Pandas group by aggregation function - Remove Top Level headers












1














I have used following aggregation dictionary:



fare_agg = {
'Fare_amount': {
'mean_fare_amount':'mean',
'meadian_fare_amount': 'median'
},
'Total_amount':{
'mean_total_amount':'mean',
'median_total_amount':'median'
},
'Trip_distance':{
'mean_trip_distance':'mean',
'median_trip_distance':'median'
}
}

df_g = df_a.groupby('type').agg(fare_agg)


When I save the data to the csv it comes up with two level headers. I tried to remove df_a.columns = df_a.columns.droplevel(0) but that didn't work. Then tried to reset_index(inplace=True) but that also didn't work. Whats the trick to get only the second level header.



Here is how the csv header looks like:



type,Trip_distance,Trip_distance,Fare_amount,Fare_amount,Total_amount,Total_amount
,mean_trip_distance,median_trip_distance,mean_fare_amount,meadian_fare_amount,median_total_amount,mean_total_amount









share|improve this question


















  • 1




    Possible duplicate of Python Pandas - How to flatten a hierarchical index in columns. If this doesn't help, I strongly suggest you provide a Minimal, Complete, and Verifiable example.
    – jpp
    Nov 20 at 17:52










  • Related? stackoverflow.com/questions/22233488/…
    – Evan
    Nov 20 at 19:32
















1














I have used following aggregation dictionary:



fare_agg = {
'Fare_amount': {
'mean_fare_amount':'mean',
'meadian_fare_amount': 'median'
},
'Total_amount':{
'mean_total_amount':'mean',
'median_total_amount':'median'
},
'Trip_distance':{
'mean_trip_distance':'mean',
'median_trip_distance':'median'
}
}

df_g = df_a.groupby('type').agg(fare_agg)


When I save the data to the csv it comes up with two level headers. I tried to remove df_a.columns = df_a.columns.droplevel(0) but that didn't work. Then tried to reset_index(inplace=True) but that also didn't work. Whats the trick to get only the second level header.



Here is how the csv header looks like:



type,Trip_distance,Trip_distance,Fare_amount,Fare_amount,Total_amount,Total_amount
,mean_trip_distance,median_trip_distance,mean_fare_amount,meadian_fare_amount,median_total_amount,mean_total_amount









share|improve this question


















  • 1




    Possible duplicate of Python Pandas - How to flatten a hierarchical index in columns. If this doesn't help, I strongly suggest you provide a Minimal, Complete, and Verifiable example.
    – jpp
    Nov 20 at 17:52










  • Related? stackoverflow.com/questions/22233488/…
    – Evan
    Nov 20 at 19:32














1












1








1







I have used following aggregation dictionary:



fare_agg = {
'Fare_amount': {
'mean_fare_amount':'mean',
'meadian_fare_amount': 'median'
},
'Total_amount':{
'mean_total_amount':'mean',
'median_total_amount':'median'
},
'Trip_distance':{
'mean_trip_distance':'mean',
'median_trip_distance':'median'
}
}

df_g = df_a.groupby('type').agg(fare_agg)


When I save the data to the csv it comes up with two level headers. I tried to remove df_a.columns = df_a.columns.droplevel(0) but that didn't work. Then tried to reset_index(inplace=True) but that also didn't work. Whats the trick to get only the second level header.



Here is how the csv header looks like:



type,Trip_distance,Trip_distance,Fare_amount,Fare_amount,Total_amount,Total_amount
,mean_trip_distance,median_trip_distance,mean_fare_amount,meadian_fare_amount,median_total_amount,mean_total_amount









share|improve this question













I have used following aggregation dictionary:



fare_agg = {
'Fare_amount': {
'mean_fare_amount':'mean',
'meadian_fare_amount': 'median'
},
'Total_amount':{
'mean_total_amount':'mean',
'median_total_amount':'median'
},
'Trip_distance':{
'mean_trip_distance':'mean',
'median_trip_distance':'median'
}
}

df_g = df_a.groupby('type').agg(fare_agg)


When I save the data to the csv it comes up with two level headers. I tried to remove df_a.columns = df_a.columns.droplevel(0) but that didn't work. Then tried to reset_index(inplace=True) but that also didn't work. Whats the trick to get only the second level header.



