Maximize $(ab+cd)^2$












0














$a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$



$ac + bd = 240$ where a, b ,c ,d are positive reals, maximize $(ab +cd)^2$



looking at the equations and restrictions, I think Cauchy can be applied



$(a^2+c^2)(b^2+d^2)> (ab + cd)^2$ so we just need to find the value of the LHS



but I'm finding it hard to manipulate them and i cant seem to find an application for the ac+bd =240.










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  • What are the constraints?$ a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$?
    – gimusi
    Nov 28 at 13:28










  • and ac + bd = 240...
    – SuperMage1
    Nov 28 at 13:33










  • sorry, edited already
    – SuperMage1
    Nov 30 at 9:34










  • last edit, its correct now.
    – SuperMage1
    Nov 30 at 10:02
















0














$a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$



$ac + bd = 240$ where a, b ,c ,d are positive reals, maximize $(ab +cd)^2$



looking at the equations and restrictions, I think Cauchy can be applied



$(a^2+c^2)(b^2+d^2)> (ab + cd)^2$ so we just need to find the value of the LHS



but I'm finding it hard to manipulate them and i cant seem to find an application for the ac+bd =240.










share|cite|improve this question
























  • What are the constraints?$ a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$?
    – gimusi
    Nov 28 at 13:28










  • and ac + bd = 240...
    – SuperMage1
    Nov 28 at 13:33










  • sorry, edited already
    – SuperMage1
    Nov 30 at 9:34










  • last edit, its correct now.
    – SuperMage1
    Nov 30 at 10:02














0












0








0


1





$a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$



$ac + bd = 240$ where a, b ,c ,d are positive reals, maximize $(ab +cd)^2$



looking at the equations and restrictions, I think Cauchy can be applied



$(a^2+c^2)(b^2+d^2)> (ab + cd)^2$ so we just need to find the value of the LHS



but I'm finding it hard to manipulate them and i cant seem to find an application for the ac+bd =240.










share|cite|improve this question















$a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$



$ac + bd = 240$ where a, b ,c ,d are positive reals, maximize $(ab +cd)^2$



looking at the equations and restrictions, I think Cauchy can be applied



$(a^2+c^2)(b^2+d^2)> (ab + cd)^2$ so we just need to find the value of the LHS



but I'm finding it hard to manipulate them and i cant seem to find an application for the ac+bd =240.







optimization






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 30 at 10:01

























asked Nov 28 at 13:19









SuperMage1

862210




862210












  • What are the constraints?$ a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$?
    – gimusi
    Nov 28 at 13:28










  • and ac + bd = 240...
    – SuperMage1
    Nov 28 at 13:33










  • sorry, edited already
    – SuperMage1
    Nov 30 at 9:34










  • last edit, its correct now.
    – SuperMage1
    Nov 30 at 10:02


















  • What are the constraints?$ a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$?
    – gimusi
    Nov 28 at 13:28










  • and ac + bd = 240...
    – SuperMage1
    Nov 28 at 13:33










  • sorry, edited already
    – SuperMage1
    Nov 30 at 9:34










  • last edit, its correct now.
    – SuperMage1
    Nov 30 at 10:02
















What are the constraints?$ a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$?
– gimusi
Nov 28 at 13:28




What are the constraints?$ a^2 + b^2 - frac{ab}{2} = c^2 + d^2 + frac{cd}{2} = 256$?
– gimusi
Nov 28 at 13:28












and ac + bd = 240...
– SuperMage1
Nov 28 at 13:33




and ac + bd = 240...
– SuperMage1
Nov 28 at 13:33












sorry, edited already
– SuperMage1
Nov 30 at 9:34




sorry, edited already
– SuperMage1
Nov 30 at 9:34












last edit, its correct now.
– SuperMage1
Nov 30 at 10:02




last edit, its correct now.
– SuperMage1
Nov 30 at 10:02















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