Finding all rectangles with fault-free tilings of the P-pentomino












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I am trying to find all rectangles with fault-free tilings of the P pentomino. (A fault is a vertical or horizontal line inside the rectangle that is not crossed by any tiles; a fault-free tiling is thus a tiling without such lines.)



My basic strategy is to find "basic" fault free tilings, and then extend them.



So far, the following extensions are possible:





  • $5 times 2n$ rectangles can be extended to $5 times (2n + 6k)$ for $n geq 1$.


  • $m times 2n$ rectangles can be extended to $(m + 5) times 2n$ for $m geq 5$ and $n geq 2$.


  • $(5m + 5) times (2n + 5)$ rectangles can be extended to $(5m + 15) times (2n + 5)$ for $m, n geq 1$.


And I have the following basic rectangles:





  • $2 times 5$, $4 times 5$, $6 times 5$


  • $7 times 10$, $9 times 10$, $11 times 10$


  • $7 times 15$, $9 times 15$, $11 times 15$, $13 times 15$, $15 times 15$


The idea is to find if all possible rectangles can have fault free tilings, so I use this table for comparison.



My question is, is there some systematic way to deal with this "system of rectangles"? How do I know I have everyone? Or if I can make either list of basic rectangles or the list of extensions shorter?



(The P-pentomino is probably manageable with a bit of care, but I make many mistakes which made me wonder if there is a more systematic way. Also, I plan to examine the Y-pentomino next, and since it has 40 prime rectangles, I expect it to have at least as many basic rectangles.)



This picture summarizes the above. Tilings that only have yellow tiles are "basic"; colored tiles are "cylinders" inserted into basic tilings to extend them.
enter image description here










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    $begingroup$


    I am trying to find all rectangles with fault-free tilings of the P pentomino. (A fault is a vertical or horizontal line inside the rectangle that is not crossed by any tiles; a fault-free tiling is thus a tiling without such lines.)



    My basic strategy is to find "basic" fault free tilings, and then extend them.



    So far, the following extensions are possible:





    • $5 times 2n$ rectangles can be extended to $5 times (2n + 6k)$ for $n geq 1$.


    • $m times 2n$ rectangles can be extended to $(m + 5) times 2n$ for $m geq 5$ and $n geq 2$.


    • $(5m + 5) times (2n + 5)$ rectangles can be extended to $(5m + 15) times (2n + 5)$ for $m, n geq 1$.


    And I have the following basic rectangles:





    • $2 times 5$, $4 times 5$, $6 times 5$


    • $7 times 10$, $9 times 10$, $11 times 10$


    • $7 times 15$, $9 times 15$, $11 times 15$, $13 times 15$, $15 times 15$


    The idea is to find if all possible rectangles can have fault free tilings, so I use this table for comparison.



    My question is, is there some systematic way to deal with this "system of rectangles"? How do I know I have everyone? Or if I can make either list of basic rectangles or the list of extensions shorter?



    (The P-pentomino is probably manageable with a bit of care, but I make many mistakes which made me wonder if there is a more systematic way. Also, I plan to examine the Y-pentomino next, and since it has 40 prime rectangles, I expect it to have at least as many basic rectangles.)



    This picture summarizes the above. Tilings that only have yellow tiles are "basic"; colored tiles are "cylinders" inserted into basic tilings to extend them.
    enter image description here










    share|cite|improve this question











    $endgroup$















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      $begingroup$


      I am trying to find all rectangles with fault-free tilings of the P pentomino. (A fault is a vertical or horizontal line inside the rectangle that is not crossed by any tiles; a fault-free tiling is thus a tiling without such lines.)



      My basic strategy is to find "basic" fault free tilings, and then extend them.



      So far, the following extensions are possible:





      • $5 times 2n$ rectangles can be extended to $5 times (2n + 6k)$ for $n geq 1$.


      • $m times 2n$ rectangles can be extended to $(m + 5) times 2n$ for $m geq 5$ and $n geq 2$.


      • $(5m + 5) times (2n + 5)$ rectangles can be extended to $(5m + 15) times (2n + 5)$ for $m, n geq 1$.


      And I have the following basic rectangles:





      • $2 times 5$, $4 times 5$, $6 times 5$


      • $7 times 10$, $9 times 10$, $11 times 10$


      • $7 times 15$, $9 times 15$, $11 times 15$, $13 times 15$, $15 times 15$


      The idea is to find if all possible rectangles can have fault free tilings, so I use this table for comparison.



      My question is, is there some systematic way to deal with this "system of rectangles"? How do I know I have everyone? Or if I can make either list of basic rectangles or the list of extensions shorter?



      (The P-pentomino is probably manageable with a bit of care, but I make many mistakes which made me wonder if there is a more systematic way. Also, I plan to examine the Y-pentomino next, and since it has 40 prime rectangles, I expect it to have at least as many basic rectangles.)



      This picture summarizes the above. Tilings that only have yellow tiles are "basic"; colored tiles are "cylinders" inserted into basic tilings to extend them.
      enter image description here










      share|cite|improve this question











      $endgroup$




      I am trying to find all rectangles with fault-free tilings of the P pentomino. (A fault is a vertical or horizontal line inside the rectangle that is not crossed by any tiles; a fault-free tiling is thus a tiling without such lines.)



      My basic strategy is to find "basic" fault free tilings, and then extend them.



      So far, the following extensions are possible:





      • $5 times 2n$ rectangles can be extended to $5 times (2n + 6k)$ for $n geq 1$.


      • $m times 2n$ rectangles can be extended to $(m + 5) times 2n$ for $m geq 5$ and $n geq 2$.


      • $(5m + 5) times (2n + 5)$ rectangles can be extended to $(5m + 15) times (2n + 5)$ for $m, n geq 1$.


      And I have the following basic rectangles:





      • $2 times 5$, $4 times 5$, $6 times 5$


      • $7 times 10$, $9 times 10$, $11 times 10$


      • $7 times 15$, $9 times 15$, $11 times 15$, $13 times 15$, $15 times 15$


      The idea is to find if all possible rectangles can have fault free tilings, so I use this table for comparison.



      My question is, is there some systematic way to deal with this "system of rectangles"? How do I know I have everyone? Or if I can make either list of basic rectangles or the list of extensions shorter?



      (The P-pentomino is probably manageable with a bit of care, but I make many mistakes which made me wonder if there is a more systematic way. Also, I plan to examine the Y-pentomino next, and since it has 40 prime rectangles, I expect it to have at least as many basic rectangles.)



      This picture summarizes the above. Tilings that only have yellow tiles are "basic"; colored tiles are "cylinders" inserted into basic tilings to extend them.
      enter image description here







      tiling polyomino






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      edited Dec 8 '18 at 2:27







      Herman Tulleken

















      asked Dec 8 '18 at 2:18









      Herman TullekenHerman Tulleken

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