Calculating time interval for one day by joining tables
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I am a beginner in Postgres. I'm still learning by mostly solving problems.
I have a PostgreSQL database with two tables: trips
, which contains information about each trip a vehicle has taken, and gps_points
, which contains the GPS points covered on each trip.
The trips table contains the columns [id, start_time, end_time, vehicle_id]. The gps_points table contains the columns [id, trip_id, latitude, longitude].
How do I write a query to select the GPS points (latitude and longitude) covered by vehicle number 4 on trips which were fully contained on the 1st January 2018 (i.e. both started and ended on that date).
sql postgresql
add a comment |
I am a beginner in Postgres. I'm still learning by mostly solving problems.
I have a PostgreSQL database with two tables: trips
, which contains information about each trip a vehicle has taken, and gps_points
, which contains the GPS points covered on each trip.
The trips table contains the columns [id, start_time, end_time, vehicle_id]. The gps_points table contains the columns [id, trip_id, latitude, longitude].
How do I write a query to select the GPS points (latitude and longitude) covered by vehicle number 4 on trips which were fully contained on the 1st January 2018 (i.e. both started and ended on that date).
sql postgresql
1
I think you have forgotten to ask a question. Sample data and desired results would also be a big help.
– Gordon Linoff
Nov 26 '18 at 18:36
the key parts of your question are not really distinct and reusable, please define code blocks and provide some data to represent it.
– Siavash Rostami
Nov 26 '18 at 18:43
add a comment |
I am a beginner in Postgres. I'm still learning by mostly solving problems.
I have a PostgreSQL database with two tables: trips
, which contains information about each trip a vehicle has taken, and gps_points
, which contains the GPS points covered on each trip.
The trips table contains the columns [id, start_time, end_time, vehicle_id]. The gps_points table contains the columns [id, trip_id, latitude, longitude].
How do I write a query to select the GPS points (latitude and longitude) covered by vehicle number 4 on trips which were fully contained on the 1st January 2018 (i.e. both started and ended on that date).
sql postgresql
I am a beginner in Postgres. I'm still learning by mostly solving problems.
I have a PostgreSQL database with two tables: trips
, which contains information about each trip a vehicle has taken, and gps_points
, which contains the GPS points covered on each trip.
The trips table contains the columns [id, start_time, end_time, vehicle_id]. The gps_points table contains the columns [id, trip_id, latitude, longitude].
How do I write a query to select the GPS points (latitude and longitude) covered by vehicle number 4 on trips which were fully contained on the 1st January 2018 (i.e. both started and ended on that date).
sql postgresql
sql postgresql
edited Nov 26 '18 at 21:20
a_horse_with_no_name
308k46469570
308k46469570
asked Nov 26 '18 at 18:34
Uthred RagnarsonUthred Ragnarson
11
11
1
I think you have forgotten to ask a question. Sample data and desired results would also be a big help.
– Gordon Linoff
Nov 26 '18 at 18:36
the key parts of your question are not really distinct and reusable, please define code blocks and provide some data to represent it.
– Siavash Rostami
Nov 26 '18 at 18:43
add a comment |
1
I think you have forgotten to ask a question. Sample data and desired results would also be a big help.
– Gordon Linoff
Nov 26 '18 at 18:36
the key parts of your question are not really distinct and reusable, please define code blocks and provide some data to represent it.
– Siavash Rostami
Nov 26 '18 at 18:43
1
1
I think you have forgotten to ask a question. Sample data and desired results would also be a big help.
– Gordon Linoff
Nov 26 '18 at 18:36
I think you have forgotten to ask a question. Sample data and desired results would also be a big help.
– Gordon Linoff
Nov 26 '18 at 18:36
the key parts of your question are not really distinct and reusable, please define code blocks and provide some data to represent it.
– Siavash Rostami
Nov 26 '18 at 18:43
the key parts of your question are not really distinct and reusable, please define code blocks and provide some data to represent it.
– Siavash Rostami
Nov 26 '18 at 18:43
add a comment |
1 Answer
1
active
oldest
votes
This should do the trick:
select p.latitude
, p.longitude
from trips t
join gps_points p
on p.trip_id = t.id
where t.vehicle_id = 4
and date_trunc('day', t.start_time) = date '2018-01-01'
and date_trunc('day', t.end_time) = date '2018-01-01'
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This should do the trick:
select p.latitude
, p.longitude
from trips t
join gps_points p
on p.trip_id = t.id
where t.vehicle_id = 4
and date_trunc('day', t.start_time) = date '2018-01-01'
and date_trunc('day', t.end_time) = date '2018-01-01'
add a comment |
This should do the trick:
select p.latitude
, p.longitude
from trips t
join gps_points p
on p.trip_id = t.id
where t.vehicle_id = 4
and date_trunc('day', t.start_time) = date '2018-01-01'
and date_trunc('day', t.end_time) = date '2018-01-01'
add a comment |
This should do the trick:
select p.latitude
, p.longitude
from trips t
join gps_points p
on p.trip_id = t.id
where t.vehicle_id = 4
and date_trunc('day', t.start_time) = date '2018-01-01'
and date_trunc('day', t.end_time) = date '2018-01-01'
This should do the trick:
select p.latitude
, p.longitude
from trips t
join gps_points p
on p.trip_id = t.id
where t.vehicle_id = 4
and date_trunc('day', t.start_time) = date '2018-01-01'
and date_trunc('day', t.end_time) = date '2018-01-01'
answered Nov 28 '18 at 0:30
SentinelSentinel
5,06011221
5,06011221
add a comment |
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1
I think you have forgotten to ask a question. Sample data and desired results would also be a big help.
– Gordon Linoff
Nov 26 '18 at 18:36
the key parts of your question are not really distinct and reusable, please define code blocks and provide some data to represent it.
– Siavash Rostami
Nov 26 '18 at 18:43