Mulicolumn and Multirow alignment and spacing
In my first encounter with multicolumn and multirow, I have attempted to make a table containing math, including matrices.
Firstly, I have an error in my column names; I'm unsure where I am going wrong and have been unable to find similar problems. I wish for my titles to be "Design" and then "Results" as my multicolumn heading, but they both sit in the same box. (Edit: I'm also getting an error "Extra alignment tab has been changed to cr." which I think may be the source of this problem?)
Secondly, the matrices in the cells seem crowded, is it possible to modify the cell size whilst retaining centering?
Finally, in my first column I have two matrices which sit each in their own multirow, they are currently left aligned (or aligned with each other) is it possible again to have them centered within their (multiple) cell?
I appreciate any help but will continue to attempt to resolve the issues. Please see the code below:
documentclass{article}
usepackage{multirow}
usepackage{amsmath}
begin{document}
begin{center}
begin{tabular}{ c|c c }
Design &multicolumn{4}{c|}{Results}\
hline
multirow{2}{11em}{$xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}$}
&$M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3)= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3})end{vmatrix}=6$
&$d(x,xi_{3})=2.5$\
multirow{2}{11em}{$xi_3^{'} = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}$}
&$M(xi_3^{'})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3^{'})= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3}^{'})end{vmatrix}=8$
&$d(x,xi_{3}^{'})=3$\
end{tabular}
end{center}
end{document}
multirow multicolumn
add a comment |
In my first encounter with multicolumn and multirow, I have attempted to make a table containing math, including matrices.
Firstly, I have an error in my column names; I'm unsure where I am going wrong and have been unable to find similar problems. I wish for my titles to be "Design" and then "Results" as my multicolumn heading, but they both sit in the same box. (Edit: I'm also getting an error "Extra alignment tab has been changed to cr." which I think may be the source of this problem?)
Secondly, the matrices in the cells seem crowded, is it possible to modify the cell size whilst retaining centering?
Finally, in my first column I have two matrices which sit each in their own multirow, they are currently left aligned (or aligned with each other) is it possible again to have them centered within their (multiple) cell?
I appreciate any help but will continue to attempt to resolve the issues. Please see the code below:
documentclass{article}
usepackage{multirow}
usepackage{amsmath}
begin{document}
begin{center}
begin{tabular}{ c|c c }
Design &multicolumn{4}{c|}{Results}\
hline
multirow{2}{11em}{$xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}$}
&$M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3)= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3})end{vmatrix}=6$
&$d(x,xi_{3})=2.5$\
multirow{2}{11em}{$xi_3^{'} = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}$}
&$M(xi_3^{'})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3^{'})= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3}^{'})end{vmatrix}=8$
&$d(x,xi_{3}^{'})=3$\
end{tabular}
end{center}
end{document}
multirow multicolumn
add a comment |
In my first encounter with multicolumn and multirow, I have attempted to make a table containing math, including matrices.
Firstly, I have an error in my column names; I'm unsure where I am going wrong and have been unable to find similar problems. I wish for my titles to be "Design" and then "Results" as my multicolumn heading, but they both sit in the same box. (Edit: I'm also getting an error "Extra alignment tab has been changed to cr." which I think may be the source of this problem?)
Secondly, the matrices in the cells seem crowded, is it possible to modify the cell size whilst retaining centering?
Finally, in my first column I have two matrices which sit each in their own multirow, they are currently left aligned (or aligned with each other) is it possible again to have them centered within their (multiple) cell?
I appreciate any help but will continue to attempt to resolve the issues. Please see the code below:
documentclass{article}
usepackage{multirow}
usepackage{amsmath}
begin{document}
begin{center}
begin{tabular}{ c|c c }
Design &multicolumn{4}{c|}{Results}\
hline
multirow{2}{11em}{$xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}$}
&$M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3)= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3})end{vmatrix}=6$
&$d(x,xi_{3})=2.5$\
multirow{2}{11em}{$xi_3^{'} = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}$}
&$M(xi_3^{'})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3^{'})= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3}^{'})end{vmatrix}=8$
&$d(x,xi_{3}^{'})=3$\
end{tabular}
end{center}
end{document}
multirow multicolumn
In my first encounter with multicolumn and multirow, I have attempted to make a table containing math, including matrices.
