Unable to understand this expression
I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)
I am not clear of the subsequent line as well
bayes-theorem
asked Nov 29 at 21:54
user1436508
1538
add a comment |
I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)
I am not clear of the subsequent line as well
bayes-theorem
asked Nov 29 at 21:54
user1436508
1538
Is this from a Markov process?
– gd1035
Nov 29 at 21:59
I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 at 22:02
yes its about Markov process
– user1436508
Nov 29 at 22:15
add a comment |
I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)
I am not clear of the subsequent line as well
bayes-theorem
asked Nov 29 at 21:54
user1436508
1538
I am unable to understand the above expression from the 3rd line onwards. Why is P(A|q1...qt-1)P(q1..q-1) = P(A|qt-1)P(q1..q-1)
I am not clear of the subsequent line as well
bayes-theorem
bayes-theorem
asked Nov 29 at 21:54
user1436508
1538
asked Nov 29 at 21:54
user1436508
1538
asked Nov 29 at 21:54
user1436508
1538
asked Nov 29 at 21:54
user1436508
1538
asked Nov 29 at 21:54
user1436508
1538
1538
Is this from a Markov process?
– gd1035
Nov 29 at 21:59
I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 at 22:02
yes its about Markov process
– user1436508
Nov 29 at 22:15
add a comment |
Is this from a Markov process?
– gd1035
Nov 29 at 21:59
I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 at 22:02
yes its about Markov process
– user1436508
Nov 29 at 22:15
Is this from a Markov process?
– gd1035
Nov 29 at 21:59
Is this from a Markov process?
– gd1035
Nov 29 at 21:59
I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 at 22:02
I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 at 22:02
yes its about Markov process
– user1436508
Nov 29 at 22:15
yes its about Markov process
– user1436508
Nov 29 at 22:15
add a comment |
1 Answer
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This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.
See link for more information about this property.
answered Nov 29 at 23:12
gd1035
459210
add a comment |
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1 Answer
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1 Answer
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active
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oldest
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This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.
See link for more information about this property.
answered Nov 29 at 23:12
gd1035
459210
add a comment |
This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.
See link for more information about this property.
answered Nov 29 at 23:12
gd1035
459210
add a comment |
This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.
See link for more information about this property.
answered Nov 29 at 23:12
gd1035
459210
This follows from the Markov property (or the memoryless property) that the conditional probability of a future event only depends on the current state.
See link for more information about this property.
answered Nov 29 at 23:12
gd1035
459210
answered Nov 29 at 23:12
gd1035
459210
answered Nov 29 at 23:12
gd1035
459210
answered Nov 29 at 23:12
gd1035
459210
459210
add a comment |
add a comment |
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Is this from a Markov process?
– gd1035
Nov 29 at 21:59
I think the third line is a typo. I think it shoulbe $P(A|q_{t-1})P(q_1, ... , q_{t-2}) = P(A|q_{t-1})P(q_{t-1}|q_{t-2})P(q_1,....,q_{t-e}) = ..... P(A|q_{t-1})P(q_{t-1}|q_{t-2})....P(q_2|q_1)P(q_1)$.
– fleablood
Nov 29 at 22:02
yes its about Markov process
– user1436508
Nov 29 at 22:15