Add a column that divides another column into n chunks, R
There's no easy way to describe my question, that's probably why I was not able to find answer through search.
So I have a data frame with 3 columns, one of the columns is Subject number, the other two columns are Correctness and Block. There are 2 participants, each was exposed to 2 blocks of 3 stimuli in each block.
subj corr block
1 1 1 1
2 1 0 1
3 1 1 1
4 1 1 2
5 1 1 2
6 1 1 2
7 2 0 1
8 2 1 1
9 2 1 1
10 2 0 2
11 2 1 2
12 2 1 2
So what I want to do is to create another column that look at a specific subj number and divide the block columns corresponding to the subj into 3 even chunks (the original df has 2 chunks). In general, I want to know how to divide the stimuli each subj is exposed to in to N chunks and input the chunk number into another column.
subj corr block newblock
1 1 1 1 1
2 1 0 1 1
3 1 1 1 2
4 1 1 2 2
5 1 1 2 3
6 1 1 2 3
7 2 0 1 1
8 2 1 1 1
9 2 1 1 2
10 2 0 2 2
11 2 1 2 3
12 2 1 2 3
r split
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
add a comment |
There's no easy way to describe my question, that's probably why I was not able to find answer through search.
So I have a data frame with 3 columns, one of the columns is Subject number, the other two columns are Correctness and Block. There are 2 participants, each was exposed to 2 blocks of 3 stimuli in each block.
subj corr block
1 1 1 1
2 1 0 1
3 1 1 1
4 1 1 2
5 1 1 2
6 1 1 2
7 2 0 1
8 2 1 1
9 2 1 1
10 2 0 2
11 2 1 2
12 2 1 2
So what I want to do is to create another column that look at a specific subj number and divide the block columns corresponding to the subj into 3 even chunks (the original df has 2 chunks). In general, I want to know how to divide the stimuli each subj is exposed to in to N chunks and input the chunk number into another column.
subj corr block newblock
1 1 1 1 1
2 1 0 1 1
3 1 1 1 2
4 1 1 2 2
5 1 1 2 3
6 1 1 2 3
7 2 0 1 1
8 2 1 1 1
9 2 1 1 2
10 2 0 2 2
11 2 1 2 3
12 2 1 2 3
r split
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
1
Really?. I gave up after seeing to over 50,000 lines and the display was still not complete. Read Minimal, Complete, and Verifiable example and reflect on why we might see this as not "M". And questions with no attempt at coding are generally met with resistance to do your entire project for you. SO is not a coding service. We expect you to write code that would download and than make some effort.
– 42-
Nov 26 '18 at 2:22
Thanks for the suggestions, I've edited my question.
– Tokaalmighty
Nov 26 '18 at 3:04
add a comment |
There's no easy way to describe my question, that's probably why I was not able to find answer through search.
So I have a data frame with 3 columns, one of the columns is Subject number, the other two columns are Correctness and Block. There are 2 participants, each was exposed to 2 blocks of 3 stimuli in each block.
subj corr block
1 1 1 1
2 1 0 1
3 1 1 1
4 1 1 2
5 1 1 2
6 1 1 2
7 2 0 1
8 2 1 1
9 2 1 1
10 2 0 2
11 2 1 2
12 2 1 2
So what I want to do is to create another column that look at a specific subj number and divide the block columns corresponding to the subj into 3 even chunks (the original df has 2 chunks). In general, I want to know how to divide the stimuli each subj is exposed to in to N chunks and input the chunk number into another column.
subj corr block newblock
1 1 1 1 1
2 1 0 1 1
3 1 1 1 2
4 1 1 2 2
5 1 1 2 3
6 1 1 2 3
7 2 0 1 1
8 2 1 1 1
9 2 1 1 2
10 2 0 2 2
11 2 1 2 3
12 2 1 2 3
r split
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
There's no easy way to describe my question, that's probably why I was not able to find answer through search.
