Can I find the next prime with sufficient small residue efficiently?












1












$begingroup$


Suppose, positive integers $N,a,b$ are given.



The object is to determine the smallest prime $p$ larger than $a$ such that $N$ modulo $p$ is smaller than $b$.




Can I determine $p$ efficiently (without just checking all primes until the desired prime is found) ?




Example



$$N=40!$$



$$a=9cdot 10^{15}$$



$$b=10^{10}$$



Brute force gives the result :



? n=40!;a=9*10^15;a=nextprime(a+1);while(n%a>=10^10,a=nextprime(a+1));p=a;print(
p)
9000000017042521
?


Is there a way to speed up the search considerably ?










share|cite|improve this question











$endgroup$












  • $begingroup$
    "The object is to determine the smallest prime p larger than a such that N modulo a is smaller than b." I think there is a typo here. Where does $p$ fit in?
    $endgroup$
    – Mike
    Dec 4 '18 at 21:52










  • $begingroup$
    @Mike You are right, fixed.
    $endgroup$
    – Peter
    Dec 4 '18 at 22:14










  • $begingroup$
    I have a hunch chebyshev function can help with this, especially as numbers get larger, but it is nothing more than a hunch.
    $endgroup$
    – user334732
    Dec 4 '18 at 22:35






  • 1




    $begingroup$
    This is just a question: What about the easier problem of finding an integer (prime or no) $q>a$ s.t. $N$ modulo $q$ is less than $b$
    $endgroup$
    – Mike
    Dec 4 '18 at 23:37
















1












$begingroup$


Suppose, positive integers $N,a,b$ are given.



The object is to determine the smallest prime $p$ larger than $a$ such that $N$ modulo $p$ is smaller than $b$.




Can I determine $p$ efficiently (without just checking all primes until the desired prime is found) ?




Example



$$N=40!$$



$$a=9cdot 10^{15}$$



$$b=10^{10}$$



Brute force gives the result :



? n=40!;a=9*10^15;a=nextprime(a+1);while(n%a>=10^10,a=nextprime(a+1));p=a;print(
p)
9000000017042521
?


Is there a way to speed up the search considerably ?










share|cite|improve this question











$endgroup$












  • $begingroup$
    "The object is to determine the smallest prime p larger than a such that N modulo a is smaller than b." I think there is a typo here. Where does $p$ fit in?
    $endgroup$
    – Mike
    Dec 4 '18 at 21:52










  • $begingroup$
    @Mike You are right, fixed.
    $endgroup$
    – Peter
    Dec 4 '18 at 22:14










  • $begingroup$
    I have a hunch chebyshev function can help with this, especially as numbers get larger, but it is nothing more than a hunch.
    $endgroup$
    – user334732
    Dec 4 '18 at 22:35






  • 1




    $begingroup$
    This is just a question: What about the easier problem of finding an integer (prime or no) $q>a$ s.t. $N$ modulo $q$ is less than $b$
    $endgroup$
    – Mike
    Dec 4 '18 at 23:37














1












1








1





$begingroup$


Suppose, positive integers $N,a,b$ are given.



The object is to determine the smallest prime $p$ larger than $a$ such that $N$ modulo $p$ is smaller than $b$.




Can I determine $p$ efficiently (without just checking all primes until the desired prime is found) ?




Example



$$N=40!$$



$$a=9cdot 10^{15}$$



$$b=10^{10}$$



Brute force gives the result :



? n=40!;a=9*10^15;a=nextprime(a+1);while(n%a>=10^10,a=nextprime(a+1));p=a;print(
p)
9000000017042521
?


Is there a way to speed up the search considerably ?










share|cite|improve this question











$endgroup$




Suppose, positive integers $N,a,b$ are given.



The object is to determine the smallest prime $p$ larger than $a$ such that $N$ modulo $p$ is smaller than $b$.




Can I determine $p$ efficiently (without just checking all primes until the desired prime is found) ?




Example



$$N=40!$$



$$a=9cdot 10^{15}$$



$$b=10^{10}$$



Brute force gives the result :



? n=40!;a=9*10^15;a=nextprime(a+1);while(n%a>=10^10,a=nextprime(a+1));p=a;print(
p)
9000000017042521
?


Is there a way to speed up the search considerably ?







number-theory elementary-number-theory prime-numbers modular-arithmetic






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 4 '18 at 22:14







Peter

















asked Dec 4 '18 at 21:34









PeterPeter

46.9k1039125




46.9k1039125












  • $begingroup$
    "The object is to determine the smallest prime p larger than a such that N modulo a is smaller than b." I think there is a typo here. Where does $p$ fit in?
    $endgroup$
    – Mike
    Dec 4 '18 at 21:52










  • $begingroup$
    @Mike You are right, fixed.
    $endgroup$
    – Peter
    Dec 4 '18 at 22:14










  • $begingroup$
    I have a hunch chebyshev function can help with this, especially as numbers get larger, but it is nothing more than a hunch.
    $endgroup$
    – user334732
    Dec 4 '18 at 22:35






  • 1




    $begingroup$
    This is just a question: What about the easier problem of finding an integer (prime or no) $q>a$ s.t. $N$ modulo $q$ is less than $b$
    $endgroup$
    – Mike
    Dec 4 '18 at 23:37


















  • $begingroup$
    "The object is to determine the smallest prime p larger than a such that N modulo a is smaller than b." I think there is a typo here. Where does $p$ fit in?
    $endgroup$
    – Mike
    Dec 4 '18 at 21:52










  • $begingroup$
    @Mike You are right, fixed.
    $endgroup$
    – Peter
    Dec 4 '18 at 22:14










  • $begingroup$
    I have a hunch chebyshev function can help with this, especially as numbers get larger, but it is nothing more than a hunch.
    $endgroup$
    – user334732
    Dec 4 '18 at 22:35






  • 1




    $begingroup$
    This is just a question: What about the easier problem of finding an integer (prime or no) $q>a$ s.t. $N$ modulo $q$ is less than $b$
    $endgroup$
    – Mike
    Dec 4 '18 at 23:37
















$begingroup$
"The object is to determine the smallest prime p larger than a such that N modulo a is smaller than b." I think there is a typo here. Where does $p$ fit in?
$endgroup$
– Mike
Dec 4 '18 at 21:52




$begingroup$
"The object is to determine the smallest prime p larger than a such that N modulo a is smaller than b." I think there is a typo here. Where does $p$ fit in?
$endgroup$
– Mike
Dec 4 '18 at 21:52












$begingroup$
@Mike You are right, fixed.
$endgroup$
– Peter
Dec 4 '18 at 22:14




$begingroup$
@Mike You are right, fixed.
$endgroup$
– Peter
Dec 4 '18 at 22:14












$begingroup$
I have a hunch chebyshev function can help with this, especially as numbers get larger, but it is nothing more than a hunch.
$endgroup$
– user334732
Dec 4 '18 at 22:35




$begingroup$
I have a hunch chebyshev function can help with this, especially as numbers get larger, but it is nothing more than a hunch.
$endgroup$
– user334732
Dec 4 '18 at 22:35




1




1




$begingroup$
This is just a question: What about the easier problem of finding an integer (prime or no) $q>a$ s.t. $N$ modulo $q$ is less than $b$
$endgroup$
– Mike
Dec 4 '18 at 23:37




$begingroup$
This is just a question: What about the easier problem of finding an integer (prime or no) $q>a$ s.t. $N$ modulo $q$ is less than $b$
$endgroup$
– Mike
Dec 4 '18 at 23:37










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