Show COMBINATORIALLY the number of irreducible monic polynomials is the number of primitive necklaces











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Show that the number of monic irreducible polynomials of degree $n$ over a finite field of size $q$ is the same as the number of primitive necklaces of size $n$ with $q$ colors. I have the formula



$$M(q,n) = sumlimits_{d|n} q^d muBig(frac{n}{d}Big)$$



which counts primitive necklaces. The goal is to show this counts monic irreducibles over a finite field combinatorially. I can use Mobius inversion. I know this question has been asked before, but the previous answers require a lot of algebra.



I tried a special case when $q = 3$ and $n = 2$. Let the colors of the beads of a necklace be red (R), yellow (Y) and blue (B). Then the primitive necklaces are $RY$, $RB$ and $YB$. I computed the irreducible polynomials of degree $2$ as well, they are: $x^2 + 1, x^2 + x + 2$ and $x^2 + 2x + 2$. It is really unclear how I could map necklaces to these polynomials. If I just consider these as $3$-tuples then we have $(1, 0, 1), (1, 1, 2)$ and $(1, 2, 2)$ so it isn't even clear how to map the colors.










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  • 1




    What is a primitive necklace?
    – KReiser
    Nov 27 at 1:01










  • @KReiser A necklace is primitive if it cannot be obtained by repeating a smaller necklace. (So $RRRY$ is primitive, but $RRRR$ and $RYRY$ are not, for example.)
    – Théophile
    Nov 27 at 1:15












  • A necklace is a cyclic sequence of colored beads. A necklace is called primitive if it is aperiodic, i.e. no non-trivial cyclic permutation yields the same necklace.
    – RickyLiuWho
    Nov 27 at 1:16















up vote
3
down vote

favorite












Show that the number of monic irreducible polynomials of degree $n$ over a finite field of size $q$ is the same as the number of primitive necklaces of size $n$ with $q$ colors. I have the formula



$$M(q,n) = sumlimits_{d|n} q^d muBig(frac{n}{d}Big)$$



which counts primitive necklaces. The goal is to show this counts monic irreducibles over a finite field combinatorially. I can use Mobius inversion. I know this question has been asked before, but the previous answers require a lot of algebra.



I tried a special case when $q = 3$ and $n = 2$. Let the colors of the beads of a necklace be red (R), yellow (Y) and blue (B). Then the primitive necklaces are $RY$, $RB$ and $YB$. I computed the irreducible polynomials of degree $2$ as well, they are: $x^2 + 1, x^2 + x + 2$ and $x^2 + 2x + 2$. It is really unclear how I could map necklaces to these polynomials. If I just consider these as $3$-tuples then we have $(1, 0, 1), (1, 1, 2)$ and $(1, 2, 2)$ so it isn't even clear how to map the colors.










share|cite|improve this question




















  • 1




    What is a primitive necklace?
    – KReiser
    Nov 27 at 1:01










  • @KReiser A necklace is primitive if it cannot be obtained by repeating a smaller necklace. (So $RRRY$ is primitive, but $RRRR$ and $RYRY$ are not, for example.)
    – Théophile
    Nov 27 at 1:15












  • A necklace is a cyclic sequence of colored beads. A necklace is called primitive if it is aperiodic, i.e. no non-trivial cyclic permutation yields the same necklace.
    – RickyLiuWho
    Nov 27 at 1:16













up vote
3
down vote

favorite









up vote
3
down vote

favorite











Show that the number of monic irreducible polynomials of degree $n$ over a finite field of size $q$ is the same as the number of primitive necklaces of size $n$ with $q$ colors. I have the formula



$$M(q,n) = sumlimits_{d|n} q^d muBig(frac{n}{d}Big)$$



which counts primitive necklaces. The goal is to show this counts monic irreducibles over a finite field combinatorially. I can use Mobius inversion. I know this question has been asked before, but the previous answers require a lot of algebra.