Firstly, I have an error in my column names; I'm unsure where I am going wrong and have been unable to find similar problems. I wish for my titles to be "Design" and then "Results" as my multicolumn heading, but they both sit in the same box. (Edit: I'm also getting an error "Extra alignment tab has been changed to cr." which I think may be the source of this problem?)
Secondly, the matrices in the cells seem crowded, is it possible to modify the cell size whilst retaining centering?
Finally, in my first column I have two matrices which sit each in their own multirow, they are currently left aligned (or aligned with each other) is it possible again to have them centered within their (multiple) cell?
I appreciate any help but will continue to attempt to resolve the issues. Please see the code below:
documentclass{article}
usepackage{multirow}
usepackage{amsmath}
begin{document}
begin{center}
begin{tabular}{ c|c c }
Design &multicolumn{4}{c|}{Results}\
hline
multirow{2}{11em}{$xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}$}
&$M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3)= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3})end{vmatrix}=6$
&$d(x,xi_{3})=2.5$\
multirow{2}{11em}{$xi_3^{'} = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}$}
&$M(xi_3^{'})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}$
&$d(x,xi_3^{'})= 1+frac{3x^2}{2}$ \
&$begin{vmatrix}M(xi_{3}^{'})end{vmatrix}=8$
&$d(x,xi_{3}^{'})=3$\
end{tabular}
end{center}
end{document}
multirow multicolumn
multirow multicolumn
asked Dec 21 '18 at 21:53
BenBen
303
303
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You do not have to take into account the number pf columns of the matrices inside the tabular. I propose here some simplifications of the code and some improvemennts to the layout, using the array
environment, and the makecell
and nccmath
packages:
documentclass{article}
usepackage{amsmath, nccmath}
usepackage{multirow, makecell}
begin{document}
[
begin{array}{c|cc}
text{Design} &multicolumn{2}{c|}{text{Results}}\%
hline
multirowcell{3}{ xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix} }
&Gape[6pt][2pt]{M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
& d(x,xi_3)= 1+mfrac{3x^2}{2} \[1ex]%
& begin{vmatrix}M(xi_{3})end{vmatrix}=6
& d(x,xi_{3})=2.5 \
multirowcell{3}{xi'_3 = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&Gape[10pt][2pt]{M(xi'_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
&d(x,xi_3')= 1+mfrac{3x^2}{2} \%
&begin{vmatrix}M(xi'_{3})end{vmatrix}=8
&d(x,xi'_{3})=3 \
end{array} ]
end{document}
add a comment |
I would avoid multirow
altogether. With array
the entries are automatically typeset in math mode, to which I add displaystyle
.
Note that x_{3}^{'}
is wrong and it should be x_{3}'
.
