multiply matrix with scalar
i need to create a function that multiply matrix with scalar without using numpy. tthe problem here is that the function doesn't return a matrix.( so for the matrix below it needs to return [[2,4],[6,9.0],[10,84]]
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
for i in j:
a = (i* alpha)
mat_new.append(a)
continue
return mat_new
print mul_mat_by_scalar([[1,2], [3,4.5], [5,42]], 2)
python
asked Nov 21 '18 at 20:23
user10687882user10687882
1
add a comment |
i need to create a function that multiply matrix with scalar without using numpy. tthe problem here is that the function doesn't return a matrix.( so for the matrix below it needs to return [[2,4],[6,9.0],[10,84]]
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
for i in j:
a = (i* alpha)
mat_new.append(a)
continue
return mat_new
print mul_mat_by_scalar([[1,2], [3,4.5], [5,42]], 2)
python
asked Nov 21 '18 at 20:23
user10687882user10687882
1
2
I don't think your question shows enough research effort... Can you for instance write the (mathematical) definition of scalar matrix multiplication for us?
– Rolvernew
Nov 21 '18 at 20:51
And you can also talke a close llok at your variables. What is the type ofa? what does the yourappenddo ?
– LoneWanderer
Nov 21 '18 at 21:14
add a comment |
i need to create a function that multiply matrix with scalar without using numpy. tthe problem here is that the function doesn't return a matrix.( so for the matrix below it needs to return [[2,4],[6,9.0],[10,84]]
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
for i in j:
a = (i* alpha)
mat_new.append(a)
continue
return mat_new
print mul_mat_by_scalar([[1,2], [3,4.5], [5,42]], 2)
python
asked Nov 21 '18 at 20:23
user10687882user10687882
1
i need to create a function that multiply matrix with scalar without using numpy. tthe problem here is that the function doesn't return a matrix.( so for the matrix below it needs to return [[2,4],[6,9.0],[10,84]]
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
for i in j:
a = (i* alpha)
mat_new.append(a)
continue
return mat_new
print mul_mat_by_scalar([[1,2], [3,4.5], [5,42]], 2)
python
python
asked Nov 21 '18 at 20:23
user10687882user10687882
1
asked Nov 21 '18 at 20:23
user10687882user10687882
1
edited Nov 21 '18 at 20:33
user10687882
asked Nov 21 '18 at 20:23
user10687882user10687882
1
asked Nov 21 '18 at 20:23
user10687882user10687882
1
asked Nov 21 '18 at 20:23
user10687882user10687882
1
1
2
I don't think your question shows enough research effort... Can you for instance write the (mathematical) definition of scalar matrix multiplication for us?
– Rolvernew
Nov 21 '18 at 20:51
And you can also talke a close llok at your variables. What is the type ofa? what does the yourappenddo ?
– LoneWanderer
Nov 21 '18 at 21:14
add a comment |
2
I don't think your question shows enough research effort... Can you for instance write the (mathematical) definition of scalar matrix multiplication for us?
– Rolvernew
Nov 21 '18 at 20:51
And you can also talke a close llok at your variables. What is the type ofa? what does the yourappenddo ?
– LoneWanderer
Nov 21 '18 at 21:14
2
2
I don't think your question shows enough research effort... Can you for instance write the (mathematical) definition of scalar matrix multiplication for us?
– Rolvernew
Nov 21 '18 at 20:51
I don't think your question shows enough research effort... Can you for instance write the (mathematical) definition of scalar matrix multiplication for us?
– Rolvernew
Nov 21 '18 at 20:51
And you can also talke a close llok at your variables. What is the type of
a ? what does the your append do ?– LoneWanderer
Nov 21 '18 at 21:14
And you can also talke a close llok at your variables. What is the type of
a ? what does the your append do ?– LoneWanderer
Nov 21 '18 at 21:14
add a comment |
1 Answer
1
active
oldest
votes
I would rather use a list comprehension like this:
def mul_mat_by_scalar(mat, alpha):
return [[alpha*j for j in i] for i in mat]
It just multiplies every element in mat by alpha and returns the new matrix.
For your approach to work, you would have to append lists and not just a. You would write something like this:
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
sub_mat=
for i in j:
a = i* alpha
sub_mat.append(a)
mat_new.append(sub_mat)
return mat_new
But that is ugly and not pythonic
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53419947%2fmultiply-matrix-with-scalar%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I would rather use a list comprehension like this:
def mul_mat_by_scalar(mat, alpha):
return [[alpha*j for j in i] for i in mat]
It just multiplies every element in mat by alpha and returns the new matrix.
For your approach to work, you would have to append lists and not just a. You would write something like this:
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
sub_mat=
for i in j:
a = i* alpha
sub_mat.append(a)
mat_new.append(sub_mat)
return mat_new
But that is ugly and not pythonic
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
add a comment |
I would rather use a list comprehension like this:
def mul_mat_by_scalar(mat, alpha):
return [[alpha*j for j in i] for i in mat]
It just multiplies every element in mat by alpha and returns the new matrix.
For your approach to work, you would have to append lists and not just a. You would write something like this:
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
sub_mat=
for i in j:
a = i* alpha
sub_mat.append(a)
mat_new.append(sub_mat)
return mat_new
But that is ugly and not pythonic
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
add a comment |
I would rather use a list comprehension like this:
def mul_mat_by_scalar(mat, alpha):
return [[alpha*j for j in i] for i in mat]
It just multiplies every element in mat by alpha and returns the new matrix.
For your approach to work, you would have to append lists and not just a. You would write something like this:
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
sub_mat=
for i in j:
a = i* alpha
sub_mat.append(a)
mat_new.append(sub_mat)
return mat_new
But that is ugly and not pythonic
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
I would rather use a list comprehension like this:
def mul_mat_by_scalar(mat, alpha):
return [[alpha*j for j in i] for i in mat]
It just multiplies every element in mat by alpha and returns the new matrix.
For your approach to work, you would have to append lists and not just a. You would write something like this:
def mul_mat_by_scalar(mat, alpha):
# Write the rest of the code for question 5 below here.
mat_new =
for j in mat:
sub_mat=
for i in j:
a = i* alpha
sub_mat.append(a)
mat_new.append(sub_mat)
return mat_new
But that is ugly and not pythonic
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
answered Nov 21 '18 at 21:36
user8408080user8408080
1,188139
1,188139
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53419947%2fmultiply-matrix-with-scalar%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
I don't think your question shows enough research effort... Can you for instance write the (mathematical) definition of scalar matrix multiplication for us?
– Rolvernew
Nov 21 '18 at 20:51
And you can also talke a close llok at your variables. What is the type of
a? what does the yourappenddo ?– LoneWanderer
Nov 21 '18 at 21:14