A non-graded Gorenstein Artin $k$-algebra such that its associated graded ring is also Gorenstein












3















I am wondering if there is a non-graded Gorenstein Artin $k$-algebra $R$ such that its associated graded ring, $mathrm{gr}(R)$, is also Gorenstein.




All the non-graded Gorenstein rings I tried so far have not Gorenstein associated graded rings.



Thanks for your help.










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    3















    I am wondering if there is a non-graded Gorenstein Artin $k$-algebra $R$ such that its associated graded ring, $mathrm{gr}(R)$, is also Gorenstein.




    All the non-graded Gorenstein rings I tried so far have not Gorenstein associated graded rings.



    Thanks for your help.










    share|cite|improve this question



























      3












      3








      3


      2






      I am wondering if there is a non-graded Gorenstein Artin $k$-algebra $R$ such that its associated graded ring, $mathrm{gr}(R)$, is also Gorenstein.




      All the non-graded Gorenstein rings I tried so far have not Gorenstein associated graded rings.



      Thanks for your help.










      share|cite|improve this question
















      I am wondering if there is a non-graded Gorenstein Artin $k$-algebra $R$ such that its associated graded ring, $mathrm{gr}(R)$, is also Gorenstein.




      All the non-graded Gorenstein rings I tried so far have not Gorenstein associated graded rings.



      Thanks for your help.







      commutative-algebra graded-rings gorenstein






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      edited Dec 1 '18 at 9:04









      user26857

      39.2k123983




      39.2k123983










      asked Jun 21 '12 at 19:46









      eileen

      463




      463






















          2 Answers
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          Let $R=k[x,y]/(xy^2, x^3-y^2)$. Then $text{gr}(R)=k[x,y]/(x^4,y^2)$.



          $R$ is nongraded Gorenstein and $mathrm{gr}(R)$ is also Gorenstein.






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            0














            Let R be a field. ${}{}{}{}{}{}{}$






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            • A field is graded, isn't it?
              – user26857
              Dec 1 '18 at 9:06











            Your Answer





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            2 Answers
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            2 Answers
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            3














            Let $R=k[x,y]/(xy^2, x^3-y^2)$. Then $text{gr}(R)=k[x,y]/(x^4,y^2)$.



            $R$ is nongraded Gorenstein and $mathrm{gr}(R)$ is also Gorenstein.






            share|cite|improve this answer




























              3














              Let $R=k[x,y]/(xy^2, x^3-y^2)$. Then $text{gr}(R)=k[x,y]/(x^4,y^2)$.



              $R$ is nongraded Gorenstein and $mathrm{gr}(R)$ is also Gorenstein.






              share|cite|improve this answer


























                3












                3








                3






                Let $R=k[x,y]/(xy^2, x^3-y^2)$. Then $text{gr}(R)=k[x,y]/(x^4,y^2)$.



                $R$ is nongraded Gorenstein and $mathrm{gr}(R)$ is also Gorenstein.






                share|cite|improve this answer














                Let $R=k[x,y]/(xy^2, x^3-y^2)$. Then $text{gr}(R)=k[x,y]/(x^4,y^2)$.



                $R$ is nongraded Gorenstein and $mathrm{gr}(R)$ is also Gorenstein.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Dec 1 '18 at 9:06









                user26857

                39.2k123983




                39.2k123983










                answered Jun 22 '12 at 21:39









                eileen

                463




                463























                    0














                    Let R be a field. ${}{}{}{}{}{}{}$






                    share|cite|improve this answer





















                    • A field is graded, isn't it?
                      – user26857
                      Dec 1 '18 at 9:06
















                    0














                    Let R be a field. ${}{}{}{}{}{}{}$






                    share|cite|improve this answer





















                    • A field is graded, isn't it?
                      – user26857
                      Dec 1 '18 at 9:06














                    0












                    0








                    0






                    Let R be a field. ${}{}{}{}{}{}{}$






                    share|cite|improve this answer












                    Let R be a field. ${}{}{}{}{}{}{}$







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Feb 18 '15 at 17:36









                    Mariano Suárez-Álvarez

                    110k7155280




                    110k7155280












                    • A field is graded, isn't it?
                      – user26857
                      Dec 1 '18 at 9:06


















                    • A field is graded, isn't it?
                      – user26857
                      Dec 1 '18 at 9:06
















                    A field is graded, isn't it?
                    – user26857
                    Dec 1 '18 at 9:06




                    A field is graded, isn't it?
                    – user26857
                    Dec 1 '18 at 9:06


















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