get a Range by using getR(2,“firstname”)

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I would like to address the cells via the headline name.
for example. getR(sheet, 2,"firstname")

example data:

1: firstname, lastname

2: john, berg

3: mark, tost

I expect the following:

getR(sheet, 2,"firstname")
should then give me :
sheet.getRange(2, 1)

Maybe there is a possibility to make it write:
sheet.getR(2,"firstname") ?

I see the following advantages:
it is easier to understand and if the layout of the headings is reversed, it still works.

my prototype:

function getR(sheet, name) { // https://gist.github.com/printminion/5520691



    var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheet);

    var range = ss.getRange(1, 1, 1, ss.getMaxColumns()).getValues()[0]; 

    Logger.log(range);

    for (var row in range) {

        Logger.log(range[row ]);

        if ( range[row ] == name ) {

            return parseInt(row ) + 1;

        }

    }

    throw 'failed';

}

asked Nov 26 '18 at 18:44

SL5net

3801416

What is supposed to represent 2in getR(sheet, 2,"firstname") what is the desired return result. An index? a string?

– JSmith
Nov 26 '18 at 19:22

Ok. What's wrong with your code?

– TheMaster
Nov 26 '18 at 20:48

add a comment |

I would like to address the cells via the headline name.
for example. getR(sheet, 2,"firstname")

example data:

1: firstname, lastname

2: john, berg

3: mark, tost

I expect the following:

getR(sheet, 2,"firstname")
should then give me :
sheet.getRange(2, 1)

Maybe there is a possibility to make it write:
sheet.getR(2,"firstname") ?

I see the following advantages:
it is easier to understand and if the layout of the headings is reversed, it still works.

my prototype:

function getR(sheet, name) { // https://gist.github.com/printminion/5520691



    var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheet);

    var range = ss.getRange(1, 1, 1, ss.getMaxColumns()).getValues()[0]; 

    Logger.log(range);

    for (var row in range) {

        Logger.log(range[row ]);

        if ( range[row ] == name ) {

            return parseInt(row ) + 1;

        }

    }

    throw 'failed';

}

asked Nov 26 '18 at 18:44

SL5net

3801416

What is supposed to represent 2in getR(sheet, 2,"firstname") what is the desired return result. An index? a string?

– JSmith
Nov 26 '18 at 19:22

Ok. What's wrong with your code?

– TheMaster
Nov 26 '18 at 20:48

add a comment |

I would like to address the cells via the headline name.
for example. getR(sheet, 2,"firstname")

example data:

1: firstname, lastname

2: john, berg

3: mark, tost

I expect the following:

getR(sheet, 2,"firstname")
should then give me :
sheet.getRange(2, 1)

Maybe there is a possibility to make it write:
sheet.getR(2,"firstname") ?

I see the following advantages:
it is easier to understand and if the layout of the headings is reversed, it still works.

my prototype:

function getR(sheet, name) { // https://gist.github.com/printminion/5520691



    var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheet);

    var range = ss.getRange(1, 1, 1, ss.getMaxColumns()).getValues()[0]; 

    Logger.log(range);

    for (var row in range) {

        Logger.log(range[row ]);

        if ( range[row ] == name ) {

            return parseInt(row ) + 1;

        }

    }

    throw 'failed';

}

asked Nov 26 '18 at 18:44

SL5net

3801416

I would like to address the cells via the headline name.
for example. getR(sheet, 2,"firstname")

example data:

1: firstname, lastname

2: john, berg

3: mark, tost

I expect the following:

getR(sheet, 2,"firstname")
should then give me :
sheet.getRange(2, 1)

Maybe there is a possibility to make it write:
sheet.getR(2,"firstname") ?

I see the following advantages:
it is easier to understand and if the layout of the headings is reversed, it still works.

my prototype:

function getR(sheet, name) { // https://gist.github.com/printminion/5520691



    var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheet);

    var range = ss.getRange(1, 1, 1, ss.getMaxColumns()).getValues()[0]; 

    Logger.log(range);

    for (var row in range) {

        Logger.log(range[row ]);

        if ( range[row ] == name ) {

            return parseInt(row ) + 1;

        }

    }

    throw 'failed';

}

google-apps-script

asked Nov 26 '18 at 18:44

SL5net

3801416

asked Nov 26 '18 at 18:44

SL5net

3801416

asked Nov 26 '18 at 18:44

SL5net

3801416

asked Nov 26 '18 at 18:44

SL5net

3801416

asked Nov 26 '18 at 18:44

SL5net

3801416

What is supposed to represent 2in getR(sheet, 2,"firstname") what is the desired return result. An index? a string?