documentclass{article}
usepackage{amsmath}
usepackage{booktabs}
usepackage{array}
begin{document}
begin{center}
$begin{array}{ *{3}{>{displaystyle}l} }
toprule
multicolumn{1}{c}{text{Design}} & multicolumn{2}{c}{text{Results}} \
midrule
smash[b]{xi_{3} = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}}
&M(xi_{3})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3})=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3})rvert=6
&d(x,xi_{3})=2.5
\ midrule
smash[b]{xi_{3}' = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&M(xi_{3}')=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3}')=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3}')rvert=8
&d(x,xi_{3}')=3
\
bottomrule
end{array}$
end{center}
end{document}
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You do not have to take into account the number pf columns of the matrices inside the tabular. I propose here some simplifications of the code and some improvemennts to the layout, using the array
environment, and the makecell
and nccmath
packages:
documentclass{article}
usepackage{amsmath, nccmath}
usepackage{multirow, makecell}
begin{document}
[
begin{array}{c|cc}
text{Design} &multicolumn{2}{c|}{text{Results}}\%
hline
multirowcell{3}{ xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix} }
&Gape[6pt][2pt]{M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
& d(x,xi_3)= 1+mfrac{3x^2}{2} \[1ex]%
& begin{vmatrix}M(xi_{3})end{vmatrix}=6
& d(x,xi_{3})=2.5 \
multirowcell{3}{xi'_3 = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&Gape[10pt][2pt]{M(xi'_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
&d(x,xi_3')= 1+mfrac{3x^2}{2} \%
&begin{vmatrix}M(xi'_{3})end{vmatrix}=8
&d(x,xi'_{3})=3 \
end{array} ]
end{document}
add a comment |
You do not have to take into account the number pf columns of the matrices inside the tabular. I propose here some simplifications of the code and some improvemennts to the layout, using the array
environment, and the makecell
and nccmath
packages:
documentclass{article}
usepackage{amsmath, nccmath}
usepackage{multirow, makecell}
begin{document}
[
begin{array}{c|cc}
text{Design} &multicolumn{2}{c|}{text{Results}}\%
hline
multirowcell{3}{ xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix} }
&Gape[6pt][2pt]{M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
& d(x,xi_3)= 1+mfrac{3x^2}{2} \[1ex]%
& begin{vmatrix}M(xi_{3})end{vmatrix}=6
& d(x,xi_{3})=2.5 \
multirowcell{3}{xi'_3 = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&Gape[10pt][2pt]{M(xi'_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
&d(x,xi_3')= 1+mfrac{3x^2}{2} \%
&begin{vmatrix}M(xi'_{3})end{vmatrix}=8
&d(x,xi'_{3})=3 \
end{array} ]
end{document}
add a comment |
You do not have to take into account the number pf columns of the matrices inside the tabular. I propose here some simplifications of the code and some improvemennts to the layout, using the array
environment, and the makecell
and nccmath
packages:
documentclass{article}
usepackage{amsmath, nccmath}
usepackage{multirow, makecell}
begin{document}
[
begin{array}{c|cc}
text{Design} &multicolumn{2}{c|}{text{Results}}\%
hline
multirowcell{3}{ xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix} }
&Gape[6pt][2pt]{M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
& d(x,xi_3)= 1+mfrac{3x^2}{2} \[1ex]%
& begin{vmatrix}M(xi_{3})end{vmatrix}=6
& d(x,xi_{3})=2.5 \
multirowcell{3}{xi'_3 = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&Gape[10pt][2pt]{M(xi'_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
&d(x,xi_3')= 1+mfrac{3x^2}{2} \%
&begin{vmatrix}M(xi'_{3})end{vmatrix}=8
&d(x,xi'_{3})=3 \
end{array} ]
end{document}
You do not have to take into account the number pf columns of the matrices inside the tabular. I propose here some simplifications of the code and some improvemennts to the layout, using the array
environment, and the makecell
and nccmath
packages:
documentclass{article}
usepackage{amsmath, nccmath}
usepackage{multirow, makecell}
begin{document}
[
begin{array}{c|cc}
text{Design} &multicolumn{2}{c|}{text{Results}}\%
hline
multirowcell{3}{ xi_3 = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix} }
&Gape[6pt][2pt]{M(xi_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
& d(x,xi_3)= 1+mfrac{3x^2}{2} \[1ex]%
& begin{vmatrix}M(xi_{3})end{vmatrix}=6
& d(x,xi_{3})=2.5 \
multirowcell{3}{xi'_3 = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&Gape[10pt][2pt]{M(xi'_3)=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}}
&d(x,xi_3')= 1+mfrac{3x^2}{2} \%
&begin{vmatrix}M(xi'_{3})end{vmatrix}=8
&d(x,xi'_{3})=3 \
end{array} ]
end{document}
answered Dec 21 '18 at 22:44
BernardBernard
172k775203
172k775203
add a comment |
add a comment |
I would avoid multirow
altogether. With array
the entries are automatically typeset in math mode, to which I add displaystyle
.
