Is there a more efficient way using mysql to get a list for a given column in an sql result?
I have a query that rows of a table each containing an id.
For each id I want to get multiple values from another table.
The way I would do this is make the first query, then loop through the result making a query for each id.
This could mean making a thousand queries, is there a way I could do this in 1 query.
mysql sql
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
add a comment |
I have a query that rows of a table each containing an id.
For each id I want to get multiple values from another table.
The way I would do this is make the first query, then loop through the result making a query for each id.
This could mean making a thousand queries, is there a way I could do this in 1 query.
mysql sql
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
1
Please provide sample data and desired results.
– Gordon Linoff
Nov 25 '18 at 20:28
add a comment |
I have a query that rows of a table each containing an id.
For each id I want to get multiple values from another table.
The way I would do this is make the first query, then loop through the result making a query for each id.
This could mean making a thousand queries, is there a way I could do this in 1 query.
mysql sql
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
I have a query that rows of a table each containing an id.
For each id I want to get multiple values from another table.
The way I would do this is make the first query, then loop through the result making a query for each id.
This could mean making a thousand queries, is there a way I could do this in 1 query.
mysql sql
mysql sql
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
asked Nov 25 '18 at 20:27
Jacob JeffersonJacob Jefferson
11
11
1
Please provide sample data and desired results.
– Gordon Linoff
Nov 25 '18 at 20:28
add a comment |
1
Please provide sample data and desired results.
– Gordon Linoff
Nov 25 '18 at 20:28
1
1
Please provide sample data and desired results.
– Gordon Linoff
Nov 25 '18 at 20:28
Please provide sample data and desired results.
– Gordon Linoff
Nov 25 '18 at 20:28
add a comment |
1 Answer
1
active
oldest
votes
I think you want group_concat(). Something like this:
select t1.id, group_concat(t2.othercol)
from table1 t1 join
table2 t2
on t1.id = t2.id
group by t1.id;
Or perhaps you just want in:
select t2.*
from table2 t2
where t2.id in (select t1.id from table1 t1);
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think you want group_concat(). Something like this:
select t1.id, group_concat(t2.othercol)
from table1 t1 join
table2 t2
on t1.id = t2.id
group by t1.id;
Or perhaps you just want in:
select t2.*
from table2 t2
where t2.id in (select t1.id from table1 t1);
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
add a comment |
I think you want group_concat(). Something like this:
select t1.id, group_concat(t2.othercol)
from table1 t1 join
table2 t2
on t1.id = t2.id
group by t1.id;
Or perhaps you just want in:
select t2.*
from table2 t2
where t2.id in (select t1.id from table1 t1);
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
add a comment |
I think you want group_concat(). Something like this:
select t1.id, group_concat(t2.othercol)
from table1 t1 join
table2 t2
on t1.id = t2.id
group by t1.id;
Or perhaps you just want in:
select t2.*
from table2 t2
where t2.id in (select t1.id from table1 t1);
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
I think you want group_concat(). Something like this:
select t1.id, group_concat(t2.othercol)
from table1 t1 join
table2 t2
on t1.id = t2.id
group by t1.id;
Or perhaps you just want in:
select t2.*
from table2 t2
where t2.id in (select t1.id from table1 t1);
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
answered Nov 25 '18 at 20:28
Gordon LinoffGordon Linoff
789k35313418
789k35313418
add a comment |
add a comment |
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1
Please provide sample data and desired results.
– Gordon Linoff
Nov 25 '18 at 20:28