How to print multiple plots for each for loop iteration in R?

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0
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I have the following code,

for (i in 1:length(split_fill_data)) {

  new_frame <- split_fill_data[i]

  new_frame_2 <- do.call(rbind.data.frame, new_frame)

  if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"]))) 

      {

        print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)



        #print('hello')

        plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))

        #x11()

        }

  }

The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).

How do I make this happen in RStudio?

edited Nov 19 at 21:29

Masoud

6,48241442

asked Nov 19 at 21:03

SampyKIshan

1

par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 at 21:32

@Gregor problem with using par is that you have to know the number of plots (not exactly, but in a sense) beforehand.
– Masoud
Nov 19 at 21:58

stackoverflow.com/questions/10706753/…
– Masoud
Nov 19 at 22:11

@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it mfrow = c(6, 6) for a little cushion. Otherwise use ggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 at 22:12

1

@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using par would not be very sufficient. Cheers
– Masoud
Nov 19 at 22:16

add a comment |

up vote
0
down vote

favorite

I have the following code,

for (i in 1:length(split_fill_data)) {

  new_frame <- split_fill_data[i]

  new_frame_2 <- do.call(rbind.data.frame, new_frame)

  if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"]))) 

      {

        print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)



        #print('hello')

        plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))

        #x11()

        }

  }

The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).

How do I make this happen in RStudio?

edited Nov 19 at 21:29

Masoud

6,48241442

asked Nov 19 at 21:03

SampyKIshan

1

par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 at 21:32

@Gregor problem with using par is that you have to know the number of plots (not exactly, but in a sense) beforehand.
– Masoud
Nov 19 at 21:58

stackoverflow.com/questions/10706753/…
– Masoud
Nov 19 at 22:11

@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it mfrow = c(6, 6) for a little cushion. Otherwise use ggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 at 22:12

1

@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using par would not be very sufficient. Cheers
– Masoud
Nov 19 at 22:16

add a comment |

up vote
0
down vote

favorite

I have the following code,

for (i in 1:length(split_fill_data)) {

  new_frame <- split_fill_data[i]

  new_frame_2 <- do.call(rbind.data.frame, new_frame)

  if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"]))) 

      {

        print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)



        #print('hello')

        plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))

        #x11()

        }

  }

The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).

How do I make this happen in RStudio?

edited Nov 19 at 21:29

Masoud

6,48241442

asked Nov 19 at 21:03

SampyKIshan

I have the following code,

for (i in 1:length(split_fill_data)) {

  new_frame <- split_fill_data[i]

  new_frame_2 <- do.call(rbind.data.frame, new_frame)

  if(is.element(head(new_frame_2["egress"],1), unlist(mkt_out_60["egress"]))) 

      {

        print(head(arrange(new_frame_2,desc(Bytes_Outside))),5)



        #print('hello')

        plot(new_frame_2$ingress, new_frame_2$Bytes_Outside, main=head(new_frame_2["egress"],1))

        #x11()

        }

  }

The if block is true about 30 times and I want plot() to print a graph of ingress vs. Bytes_Outside for each of those 30 times. So, multiple subplots on a single window (or plot?).

How do I make this happen in RStudio?

r plot

edited Nov 19 at 21:29

Masoud

6,48241442

asked Nov 19 at 21:03

SampyKIshan

edited Nov 19 at 21:29

Masoud

6,48241442

asked Nov 19 at 21:03

SampyKIshan

edited Nov 19 at 21:29

Masoud

6,48241442

edited Nov 19 at 21:29

Masoud

6,48241442

edited Nov 19 at 21:29

Masoud

6,48241442

asked Nov 19 at 21:03

SampyKIshan

asked Nov 19 at 21:03

SampyKIshan

asked Nov 19 at 21:03

SampyKIshan

1

par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 at 21:32

@Gregor problem with using par is that you have to know the number of plots (not exactly, but in a sense) beforehand.
– Masoud
Nov 19 at 21:58

stackoverflow.com/questions/10706753/…
– Masoud
Nov 19 at 22:11

@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it mfrow = c(6, 6) for a little cushion. Otherwise use ggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 at 22:12

1

@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using par would not be very sufficient. Cheers
– Masoud
Nov 19 at 22:16

add a comment |

1

par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 at 21:32

@Gregor problem with using par is that you have to know the number of plots (not exactly, but in a sense) beforehand.
– Masoud
Nov 19 at 21:58

stackoverflow.com/questions/10706753/…
– Masoud
Nov 19 at 22:11

@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it mfrow = c(6, 6) for a little cushion. Otherwise use ggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 at 22:12

1

@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using par would not be very sufficient. Cheers
– Masoud
Nov 19 at 22:16

par(mfrow = c(5, 6))? Or any other way of doing multiple plots...
– Gregor
Nov 19 at 21:32

@Gregor problem with using par is that you have to know the number of plots (not exactly, but in a sense) beforehand.
– Masoud
Nov 19 at 21:58

stackoverflow.com/questions/10706753/…
– Masoud
Nov 19 at 22:11

@Masoud "The if block is true about 30 times", sounds like OP has a sense of how many plots. Make it mfrow = c(6, 6) for a little cushion. Otherwise use ggplot, save the plots to a list, and then stick them together at the end (which is, I suppose, what your link is suggesting).
– Gregor
Nov 19 at 22:12

@Gregor I didn't mean your solution won't help the OP. I was talking about it in a broader sense. Imagine you have a for-loop and if statement. As you change the parameters the ballpark number of plots would change so using par would not be very sufficient. Cheers
– Masoud
Nov 19 at 22:16

add a comment |

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A clunky fix would be to use par(mfrow = c(x,x) by running the for loop once and recording the number of true cases (say in y). Then in a second successive for loop defining the mfrow argument based on the results of the first for loop, where x would equal the square root of the length of y rounded up (i.e. ceiling(sqrt(length(y))). It's hard to write an example (at least for me) without some data to try it out on though. If you post some I will give it a crack. It's not the most elegant solution but I think it might get the job done!

answered Nov 19 at 22:13

André.B

257

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answered Nov 19 at 22:13

André.B

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up vote
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down vote

answered Nov 19 at 22:13

André.B

257

add a comment |

up vote
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down vote

answered Nov 19 at 22:13

André.B

257

answered Nov 19 at 22:13

André.B

257

answered Nov 19 at 22:13

André.B

257

answered Nov 19 at 22:13

André.B

257

answered Nov 19 at 22:13

André.B

257

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