Traversing path in C#
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder
and not \folder1anotherFolder
?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder"));
prints \folder1folder2anotherFolder
as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
add a comment |
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder
and not \folder1anotherFolder
?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder"));
prints \folder1folder2anotherFolder
as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
2
With@
you do not need `\`. If you want to use an UNC path, don't call a server folder1.
– Henk Holterman
Nov 22 '18 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 '18 at 10:15
add a comment |
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder
and not \folder1anotherFolder
?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder"));
prints \folder1folder2anotherFolder
as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder
and not \folder1anotherFolder
?
While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder"));
prints \folder1folder2anotherFolder
as I would expect it.
It seems as if I can not escape the first two folders of my path. But every folder after the two.
Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));
Which explains the behaviour.
c# .net path
c# .net path
edited Nov 23 '18 at 10:18
chbest
asked Nov 22 '18 at 18:11
chbestchbest
134
134
2
With@
you do not need `\`. If you want to use an UNC path, don't call a server folder1.
– Henk Holterman
Nov 22 '18 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 '18 at 10:15
add a comment |
2
With@
you do not need `\`. If you want to use an UNC path, don't call a server folder1.
– Henk Holterman
Nov 22 '18 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 '18 at 10:15
2
2
With
@
you do not need `\`. If you want to use an UNC path, don't call a server folder1.– Henk Holterman
Nov 22 '18 at 18:21
With
@
you do not need `\`. If you want to use an UNC path, don't call a server folder1.– Henk Holterman
Nov 22 '18 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 '18 at 10:15
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 '18 at 10:15
add a comment |
1 Answer
1
active
oldest
votes
When you specify a network path the first part (folder1
in your example) is the server name. The second part folder2
is the share name. You can use ..
to traverse up an actual folder but not a share.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
When you specify a network path the first part (folder1
in your example) is the server name. The second part folder2
is the share name. You can use ..
to traverse up an actual folder but not a share.
add a comment |
When you specify a network path the first part (folder1
in your example) is the server name. The second part folder2
is the share name. You can use ..
to traverse up an actual folder but not a share.
add a comment |
When you specify a network path the first part (folder1
in your example) is the server name. The second part folder2
is the share name. You can use ..
to traverse up an actual folder but not a share.
When you specify a network path the first part (folder1
in your example) is the server name. The second part folder2
is the share name. You can use ..
to traverse up an actual folder but not a share.
answered Nov 22 '18 at 22:13
iakobskiiakobski
1564
1564
add a comment |
add a comment |
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2
With
@
you do not need `\`. If you want to use an UNC path, don't call a server folder1.– Henk Holterman
Nov 22 '18 at 18:21
If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)
– chbest
Nov 23 '18 at 10:15