Here is how the csv header looks like:



type,Trip_distance,Trip_distance,Fare_amount,Fare_amount,Total_amount,Total_amount
,mean_trip_distance,median_trip_distance,mean_fare_amount,meadian_fare_amount,median_total_amount,mean_total_amount






python pandas






share|improve this question













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share|improve this question










asked Nov 20 at 17:50









Null-Hypothesis

5,5483099171




5,5483099171








  • 1




    Possible duplicate of Python Pandas - How to flatten a hierarchical index in columns. If this doesn't help, I strongly suggest you provide a Minimal, Complete, and Verifiable example.
    – jpp
    Nov 20 at 17:52










  • Related? stackoverflow.com/questions/22233488/…
    – Evan
    Nov 20 at 19:32














  • 1




    Possible duplicate of Python Pandas - How to flatten a hierarchical index in columns. If this doesn't help, I strongly suggest you provide a Minimal, Complete, and Verifiable example.
    – jpp
    Nov 20 at 17:52










  • Related? stackoverflow.com/questions/22233488/…
    – Evan
    Nov 20 at 19:32








1




1




Possible duplicate of Python Pandas - How to flatten a hierarchical index in columns. If this doesn't help, I strongly suggest you provide a Minimal, Complete, and Verifiable example.
– jpp
Nov 20 at 17:52




Possible duplicate of Python Pandas - How to flatten a hierarchical index in columns. If this doesn't help, I strongly suggest you provide a Minimal, Complete, and Verifiable example.
– jpp
Nov 20 at 17:52












Related? stackoverflow.com/questions/22233488/…
– Evan
Nov 20 at 19:32




Related? stackoverflow.com/questions/22233488/…
– Evan
Nov 20 at 19:32












1 Answer
1






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oldest

votes


















0














This should do what you want:



df_g.columns = df_g.columns.droplevel(-1)


Example:



df = pd.DataFrame({'type':['a','a','b','b'],'Fare_amount':[2,5,3,4],
'Total_amount':[2,3,4,1],'Trip_distance' :[2,2,4,4]})

df_g = df.groupby('type').agg(fare_agg)
df_g.columns = df_g.columns.droplevel(-1)

print(df_g)
Fare_amount Fare_amount Total_amount Total_amount Trip_distance
type
a 3.5 3.5 2.5 2.5 2
b 3.5 3.5 2.5 2.5 4

Trip_distance
type
a 2
b 4





share|improve this answer





















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    1 Answer
    1






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    oldest

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    1 Answer
    1






    active

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    active

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    0














    This should do what you want:



    df_g.columns = df_g.columns.droplevel(-1)


    Example:



    df = pd.DataFrame({'type':['a','a','b','b'],'Fare_amount':[2,5,3,4],
    'Total_amount':[2,3,4,1],'Trip_distance' :[2,2,4,4]})

    df_g = df.groupby('type').agg(fare_agg)
    df_g.columns = df_g.columns.droplevel(-1)

    print(df_g)
    Fare_amount Fare_amount Total_amount Total_amount Trip_distance
    type
    a 3.5 3.5 2.5 2.5 2
    b 3.5 3.5 2.5 2.5 4

    Trip_distance
    type
    a 2
    b 4





    share|improve this answer


























      0














      This should do what you want:



      df_g.columns = df_g.columns.droplevel(-1)


      Example:



      df = pd.DataFrame({'type':['a','a','b','b'],'Fare_amount':[2,5,3,4],
      'Total_amount':[2,3,4,1],'Trip_distance' :[2,2,4,4]})

      df_g = df.groupby('type').agg(fare_agg)
      df_g.columns = df_g.columns.droplevel(-1)

      print(df_g)
      Fare_amount Fare_amount Total_amount Total_amount Trip_distance
      type
      a 3.5 3.5 2.5 2.5 2
      b 3.5 3.5 2.5 2.5 4

      Trip_distance
      type
      a 2
      b 4





      share|improve this answer
























        0












        0








        0






        This should do what you want:



        df_g.columns = df_g.columns.droplevel(-1)


        Example:



        df = pd.DataFrame({'type':['a','a','b','b'],'Fare_amount':[2,5,3,4],
        'Total_amount':[2,3,4,1],'Trip_distance' :[2,2,4,4]})

        df_g = df.groupby('type').agg(fare_agg)
        df_g.columns = df_g.columns.droplevel(-1)

        print(df_g)
        Fare_amount Fare_amount Total_amount Total_amount Trip_distance
        type
        a 3.5 3.5 2.5 2.5 2
        b 3.5 3.5 2.5 2.5 4

        Trip_distance
        type
        a 2
        b 4





        share|improve this answer












        This should do what you want:



        df_g.columns = df_g.columns.droplevel(-1)


        Example:



        df = pd.DataFrame({'type':['a','a','b','b'],'Fare_amount':[2,5,3,4],
        'Total_amount':[2,3,4,1],'Trip_distance' :[2,2,4,4]})

        df_g = df.groupby('type').agg(fare_agg)
        df_g.columns = df_g.columns.droplevel(-1)

        print(df_g)
        Fare_amount Fare_amount Total_amount Total_amount Trip_distance
        type
        a 3.5 3.5 2.5 2.5 2
        b 3.5 3.5 2.5 2.5 4

        Trip_distance
        type
        a 2
        b 4






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 1 at 19:04









        nixon

        3,2521221




        3,2521221






























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