So I have a data frame with 3 columns, one of the columns is Subject number, the other two columns are Correctness and Block. There are 2 participants, each was exposed to 2 blocks of 3 stimuli in each block.
subj corr block
1 1 1 1
2 1 0 1
3 1 1 1
4 1 1 2
5 1 1 2
6 1 1 2
7 2 0 1
8 2 1 1
9 2 1 1
10 2 0 2
11 2 1 2
12 2 1 2
So what I want to do is to create another column that look at a specific subj number and divide the block columns corresponding to the subj into 3 even chunks (the original df has 2 chunks). In general, I want to know how to divide the stimuli each subj is exposed to in to N chunks and input the chunk number into another column.
subj corr block newblock
1 1 1 1 1
2 1 0 1 1
3 1 1 1 2
4 1 1 2 2
5 1 1 2 3
6 1 1 2 3
7 2 0 1 1
8 2 1 1 1
9 2 1 1 2
10 2 0 2 2
11 2 1 2 3
12 2 1 2 3
r split
r split
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
edited Nov 26 '18 at 3:08
Tokaalmighty
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
asked Nov 26 '18 at 2:13
TokaalmightyTokaalmighty
978
978
1
Really?. I gave up after seeing to over 50,000 lines and the display was still not complete. Read Minimal, Complete, and Verifiable example and reflect on why we might see this as not "M". And questions with no attempt at coding are generally met with resistance to do your entire project for you. SO is not a coding service. We expect you to write code that would download and than make some effort.
– 42-
Nov 26 '18 at 2:22
Thanks for the suggestions, I've edited my question.
– Tokaalmighty
Nov 26 '18 at 3:04
add a comment |
1
Really?. I gave up after seeing to over 50,000 lines and the display was still not complete. Read Minimal, Complete, and Verifiable example and reflect on why we might see this as not "M". And questions with no attempt at coding are generally met with resistance to do your entire project for you. SO is not a coding service. We expect you to write code that would download and than make some effort.
– 42-
Nov 26 '18 at 2:22
Thanks for the suggestions, I've edited my question.
– Tokaalmighty
Nov 26 '18 at 3:04
1
1
Really?. I gave up after seeing to over 50,000 lines and the display was still not complete. Read Minimal, Complete, and Verifiable example and reflect on why we might see this as not "M". And questions with no attempt at coding are generally met with resistance to do your entire project for you. SO is not a coding service. We expect you to write code that would download and than make some effort.
– 42-
Nov 26 '18 at 2:22
Really?. I gave up after seeing to over 50,000 lines and the display was still not complete. Read Minimal, Complete, and Verifiable example and reflect on why we might see this as not "M". And questions with no attempt at coding are generally met with resistance to do your entire project for you. SO is not a coding service. We expect you to write code that would download and than make some effort.
– 42-
Nov 26 '18 at 2:22
Thanks for the suggestions, I've edited my question.
– Tokaalmighty
Nov 26 '18 at 3:04
Thanks for the suggestions, I've edited my question.
