Equidistribution of ${p_n^2 alpha }$












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Let $p_n$ be the $n$th prime and $alpha$ an irrational number. Vinogradov proved that the sequence ${p_n alpha }$ is equidistributed. Is it known whether the sequence ${p_n^2 alpha }$ is equidistributed?



I decided to crosspost to mathoverflow.










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    0












    $begingroup$


    Let $p_n$ be the $n$th prime and $alpha$ an irrational number. Vinogradov proved that the sequence ${p_n alpha }$ is equidistributed. Is it known whether the sequence ${p_n^2 alpha }$ is equidistributed?



    I decided to crosspost to mathoverflow.










    share|cite|improve this question











    $endgroup$















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      $begingroup$


      Let $p_n$ be the $n$th prime and $alpha$ an irrational number. Vinogradov proved that the sequence ${p_n alpha }$ is equidistributed. Is it known whether the sequence ${p_n^2 alpha }$ is equidistributed?



      I decided to crosspost to mathoverflow.










      share|cite|improve this question











      $endgroup$




      Let $p_n$ be the $n$th prime and $alpha$ an irrational number. Vinogradov proved that the sequence ${p_n alpha }$ is equidistributed. Is it known whether the sequence ${p_n^2 alpha }$ is equidistributed?



      I decided to crosspost to mathoverflow.







      number-theory ergodic-theory diophantine-approximation equidistribution






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      edited Dec 24 '18 at 1:14







      zoidberg

















      asked Dec 23 '18 at 7:43









      zoidbergzoidberg

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          Yes, any polynomial in the primes with a non-constant irrational coefficient is equidistributed. See the mathoverflow answer.






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            Yes, any polynomial in the primes with a non-constant irrational coefficient is equidistributed. See the mathoverflow answer.






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              $begingroup$

              Yes, any polynomial in the primes with a non-constant irrational coefficient is equidistributed. See the mathoverflow answer.






              share|cite|improve this answer









              $endgroup$
















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                $begingroup$

                Yes, any polynomial in the primes with a non-constant irrational coefficient is equidistributed. See the mathoverflow answer.






                share|cite|improve this answer









                $endgroup$



                Yes, any polynomial in the primes with a non-constant irrational coefficient is equidistributed. See the mathoverflow answer.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 24 '18 at 1:13









                zoidbergzoidberg

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