Traversing path in C#












2















Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?



While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.



It seems as if I can not escape the first two folders of my path. But every folder after the two.





Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));



Which explains the behaviour.










share|improve this question




















  • 2





    With @ you do not need `\`. If you want to use an UNC path, don't call a server folder1.

    – Henk Holterman
    Nov 22 '18 at 18:21













  • If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)

    – chbest
    Nov 23 '18 at 10:15


















2















Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?



While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.



It seems as if I can not escape the first two folders of my path. But every folder after the two.





Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));



Which explains the behaviour.










share|improve this question




















  • 2





    With @ you do not need `\`. If you want to use an UNC path, don't call a server folder1.

    – Henk Holterman
    Nov 22 '18 at 18:21













  • If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)

    – chbest
    Nov 23 '18 at 10:15
















2












2








2


1






Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?



While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.



It seems as if I can not escape the first two folders of my path. But every folder after the two.





Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));



Which explains the behaviour.










share|improve this question
















Why does
Console.WriteLine(Path.GetFullPath(@"\folder1folder2..anotherFolder"));
print \folder1folder2anotherFolder and not \folder1anotherFolder?



While Console.WriteLine(Path.GetFullPath(@"\folder1folder2folder3..anotherFolder")); prints \folder1folder2anotherFolder as I would expect it.



It seems as if I can not escape the first two folders of my path. But every folder after the two.





Edit:
Actually it is:
Console.WriteLine(Path.GetFullPath(@"servershare..anotherFolder"));



Which explains the behaviour.







c# .net path






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share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 10:18







chbest

















asked Nov 22 '18 at 18:11









chbestchbest

134




134








  • 2





    With @ you do not need `\`. If you want to use an UNC path, don't call a server folder1.

    – Henk Holterman
    Nov 22 '18 at 18:21













  • If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)

    – chbest
    Nov 23 '18 at 10:15
















  • 2





    With @ you do not need `\`. If you want to use an UNC path, don't call a server folder1.

    – Henk Holterman
    Nov 22 '18 at 18:21













  • If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)

    – chbest
    Nov 23 '18 at 10:15










2




2





With @ you do not need `\`. If you want to use an UNC path, don't call a server folder1.

– Henk Holterman
Nov 22 '18 at 18:21







With @ you do not need `\`. If you want to use an UNC path, don't call a server folder1.

– Henk Holterman
Nov 22 '18 at 18:21















If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)

– chbest
Nov 23 '18 at 10:15







If you want to use an UNC path, don't call a server folder1. Guess that is part of the miss understanding I had. ;-)

– chbest
Nov 23 '18 at 10:15














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When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.






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    When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.






    share|improve this answer




























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      When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.






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        When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.






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        When you specify a network path the first part (folder1 in your example) is the server name. The second part folder2 is the share name. You can use .. to traverse up an actual folder but not a share.







        share|improve this answer












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        answered Nov 22 '18 at 22:13









        iakobskiiakobski

        1564




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