– JSmith
Nov 26 '18 at 19:22

Ok. What's wrong with your code?

– TheMaster
Nov 26 '18 at 20:48

add a comment |

What is supposed to represent 2in getR(sheet, 2,"firstname") what is the desired return result. An index? a string?

– JSmith
Nov 26 '18 at 19:22

Ok. What's wrong with your code?

– TheMaster
Nov 26 '18 at 20:48

What is supposed to represent 2in getR(sheet, 2,"firstname") what is the desired return result. An index? a string?

– JSmith
Nov 26 '18 at 19:22

Ok. What's wrong with your code?

– TheMaster
Nov 26 '18 at 20:48

add a comment |

1 Answer
1

active

oldest

votes

Try this:

function getR(row,sheet,headername){

  var ss=SpreadsheetApp.getActive();

  var sh=ss.getSheetByName(sheet);

  var rg=sh.getDataRange();

  var nA=rg.getValues();

  for(var i=1;i<nA.length;i++){

    if(i+1==row){

      for(var j=0;j<nA[i].length;j++){

        if(nA[0][j]==headername){

          return nA[i][j];

        }

      }

    }

  }

  throw 'failed';

}

answered Nov 26 '18 at 20:05

Cooper

8,3872829

works. i get the first entry in column firstname with: var range = getR(2,'Addresses','firstname'); Browser.msgBox(range);

– SL5net
Nov 26 '18 at 22:14

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Try this:

function getR(row,sheet,headername){

  var ss=SpreadsheetApp.getActive();

  var sh=ss.getSheetByName(sheet);

  var rg=sh.getDataRange();

  var nA=rg.getValues();

  for(var i=1;i<nA.length;i++){

    if(i+1==row){

      for(var j=0;j<nA[i].length;j++){

        if(nA[0][j]==headername){

          return nA[i][j];

        }

      }

    }

  }

  throw 'failed';

}

answered Nov 26 '18 at 20:05

Cooper

8,3872829

works. i get the first entry in column firstname with: var range = getR(2,'Addresses','firstname'); Browser.msgBox(range);

– SL5net
Nov 26 '18 at 22:14

add a comment |

Try this:

function getR(row,sheet,headername){

  var ss=SpreadsheetApp.getActive();

  var sh=ss.getSheetByName(sheet);

  var rg=sh.getDataRange();

  var nA=rg.getValues();

  for(var i=1;i<nA.length;i++){

    if(i+1==row){

      for(var j=0;j<nA[i].length;j++){

        if(nA[0][j]==headername){

          return nA[i][j];

        }

      }

    }

  }

  throw 'failed';

}

answered Nov 26 '18 at 20:05

Cooper

8,3872829

works. i get the first entry in column firstname with: var range = getR(2,'Addresses','firstname'); Browser.msgBox(range);

– SL5net
Nov 26 '18 at 22:14

add a comment |

Try this:

function getR(row,sheet,headername){

  var ss=SpreadsheetApp.getActive();

  var sh=ss.getSheetByName(sheet);

  var rg=sh.getDataRange();

  var nA=rg.getValues();

  for(var i=1;i<nA.length;i++){

    if(i+1==row){

      for(var j=0;j<nA[i].length;j++){

        if(nA[0][j]==headername){

          return nA[i][j];

        }

      }

    }

  }

  throw 'failed';

}

answered Nov 26 '18 at 20:05

Cooper

8,3872829

Try this:

function getR(row,sheet,headername){

  var ss=SpreadsheetApp.getActive();

  var sh=ss.getSheetByName(sheet);

  var rg=sh.getDataRange();

  var nA=rg.getValues();

  for(var i=1;i<nA.length;i++){

    if(i+1==row){

      for(var j=0;j<nA[i].length;j++){

        if(nA[0][j]==headername){

          return nA[i][j];

        }

      }

    }

  }

  throw 'failed';

}

answered Nov 26 '18 at 20:05

Cooper

8,3872829

answered Nov 26 '18 at 20:05

Cooper

8,3872829

answered Nov 26 '18 at 20:05

Cooper

8,3872829

answered Nov 26 '18 at 20:05

Cooper

8,3872829

works. i get the first entry in column firstname with: var range = getR(2,'Addresses','firstname'); Browser.msgBox(range);

– SL5net
Nov 26 '18 at 22:14

add a comment |

works. i get the first entry in column firstname with: var range = getR(2,'Addresses','firstname'); Browser.msgBox(range);

– SL5net
Nov 26 '18 at 22:14

works. i get the first entry in column firstname with: var range = getR(2,'Addresses','firstname'); Browser.msgBox(range);

– SL5net
Nov 26 '18 at 22:14

add a comment |

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