– Tokaalmighty
Nov 26 '18 at 3:04
add a comment |
1 Answer
1
active
oldest
votes
Something like this:
library(dplyr)
n_chunks = 3
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
How much of this is necessary depends on your use case. If you can guarantee that n_chunks evenly divides the number of observations for each subject you can simplify to:
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = n() / n_chunks))
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
Thanks @Gregor! There was a missing bracket in the first code block before [1:n()], but otherwise it solved my problem perfectly well. df %>% group_by(subj) %>% mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
– Tokaalmighty
Nov 26 '18 at 3:35
If anyone else run into the Error 'This function should not be called directly', detach dplyr first with detach("package:dplyr", unload=TRUE), then load plyr first, then load dplyr
– Tokaalmighty
Nov 26 '18 at 16:50
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
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oldest
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active
oldest
votes
Something like this:
library(dplyr)
n_chunks = 3
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
How much of this is necessary depends on your use case. If you can guarantee that n_chunks evenly divides the number of observations for each subject you can simplify to:
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = n() / n_chunks))
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
Thanks @Gregor! There was a missing bracket in the first code block before [1:n()], but otherwise it solved my problem perfectly well. df %>% group_by(subj) %>% mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
– Tokaalmighty
Nov 26 '18 at 3:35
If anyone else run into the Error 'This function should not be called directly', detach dplyr first with detach("package:dplyr", unload=TRUE), then load plyr first, then load dplyr
– Tokaalmighty
Nov 26 '18 at 16:50
add a comment |
Something like this:
library(dplyr)
n_chunks = 3
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
How much of this is necessary depends on your use case. If you can guarantee that n_chunks evenly divides the number of observations for each subject you can simplify to:
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = n() / n_chunks))
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
Thanks @Gregor! There was a missing bracket in the first code block before [1:n()], but otherwise it solved my problem perfectly well. df %>% group_by(subj) %>% mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
– Tokaalmighty
Nov 26 '18 at 3:35
If anyone else run into the Error 'This function should not be called directly', detach dplyr first with detach("package:dplyr", unload=TRUE), then load plyr first, then load dplyr
– Tokaalmighty
Nov 26 '18 at 16:50
add a comment |
Something like this:
library(dplyr)
n_chunks = 3
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
How much of this is necessary depends on your use case. If you can guarantee that n_chunks evenly divides the number of observations for each subject you can simplify to:
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = n() / n_chunks))
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
Something like this:
library(dplyr)
n_chunks = 3
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
How much of this is necessary depends on your use case. If you can guarantee that n_chunks evenly divides the number of observations for each subject you can simplify to:
df %>%
group_by(subj) %>%
mutate(newblock = rep(1:n_chunks, each = n() / n_chunks))
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
edited Nov 26 '18 at 3:39
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
answered Nov 26 '18 at 3:15
GregorGregor
67.1k1095179
67.1k1095179
Thanks @Gregor! There was a missing bracket in the first code block before [1:n()], but otherwise it solved my problem perfectly well. df %>% group_by(subj) %>% mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
– Tokaalmighty
Nov 26 '18 at 3:35
If anyone else run into the Error 'This function should not be called directly', detach dplyr first with detach("package:dplyr", unload=TRUE), then load plyr first, then load dplyr
– Tokaalmighty
Nov 26 '18 at 16:50
add a comment |
Thanks @Gregor! There was a missing bracket in the first code block before [1:n()], but otherwise it solved my problem perfectly well. df %>% group_by(subj) %>% mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
– Tokaalmighty
Nov 26 '18 at 3:35
If anyone else run into the Error 'This function should not be called directly', detach dplyr first with detach("package:dplyr", unload=TRUE), then load plyr first, then load dplyr
– Tokaalmighty
Nov 26 '18 at 16:50
Thanks @Gregor! There was a missing bracket in the first code block before [1:n()], but otherwise it solved my problem perfectly well. df %>% group_by(subj) %>% mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
– Tokaalmighty
Nov 26 '18 at 3:35
Thanks @Gregor! There was a missing bracket in the first code block before [1:n()], but otherwise it solved my problem perfectly well. df %>% group_by(subj) %>% mutate(newblock = rep(1:n_chunks, each = ceiling(n() / n_chunks))[1:n()])
– Tokaalmighty
Nov 26 '18 at 3:35
If anyone else run into the Error 'This function should not be called directly', detach dplyr first with detach("package:dplyr", unload=TRUE), then load plyr first, then load dplyr
– Tokaalmighty
Nov 26 '18 at 16:50
If anyone else run into the Error 'This function should not be called directly', detach dplyr first with detach("package:dplyr", unload=TRUE), then load plyr first, then load dplyr
– Tokaalmighty
Nov 26 '18 at 16:50
add a comment |
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1
Really?. I gave up after seeing to over 50,000 lines and the display was still not complete. Read Minimal, Complete, and Verifiable example and reflect on why we might see this as not "M". And questions with no attempt at coding are generally met with resistance to do your entire project for you. SO is not a coding service. We expect you to write code that would download and than make some effort.
– 42-
Nov 26 '18 at 2:22
Thanks for the suggestions, I've edited my question.
– Tokaalmighty
Nov 26 '18 at 3:04