Note that x_{3}^{'}
is wrong and it should be x_{3}'
.
documentclass{article}
usepackage{amsmath}
usepackage{booktabs}
usepackage{array}
begin{document}
begin{center}
$begin{array}{ *{3}{>{displaystyle}l} }
toprule
multicolumn{1}{c}{text{Design}} & multicolumn{2}{c}{text{Results}} \
midrule
smash[b]{xi_{3} = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}}
&M(xi_{3})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3})=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3})rvert=6
&d(x,xi_{3})=2.5
\ midrule
smash[b]{xi_{3}' = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&M(xi_{3}')=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3}')=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3}')rvert=8
&d(x,xi_{3}')=3
\
bottomrule
end{array}$
end{center}
end{document}
add a comment |
I would avoid multirow
altogether. With array
the entries are automatically typeset in math mode, to which I add displaystyle
.
Note that x_{3}^{'}
is wrong and it should be x_{3}'
.
documentclass{article}
usepackage{amsmath}
usepackage{booktabs}
usepackage{array}
begin{document}
begin{center}
$begin{array}{ *{3}{>{displaystyle}l} }
toprule
multicolumn{1}{c}{text{Design}} & multicolumn{2}{c}{text{Results}} \
midrule
smash[b]{xi_{3} = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}}
&M(xi_{3})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3})=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3})rvert=6
&d(x,xi_{3})=2.5
\ midrule
smash[b]{xi_{3}' = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&M(xi_{3}')=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3}')=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3}')rvert=8
&d(x,xi_{3}')=3
\
bottomrule
end{array}$
end{center}
end{document}
add a comment |
I would avoid multirow
altogether. With array
the entries are automatically typeset in math mode, to which I add displaystyle
.
Note that x_{3}^{'}
is wrong and it should be x_{3}'
.
documentclass{article}
usepackage{amsmath}
usepackage{booktabs}
usepackage{array}
begin{document}
begin{center}
$begin{array}{ *{3}{>{displaystyle}l} }
toprule
multicolumn{1}{c}{text{Design}} & multicolumn{2}{c}{text{Results}} \
midrule
smash[b]{xi_{3} = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}}
&M(xi_{3})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3})=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3})rvert=6
&d(x,xi_{3})=2.5
\ midrule
smash[b]{xi_{3}' = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&M(xi_{3}')=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3}')=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3}')rvert=8
&d(x,xi_{3}')=3
\
bottomrule
end{array}$
end{center}
end{document}
I would avoid multirow
altogether. With array
the entries are automatically typeset in math mode, to which I add displaystyle
.
Note that x_{3}^{'}
is wrong and it should be x_{3}'
.
documentclass{article}
usepackage{amsmath}
usepackage{booktabs}
usepackage{array}
begin{document}
begin{center}
$begin{array}{ *{3}{>{displaystyle}l} }
toprule
multicolumn{1}{c}{text{Design}} & multicolumn{2}{c}{text{Results}} \
midrule
smash[b]{xi_{3} = begin{Bmatrix}
-1 &0 &1 \
1/3 &1/3 &1/3 \
end{Bmatrix}}
&M(xi_{3})=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3})=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3})rvert=6
&d(x,xi_{3})=2.5
\ midrule
smash[b]{xi_{3}' = begin{Bmatrix}
-1 &1 \
1/2 &1/2 \
end{Bmatrix}}
&M(xi_{3}')=begin{bmatrix}
3 &0 \
0 &2
end{bmatrix}
&d(x,xi_{3}')=1+frac{3x^2}{2}
\ addlinespace
&lvert M(xi_{3}')rvert=8
&d(x,xi_{3}')=3
\
bottomrule
end{array}$
end{center}
end{document}
answered Dec 21 '18 at 22:30
egregegreg
723k8819173221
723k8819173221
add a comment |
add a comment |
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