I tried a special case when $q = 3$ and $n = 2$. Let the colors of the beads of a necklace be red (R), yellow (Y) and blue (B). Then the primitive necklaces are $RY$, $RB$ and $YB$. I computed the irreducible polynomials of degree $2$ as well, they are: $x^2 + 1, x^2 + x + 2$ and $x^2 + 2x + 2$. It is really unclear how I could map necklaces to these polynomials. If I just consider these as $3$-tuples then we have $(1, 0, 1), (1, 1, 2)$ and $(1, 2, 2)$ so it isn't even clear how to map the colors.










share|cite|improve this question















Show that the number of monic irreducible polynomials of degree $n$ over a finite field of size $q$ is the same as the number of primitive necklaces of size $n$ with $q$ colors. I have the formula



$$M(q,n) = sumlimits_{d|n} q^d muBig(frac{n}{d}Big)$$



which counts primitive necklaces. The goal is to show this counts monic irreducibles over a finite field combinatorially. I can use Mobius inversion. I know this question has been asked before, but the previous answers require a lot of algebra.



I tried a special case when $q = 3$ and $n = 2$. Let the colors of the beads of a necklace be red (R), yellow (Y) and blue (B). Then the primitive necklaces are $RY$, $RB$ and $YB$. I computed the irreducible polynomials of degree $2$ as well, they are: $x^2 + 1, x^2 + x + 2$ and $x^2 + 2x + 2$. It is really unclear how I could map necklaces to these polynomials. If I just consider these as $3$-tuples then we have $(1, 0, 1), (1, 1, 2)$ and $(1, 2, 2)$ so it isn't even clear how to map the colors.







combinatorics algebraic-combinatorics necklace-and-bracelets






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edited Nov 27 at 0:47

























asked Nov 27 at 0:32









RickyLiuWho

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162








  • 1




    What is a primitive necklace?
    – KReiser
    Nov 27 at 1:01










  • @KReiser A necklace is primitive if it cannot be obtained by repeating a smaller necklace. (So $RRRY$ is primitive, but $RRRR$ and $RYRY$ are not, for example.)
    – Théophile
    Nov 27 at 1:15












  • A necklace is a cyclic sequence of colored beads. A necklace is called primitive if it is aperiodic, i.e. no non-trivial cyclic permutation yields the same necklace.
    – RickyLiuWho
    Nov 27 at 1:16














  • 1




    What is a primitive necklace?
    – KReiser
    Nov 27 at 1:01










  • @KReiser A necklace is primitive if it cannot be obtained by repeating a smaller necklace. (So $RRRY$ is primitive, but $RRRR$ and $RYRY$ are not, for example.)
    – Théophile
    Nov 27 at 1:15












  • A necklace is a cyclic sequence of colored beads. A necklace is called primitive if it is aperiodic, i.e. no non-trivial cyclic permutation yields the same necklace.
    – RickyLiuWho
    Nov 27 at 1:16








1




1




What is a primitive necklace?
– KReiser
Nov 27 at 1:01




What is a primitive necklace?
– KReiser
Nov 27 at 1:01












@KReiser A necklace is primitive if it cannot be obtained by repeating a smaller necklace. (So $RRRY$ is primitive, but $RRRR$ and $RYRY$ are not, for example.)
– Théophile
Nov 27 at 1:15






@KReiser A necklace is primitive if it cannot be obtained by repeating a smaller necklace. (So $RRRY$ is primitive, but $RRRR$ and $RYRY$ are not, for example.)
– Théophile
Nov 27 at 1:15














A necklace is a cyclic sequence of colored beads. A necklace is called primitive if it is aperiodic, i.e. no non-trivial cyclic permutation yields the same necklace.
– RickyLiuWho
Nov 27 at 1:16




A necklace is a cyclic sequence of colored beads. A necklace is called primitive if it is aperiodic, i.e. no non-trivial cyclic permutation yields the same necklace.
– RickyLiuWho
Nov 27 at 1:16















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