Find radius of a circular cross section based on distance from the origin
-1
How to find the radius of a circular cross section (centered on the z-axis) of the unit sphere based on its distance from the origin?
geometry
edited Nov 28 at 4:54
Saad
19.7k92252
asked Nov 28 at 4:21
Anthony Ferraro
1
add a comment |
-1
How to find the radius of a circular cross section (centered on the z-axis) of the unit sphere based on its distance from the origin?
geometry
edited Nov 28 at 4:54
Saad
19.7k92252
asked Nov 28 at 4:21
Anthony Ferraro
1
$r_1=sqrt {r^2-d^2}$ by Pythagoras theorem. Also, if it is the unit circle then $r_1=sqrt {1-d^2}$
– Mohammad Zuhair Khan
Nov 28 at 4:29
1
Hint: connect the origin to another point, and apply the Pythagoras theorem as suggested by Raptor, can you finish it?
– Alex Vong
Nov 28 at 4:36
add a comment |
-1
-1
-1
How to find the radius of a circular cross section (centered on the z-axis) of the unit sphere based on its distance from the origin?
geometry
edited Nov 28 at 4:54
Saad
19.7k92252
asked Nov 28 at 4:21
Anthony Ferraro
1
How to find the radius of a circular cross section (centered on the z-axis) of the unit sphere based on its distance from the origin?
geometry
geometry
edited Nov 28 at 4:54
Saad
19.7k92252
asked Nov 28 at 4:21
Anthony Ferraro
1
edited Nov 28 at 4:54
Saad
19.7k92252
asked Nov 28 at 4:21
Anthony Ferraro
1
edited Nov 28 at 4:54
Saad
19.7k92252
edited Nov 28 at 4:54
Saad
19.7k92252
edited Nov 28 at 4:54
Saad
19.7k92252
19.7k92252
asked Nov 28 at 4:21
Anthony Ferraro
1
asked Nov 28 at 4:21
Anthony Ferraro
1
asked Nov 28 at 4:21
Anthony Ferraro
1
1
$r_1=sqrt {r^2-d^2}$ by Pythagoras theorem. Also, if it is the unit circle then $r_1=sqrt {1-d^2}$
– Mohammad Zuhair Khan
Nov 28 at 4:29
1
Hint: connect the origin to another point, and apply the Pythagoras theorem as suggested by Raptor, can you finish it?
– Alex Vong
Nov 28 at 4:36
add a comment |
$r_1=sqrt {r^2-d^2}$ by Pythagoras theorem. Also, if it is the unit circle then $r_1=sqrt {1-d^2}$
– Mohammad Zuhair Khan
Nov 28 at 4:29
1
Hint: connect the origin to another point, and apply the Pythagoras theorem as suggested by Raptor, can you finish it?
– Alex Vong
Nov 28 at 4:36
$r_1=sqrt {r^2-d^2}$ by Pythagoras theorem. Also, if it is the unit circle then $r_1=sqrt {1-d^2}$
– Mohammad Zuhair Khan
Nov 28 at 4:29
$r_1=sqrt {r^2-d^2}$ by Pythagoras theorem. Also, if it is the unit circle then $r_1=sqrt {1-d^2}$
– Mohammad Zuhair Khan
Nov 28 at 4:29
1
1
Hint: connect the origin to another point, and apply the Pythagoras theorem as suggested by Raptor, can you finish it?
– Alex Vong
Nov 28 at 4:36
Hint: connect the origin to another point, and apply the Pythagoras theorem as suggested by Raptor, can you finish it?
– Alex Vong
Nov 28 at 4:36
add a comment |
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$r_1=sqrt {r^2-d^2}$ by Pythagoras theorem. Also, if it is the unit circle then $r_1=sqrt {1-d^2}$
– Mohammad Zuhair Khan
Nov 28 at 4:29
1
Hint: connect the origin to another point, and apply the Pythagoras theorem as suggested by Raptor, can you finish it?
– Alex Vong
Nov 28 at 4:36