True of false: If $0<x<1$, then HCF of $x^4, x^5, x^6$ is $x^6$. Justify.
True of false: If $0<x<1$, then HCF of $x^4, x^5, x^6$ is $x^6$. Justify.
I think it is true as $0<x<1$, $x^6$ is the minimum and hence a HCF. Please give me a proper justification.
algebra-precalculus
add a comment |
True of false: If $0<x<1$, then HCF of $x^4, x^5, x^6$ is $x^6$. Justify.
I think it is true as $0<x<1$, $x^6$ is the minimum and hence a HCF. Please give me a proper justification.
algebra-precalculus
2
This is not clear. If you mean those as just three real numbers...well, there really isn't a notion of the highest common factor of two real numbers. What would be the hcf of $sqrt 2, pi$, say? If you mean them as polynomials then $x^4$ would be it.
– lulu
Dec 3 '18 at 19:20
x$^6$ is the SCM.
– William Elliot
Dec 4 '18 at 3:35
if you mean those values as polynomials, then the condition $0<x<1$ is redundant. If you mean those numerical values, then there's no notion of HCF for real numbers. Either way, I'm moved to wonder where this question came from.
– YiFan
Dec 4 '18 at 5:07
add a comment |
True of false: If $0<x<1$, then HCF of $x^4, x^5, x^6$ is $x^6$. Justify.
I think it is true as $0<x<1$, $x^6$ is the minimum and hence a HCF. Please give me a proper justification.
algebra-precalculus
True of false: If $0<x<1$, then HCF of $x^4, x^5, x^6$ is $x^6$. Justify.
I think it is true as $0<x<1$, $x^6$ is the minimum and hence a HCF. Please give me a proper justification.
algebra-precalculus
algebra-precalculus
asked Dec 3 '18 at 19:18
user1942348user1942348
1,3731732
1,3731732
2
This is not clear. If you mean those as just three real numbers...well, there really isn't a notion of the highest common factor of two real numbers. What would be the hcf of $sqrt 2, pi$, say? If you mean them as polynomials then $x^4$ would be it.
– lulu
Dec 3 '18 at 19:20
x$^6$ is the SCM.
– William Elliot
Dec 4 '18 at 3:35
if you mean those values as polynomials, then the condition $0<x<1$ is redundant. If you mean those numerical values, then there's no notion of HCF for real numbers. Either way, I'm moved to wonder where this question came from.
– YiFan
Dec 4 '18 at 5:07
add a comment |
2
This is not clear. If you mean those as just three real numbers...well, there really isn't a notion of the highest common factor of two real numbers. What would be the hcf of $sqrt 2, pi$, say? If you mean them as polynomials then $x^4$ would be it.
– lulu
Dec 3 '18 at 19:20
x$^6$ is the SCM.
– William Elliot
Dec 4 '18 at 3:35
if you mean those values as polynomials, then the condition $0<x<1$ is redundant. If you mean those numerical values, then there's no notion of HCF for real numbers. Either way, I'm moved to wonder where this question came from.
– YiFan
Dec 4 '18 at 5:07
2
2
This is not clear. If you mean those as just three real numbers...well, there really isn't a notion of the highest common factor of two real numbers. What would be the hcf of $sqrt 2, pi$, say? If you mean them as polynomials then $x^4$ would be it.
– lulu
Dec 3 '18 at 19:20
This is not clear. If you mean those as just three real numbers...well, there really isn't a notion of the highest common factor of two real numbers. What would be the hcf of $sqrt 2, pi$, say? If you mean them as polynomials then $x^4$ would be it.
– lulu
Dec 3 '18 at 19:20
x$^6$ is the SCM.
– William Elliot
Dec 4 '18 at 3:35
x$^6$ is the SCM.
– William Elliot
Dec 4 '18 at 3:35
if you mean those values as polynomials, then the condition $0<x<1$ is redundant. If you mean those numerical values, then there's no notion of HCF for real numbers. Either way, I'm moved to wonder where this question came from.
– YiFan
Dec 4 '18 at 5:07
if you mean those values as polynomials, then the condition $0<x<1$ is redundant. If you mean those numerical values, then there's no notion of HCF for real numbers. Either way, I'm moved to wonder where this question came from.
– YiFan
Dec 4 '18 at 5:07
add a comment |
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2
This is not clear. If you mean those as just three real numbers...well, there really isn't a notion of the highest common factor of two real numbers. What would be the hcf of $sqrt 2, pi$, say? If you mean them as polynomials then $x^4$ would be it.
– lulu
Dec 3 '18 at 19:20
x$^6$ is the SCM.
– William Elliot
Dec 4 '18 at 3:35
if you mean those values as polynomials, then the condition $0<x<1$ is redundant. If you mean those numerical values, then there's no notion of HCF for real numbers. Either way, I'm moved to wonder where this question came from.
– YiFan
Dec 4 '18 at 5:07