best way to compare xml files in python












0















I want to compare these two xml files:



File1.xml:



<ngs_sample id="40332">
<workflow value="salmonella" version="101_provisional" />
<results>
<gastro_prelim_st reason="not novel" success="false">
<type st="1364" />
<type st="9999" />
</gastro_prelim_st>
</results>
</ngs_sample>


File2.xml:



<ngs_sample id="40332">
<workflow value="salmonella" version="101_provisional" />
<results>
<gastro_prelim_st reason="not novel" success="false">
<type st="1364" />
</gastro_prelim_st>
</results>
</ngs_sample>


I've used xmldiff to compare a.xml with b.xml:



def compare_xmls(observed,expected):

from xmldiff import main, formatting
formatter = formatting.DiffFormatter()
diff = main.diff_files(observed,expected,formatter=formatter)
return diff

out = compare_xmls(a.xml, b.xml)
print(out)


OUTPUT:



[delete, /ngs_sample/results/gastro_prelim_st/type[2]]


Anyone know how to identify what is the difference between the two xml files, i.e. what has been deleted compared to the file b.xml. Anyone recommend any other way of comparing xml files in python?










share|improve this question





























    0















    I want to compare these two xml files:



    File1.xml:



    <ngs_sample id="40332">
    <workflow value="salmonella" version="101_provisional" />
    <results>
    <gastro_prelim_st reason="not novel" success="false">
    <type st="1364" />
    <type st="9999" />
    </gastro_prelim_st>
    </results>
    </ngs_sample>


    File2.xml:



    <ngs_sample id="40332">
    <workflow value="salmonella" version="101_provisional" />
    <results>
    <gastro_prelim_st reason="not novel" success="false">
    <type st="1364" />
    </gastro_prelim_st>
    </results>
    </ngs_sample>


    I've used xmldiff to compare a.xml with b.xml:



    def compare_xmls(observed,expected):

    from xmldiff import main, formatting
    formatter = formatting.DiffFormatter()
    diff = main.diff_files(observed,expected,formatter=formatter)
    return diff

    out = compare_xmls(a.xml, b.xml)
    print(out)


    OUTPUT:



    [delete, /ngs_sample/results/gastro_prelim_st/type[2]]


    Anyone know how to identify what is the difference between the two xml files, i.e. what has been deleted compared to the file b.xml. Anyone recommend any other way of comparing xml files in python?










    share|improve this question



























      0












      0








      0


      0






      I want to compare these two xml files:



      File1.xml:



      <ngs_sample id="40332">
      <workflow value="salmonella" version="101_provisional" />
      <results>
      <gastro_prelim_st reason="not novel" success="false">
      <type st="1364" />
      <type st="9999" />
      </gastro_prelim_st>
      </results>
      </ngs_sample>


      File2.xml:



      <ngs_sample id="40332">
      <workflow value="salmonella" version="101_provisional" />
      <results>
      <gastro_prelim_st reason="not novel" success="false">
      <type st="1364" />
      </gastro_prelim_st>
      </results>
      </ngs_sample>


      I've used xmldiff to compare a.xml with b.xml:



      def compare_xmls(observed,expected):

      from xmldiff import main, formatting
      formatter = formatting.DiffFormatter()
      diff = main.diff_files(observed,expected,formatter=formatter)
      return diff

      out = compare_xmls(a.xml, b.xml)
      print(out)


      OUTPUT:



      [delete, /ngs_sample/results/gastro_prelim_st/type[2]]


      Anyone know how to identify what is the difference between the two xml files, i.e. what has been deleted compared to the file b.xml. Anyone recommend any other way of comparing xml files in python?










      share|improve this question
















      I want to compare these two xml files:



      File1.xml:



      <ngs_sample id="40332">
      <workflow value="salmonella" version="101_provisional" />
      <results>
      <gastro_prelim_st reason="not novel" success="false">
      <type st="1364" />
      <type st="9999" />
      </gastro_prelim_st>
      </results>
      </ngs_sample>


      File2.xml:



      <ngs_sample id="40332">
      <workflow value="salmonella" version="101_provisional" />
      <results>
      <gastro_prelim_st reason="not novel" success="false">
      <type st="1364" />
      </gastro_prelim_st>
      </results>
      </ngs_sample>


      I've used xmldiff to compare a.xml with b.xml:



      def compare_xmls(observed,expected):

      from xmldiff import main, formatting
      formatter = formatting.DiffFormatter()
      diff = main.diff_files(observed,expected,formatter=formatter)
      return diff

      out = compare_xmls(a.xml, b.xml)
      print(out)


      OUTPUT:



      [delete, /ngs_sample/results/gastro_prelim_st/type[2]]


      Anyone know how to identify what is the difference between the two xml files, i.e. what has been deleted compared to the file b.xml. Anyone recommend any other way of comparing xml files in python?







      python xml compare xmldiff






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 22 '18 at 13:51







      Mark

















      asked Nov 22 '18 at 12:23









      MarkMark

      1611516




      1611516
























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