdot h_b+CHcdot h_c= a^2$ and $AHcdot h_a+CHcdot h_c= b^2$. Now just add these three equations.






    share|cite|improve this answer


























      2














      If $A',B',C'$ are feet of the altitudes, from $ABA'sim AHC'$ we have $AHcdot h_a= ABcdot AC'$. Similarly, from $BAB'sim BHC'$, $BHcdot h_b= ABcdot BC'$ follows. By adding we have $AHcdot h_a+BHcdot h_b=AB(AC'+BC')= AB^2=c^2$. By symmetry, $BHcdot h_b+CHcdot h_c= a^2$ and $AHcdot h_a+CHcdot h_c= b^2$. Now just add these three equations.






      share|cite|improve this answer
























        2












        2








        2






        If $A',B',C'$ are feet of the altitudes, from $ABA'sim AHC'$ we have $AHcdot h_a= ABcdot AC'$. Similarly, from $BAB'sim BHC'$, $BHcdot h_b= ABcdot BC'$ follows. By adding we have $AHcdot h_a+BHcdot h_b=AB(AC'+BC')= AB^2=c^2$. By symmetry, $BHcdot h_b+CHcdot h_c= a^2$ and $AHcdot h_a+CHcdot h_c= b^2$. Now just add these three equations.






        share|cite|improve this answer












        If $A',B',C'$ are feet of the altitudes, from $ABA'sim AHC'$ we have $AHcdot h_a= ABcdot AC'$. Similarly, from $BAB'sim BHC'$, $BHcdot h_b= ABcdot BC'$ follows. By adding we have $AHcdot h_a+BHcdot h_b=AB(AC'+BC')= AB^2=c^2$. By symmetry, $BHcdot h_b+CHcdot h_c= a^2$ and $AHcdot h_a+CHcdot h_c= b^2$. Now just add these three equations.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 29 at 22:35









        SMM

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        2,19349















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