Check if elements of vector are equal to the elements of another vector +/- 1 in R
I would like to check if the elements of a vector are equal to the elements of another vector +/- 1, and count the number of times this is true. I could do it manually this way:
> a <- c(1:10)
> b <- c(1,2,3,4,6,5,10,11,12,13)
> sum(a == b-1) + sum(a == b) + sum(a == b+1)
[1] 6
Is there a neater way to achieve this? In the code I'm trying to write I'm using fairly long index vectors for both a and b, so the above would look quite messy.
r
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
add a comment |
I would like to check if the elements of a vector are equal to the elements of another vector +/- 1, and count the number of times this is true. I could do it manually this way:
> a <- c(1:10)
> b <- c(1,2,3,4,6,5,10,11,12,13)
> sum(a == b-1) + sum(a == b) + sum(a == b+1)
[1] 6
Is there a neater way to achieve this? In the code I'm trying to write I'm using fairly long index vectors for both a and b, so the above would look quite messy.
r
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
1
Maybe just use "or", as insum(a == b-1 | a == b | a == b+1)
– Dan Y
Nov 24 '18 at 20:04
4
sum(abs(a - b) <= 1)?
– jdobres
Nov 24 '18 at 20:05
I think this post is what you need: stackoverflow.com/questions/1169248/…
– Ben
Nov 25 '18 at 1:03
add a comment |
I would like to check if the elements of a vector are equal to the elements of another vector +/- 1, and count the number of times this is true. I could do it manually this way:
> a <- c(1:10)
> b <- c(1,2,3,4,6,5,10,11,12,13)
> sum(a == b-1) + sum(a == b) + sum(a == b+1)
[1] 6
Is there a neater way to achieve this? In the code I'm trying to write I'm using fairly long index vectors for both a and b, so the above would look quite messy.
r
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
I would like to check if the elements of a vector are equal to the elements of another vector +/- 1, and count the number of times this is true. I could do it manually this way:
> a <- c(1:10)
> b <- c(1,2,3,4,6,5,10,11,12,13)
> sum(a == b-1) + sum(a == b) + sum(a == b+1)
[1] 6
Is there a neater way to achieve this? In the code I'm trying to write I'm using fairly long index vectors for both a and b, so the above would look quite messy.
r
r
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
asked Nov 24 '18 at 20:01
LatteMasterLatteMaster
434
434
1
Maybe just use "or", as insum(a == b-1 | a == b | a == b+1)
– Dan Y
Nov 24 '18 at 20:04
4
sum(abs(a - b) <= 1)?
– jdobres
Nov 24 '18 at 20:05
I think this post is what you need: stackoverflow.com/questions/1169248/…
– Ben
Nov 25 '18 at 1:03
add a comment |
1
Maybe just use "or", as insum(a == b-1 | a == b | a == b+1)
– Dan Y
Nov 24 '18 at 20:04
4
sum(abs(a - b) <= 1)?
– jdobres
Nov 24 '18 at 20:05
I think this post is what you need: stackoverflow.com/questions/1169248/…
– Ben
Nov 25 '18 at 1:03
1
1
Maybe just use "or", as in
sum(a == b-1 | a == b | a == b+1)– Dan Y
Nov 24 '18 at 20:04
Maybe just use "or", as in
sum(a == b-1 | a == b | a == b+1)– Dan Y
Nov 24 '18 at 20:04
4
4
sum(abs(a - b) <= 1) ?– jdobres
Nov 24 '18 at 20:05
sum(abs(a - b) <= 1) ?– jdobres
Nov 24 '18 at 20:05
I think this post is what you need: stackoverflow.com/questions/1169248/…
– Ben
Nov 25 '18 at 1:03
I think this post is what you need: stackoverflow.com/questions/1169248/…
– Ben
Nov 25 '18 at 1:03
add a comment |
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1
Maybe just use "or", as in
sum(a == b-1 | a == b | a == b+1)– Dan Y
Nov 24 '18 at 20:04
4
sum(abs(a - b) <= 1)?– jdobres
Nov 24 '18 at 20:05
I think this post is what you need: stackoverflow.com/questions/1169248/…
– Ben
Nov 25 '18 at 1:03